Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
| | x + 5 | - 4 | = 3
<=> x + 5 = 3 + 4
<=> x + 5 = 7
<=> x = 7 - 5
<=> x = 2
Chúc bạn học tốt!!!
\(a)\) \(\frac{x-1}{3}=\frac{x+2}{4}\)
\(\Leftrightarrow\)\(\frac{4\left(x-1\right)}{12}=\frac{3\left(x+2\right)}{12}\)
\(\Leftrightarrow\)\(4\left(x-1\right)=3\left(x+2\right)\)
\(\Leftrightarrow\)\(4x-4=3x+6\)
\(\Leftrightarrow\)\(4x-3x=6+4\)
\(\Leftrightarrow\)\(x=10\)
Vậy \(x=10\)
Câu b) thiếu đề nhé bạn
Chúc bạn học tốt ~
Thanks bạn Phùng Minh Quân nha!
Mk chỉnh lại cau b nè:
b, Tìm x € Z để \(B=\frac{2x+9}{x-1}\)có giá trị nguyên.
mik ko chép lại đề, mik làm luôn:
a) x - \(\frac{31}{36}=\frac{-13}{38}\)
x = \(\frac{-13}{18}+\frac{31}{36}\)
\(x=\frac{5}{36}\)
b)\(2-x-\frac{3}{7}=\frac{9}{-21}\)
\(\frac{11}{7}-x=\frac{3}{7}\)
x = \(\frac{11}{7}-\frac{3}{7}\)
x = 8/7
c) x + 3/11 = 23/44
x = 23/44 - 3/11
x = 1/4
d) \(\frac{1}{12}-x=\frac{-11}{9}\)
x = \(\frac{1}{12}+\frac{11}{9}\)
x = 47/36
e) \(x-\frac{2}{3}=\frac{-17}{3}\)
x= -17/3 + 2/3
x = -5
f) \(x-\frac{1}{2}=\frac{11}{4}.\frac{3}{11}\)
x - 1/2 = 3/4
x = 3/4 + 1/2
x = 5/4
g) \(2x+\frac{3}{8}=\frac{-21}{32}.\frac{4}{7}\)
2x + 3/8 = -3 / 8
2x = -3/8 - 3/8
2x = -9/8
x = -9/8.1/2
x = -9/16
h) x - \(\frac{x}{3}=\frac{3}{57}.\frac{19}{12}\)
x - \(\frac{x}{3}=\frac{1}{12}\)
x = \(\frac{1}{12}+\frac{x}{3}\)
x = \(\frac{1+4x}{12}\)
=> 12x = 1+4x
12x - 4x = 1
8x = 1
x = 1/8
Câu 1: \(\Leftrightarrow(\frac{x-1}{6}-1)+(\frac{x-2}{5}-1)+(\frac{x-3}{4}-1)+(\frac{x-4}{3}-1)+(\frac{x-5}{2}-1=0)\)
\(\Leftrightarrow(x-7)(\frac{1}{6}+\frac{1}{5}+\frac{1}{4}+\frac{1}{3}+\frac{1}{2})=0\)
\(\Leftrightarrow x-7=0\Leftrightarrow x=7\)
\(a)\frac{1}{3}+\frac{-2}{5}+\frac{1}{6}+\frac{-1}{5}\le x< \frac{-3}{4}+\frac{2}{7}+\frac{-1}{4}+\frac{3}{5}+\frac{5}{7}\)
\(\Rightarrow\frac{1}{3}+\frac{1}{6}+\frac{-2}{5}+\frac{-1}{5}\le x< \frac{-3}{4}+\frac{-1}{4}+\frac{2}{7}+\frac{5}{7}+\frac{3}{5}\)
\(\Rightarrow\frac{2}{6}+\frac{1}{6}+\frac{-3}{5}\le x< -1+1+\frac{3}{5}\)
\(\Rightarrow\frac{1}{2}+\frac{-3}{5}\le x< \frac{3}{5}\)
\(\Rightarrow\frac{-1}{10}\le x< \frac{6}{10}\)
\(\Rightarrow-1\le x< 6\)
\(\Rightarrow x\in\left\{-1;0;1;2;3;4;5\right\}\)
Bài b tương tự
\(\frac{x}{3}-\frac{-4}{7}=\frac{2}{9}\).
\(\Rightarrow\frac{x}{3}+\frac{4}{7}=\frac{2}{9}\).
\(\Rightarrow\frac{x}{3}=\frac{2}{9}-\frac{4}{7}\).
\(\Rightarrow\frac{x}{3}=-\frac{22}{63}\).
\(\Rightarrow x=\frac{-22}{63}.3\).
\(\Rightarrow x=\frac{-22}{21}\).
Vậy \(x=\frac{-22}{21}\).