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1) 2Al(OH)3 + 3H2SO4 --> Al2(SO4)3 + 6H2O
2) Ba(NO3)2 + Na2SO4 --> BaSO4 + 2NaNO3
3) 2KClO3 --to--> 2KCl + 3O2
4) 2NaHS + 2KOH --> Na2S + K2S + 2H2O
5) 4Fe(OH)2 + O2 + 2H2O --> 4Fe(OH)3
6) 4NO2 + O2 + 2H2O --> 4HNO3
7) SO2 + Br2 + 2H2O --> H2SO4 + 2HBr
8) Fe3O4 + 8HCl --> FeCl2 + 2FeCl3 + 4H2O
9) 4FeS + 7O2 -to--> 2Fe2O3 + 4SO2
10) 3Fe3O4 + 8Al --to--> 9Fe + 4Al2O3
11) 2Fe(OH)3 --to--> Fe2O3 + 3H2O
12) 2KMnO4 + 16HCl --> 2KCl + 2MnCl2 + 5Cl2 + 8H2O
Pư hóa hợp: 5,6
Pư phân hủy: 3,11
1. 3H2SO4+ 2Al(OH)3 → Al2(SO4)3+ 6H2O (phản ứng thế)
2. Ba(NO3)2 + Na2SO4 → BaSO4 + 2NaNO3 (phản ứng thế)
3. 2KClO3 → 2KCl + 3O2 (phản ứng phân hủy)
4. 2NaHS + 2KOH → Na2S + K2S + 2H2O (phản ứng thế)
5. 4Fe(OH)2 + O2 + 2H2O → 4Fe(OH)3 (phản ứng hóa hợp)
(1) ZnO + 2 HCl → ZnCl2 + H2O (thế )
(2) 3 Ca(OH)2 + 2 H3PO4 →Ca3(PO4)2 + 6 H2O (thế )
(3) P2O5 + 3H2O → 2H3PO4 (hóa hợp )
(4) P2O5 + 3 NaOH → Na3PO4 + 3 H2O (thế )
(5) CaCO3 toto→ CaO + CO2 (phân hủy )
(6) 4H2 + Fe3O4 to→ 3Fe + 4H2O (oxi hóa khử)
(7) 2KMnO4 to→ K2MnO4 + MnO2 + O2↑ (phân hủy)
(1) ZnO + 2HCl → ZnCl2 + H2O : pứ thế
(2) 3Ca(OH)2 + 2H3PO4 →Ca3(PO4)2 + 6H2O :pứ trao đổi
(3) P2O5 + 3H2O → 2H3PO4 : pứ hóa hợp
(4) P2O5 + 6NaOH → 2Na3PO4 + 3H2O : pứ trao đổi
(5) CaCO3 → CaO + CO2 : pứ phân hủy
(6) 4H2 + Fe3O4 → 3Fe + 4H2O :pứ oxi hóa-khử, pứ thế
(7) 2KMnO4 → K2MnO4 + MnO2 + O2↑ : pứ phân hủy
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Al2(SO4)3 + ...
Zn + 2HCl → ZnCl2 + H2
2H2 + O2 → 2H2O
2KClO3 ---to→ 2KCl + 3O2
2Al + 3H2SO4 → Al2(SO4)3 + 3H2
CuO + H2 → Cu + H2O
1. \(3H_2SO_4+2Al\left(OH\right)_3\rightarrow Al_2\left(SO_4\right)_3+6H_2O\) - Pư thế
2. \(Ba\left(NO_3\right)_2+Na_2SO_4\rightarrow BaSO_4+2NaNO_3\) - Pư thế
3. \(2KClO_3\underrightarrow{t^o}2KCl+3O_2\) - Pư phân hủy.
4. \(2NaHS+2KOH\rightarrow Na_2S+K_2S+2H_2O\) - Pư thế
5. \(4Fe\left(OH\right)_2+O_2+2H_2O\rightarrow4Fe\left(OH\right)_3\) - Pư hóa hợp.
6. \(4NO_2+O_2+2H_2O\rightarrow4HNO_3\) - Pư hóa hợp.
\(Mg+2HCl\rightarrow MgCl_2+H_2\\ 2Al+3Cl_2\rightarrow\left(t^o\right)2AlCl_3\\ 2H_2O\rightarrow\left(đp\right)2H_2+O_2\\ 2Al+3CuSO_4\rightarrow Al_2\left(SO_4\right)_3+3Cu\)
<p font-family:times="" new="" roman,serif;="" font-size:14.0pt;="" line-height:115%"="">1. CaCO3 --to--> CaO + CO2
2. MgCl2 +2 KOH → Mg(OH)2 +2 KCl
3. Cu(OH)2 +2 HCl → CuCl2 + 2H2O
4. P2O5 + 3H2O ----> 2 H3PO4
5. 4P +5 O2 to→ 2P2O5
6. 2Al + 3 H2SO4 ----> Al2(SO4)3 + 3H2
7. Zn + 2 HCl ----> ZnCl2 + H2
8. N2 + O2 to→ 2NO
9. 2NO + O2 to→ 2NO2
10.4NO2 + O2 + 2H2O → 4HNO3
1. CaCO3 ----> CaO + CO2
2. MgCl2 + 2KOH → Mg(OH)2 + 2KCl
3. Cu(OH)2 + 2HCl → CuCl2 + 2H2O
4. P2O5 + 3H2O ----> 2H3PO4
5. 4P + 5O2 → 2P2O5
6. 2Al + 3H2SO4 ----> Al2(SO4)3 + 3H2
7. Zn + 2HCl ----> ZnCl2 + H2
8. N2 + O2 → 2NO
9. 2NO + O2 → 2NO2
10.4NO2 + O2 + 2H2O → 4HNO3
a) 4NH3 + 5O2 -to-> 4NO + 6H2O
4:5:4:6
b) S + 2HNO3 --> H2SO4 + 2NO
1:2:1:2
c) 3Ba(NO3)2 + Al2(SO4)3 --> 3BaSO4\(\downarrow\) + 2Al(NO3)3
3:1:3:2
d) FeCl3 + 3AgNO3 --> Fe(NO3)3 + 3AgCl\(\downarrow\)
1:3:1:3
\(a.4NH_3+5O_2\rightarrow4NO+6H_2O\)
\(NH_3\div NO=4\div4=1\div1\)
\(b.S+2HNO_3\rightarrow H_2SO_4+2NO\)
\(HNO_3\div NO=2\div2=1\div1\)
\(c.2Ba\left(NO_3\right)_2+Al_2\left(SO_4\right)\rightarrow2BaSO_4+4NO\)
\(Ba\left(NO_3\right)_2\div BaSO_4=2\div2=1\div1\)
\(d.FeCl_3+3AgNO_3\rightarrow Fe\left(NO_3\right)_3+3AgCl\) (ban sai de mik sua lai)
\(AgNO_3\div AgCl=3\div3=1\div1\)
7.SO2+Br2+2H20->H2SO4+2HBr(phản ứng thế)
8.Fe3O4+8HCl->FeCl2+2FeCL3+4H20(phản phân huỷ)
9.4FeS+7O2->2Fe2O3+4SO2 (phản ứng thế)
10.3Fe3O4+8Al->9Fe+4Al2O3 (phản ứng thế)
11.2Fe(OH)3->Fe2O3+3H20(phản ứng phân huỷ)
12.2KMnO4+16HCl->5Cl2+2KCl+2MnCI2+8H20(phản ứng phân huỷ)
13.Zn+2HCI->ZnCL2+H2(phản ứng thế)
(8) 2Al + 3H2SO4 → Al2(SO4)3 + 3H2
phản ứng thế
(9) Cu + 2AgNO3 → Cu(NO3)2 + 2Ag
phản ứng thế
(10) 3Cl2 + 2NH3 → 6HCl + N2
phản ứng thế