Câu hỏi của Bùi Minh PHƯƠNG

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HT.Phong (9A5) · Accepted Answer

$a\times1\dfrac{1}{3}+a\times2\dfrac{2}{3}+a\times6=110$$a\times\left(1\dfrac{1}{3}+2\dfrac{2}{3}+6\right)=110$$a\times\left(1+\dfrac{1}{3}+2+\dfrac{2}{3}+6\right)=110$$a\times\left(9+\dfrac{1}{3}+\dfrac{2}{3}\right)=110$$a\times10=110$$a=110:10$$a=11$Vậy: a = 11Câu trả lời: $a\times1\dfrac{1}{3}+a\times2\dfrac{2}{3}+a\times6=110$$a\times\left(1\dfrac{1}{3}+2\dfrac{2}{3}+6\right)=110$$a\times\left(1+\dfrac{1}{3}+2+\dfrac{2}{3}+6\right)=110$$a\times\left(9+\dfrac{1}{3}+\dfrac{2}{3}\right)=110$$a\times10=110$$a=110:10$$a=11$Vậy: a = 11

Toru · Answer

$a\times1\dfrac{1}{3}+a\times2\dfrac{2}{3}+a\times6=110$$a\times\left(1\dfrac{1}{3}+2\dfrac{2}{3}+6\right)=110$$a\times\left(1+\dfrac{1}{3}+2+\dfrac{2}{3}+6\right)=110$$a\times\left[\left(1+2+6\right)+\left(\dfrac{1}{3}+\dfrac{2}{3}\right)\right]=110$$a\times\left(9+1\right)=110$$a\times10=110$$a=110:10$$a=11$Câu trả lời: $a\times1\dfrac{1}{3}+a\times2\dfrac{2}{3}+a\times6=110$$a\times\left(1\dfrac{1}{3}+2\dfrac{2}{3}+6\right)=110$$a\times\left(1+\dfrac{1}{3}+2+\dfrac{2}{3}+6\right)=110$$a\times\left[\left(1+2+6\right)+\left(\dfrac{1}{3}+\dfrac{2}{3}\right)\right]=110$$a\times\left(9+1\right)=110$$a\times10=110$$a=110:10$$a=11$

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