Question

[Dương Trương Trâm Anh]

Cảm ơn nha 

Answer 1

[Yeutoanhoc]

`a+3/4+1/4:x=-2`

`<=>1/4:x=-2-3/4`

`<=>1/4:x=-11/4`

`<=>x=-11`

`b)2x-10/3=3/5`

`<=>2x=10/3+3/5`

`<=>2x=59/15`

`<=>x=589/30`

`c)(1/4-x)^2-125%=1 13/16`

`<=>(1/4-x)^2-5/4=29/16`

`<=>(1/4-x)^2=9/16=(+-3/4)^2`

`+)1/4-x=3/4`

`<=>x=-1/2`

`+)1/4-x=-3/4`

`<=>x=1`

Answer 2

[꧁_͏ͥ͏_͏ͣ͏_͏ͫ͏ ¡亗ᵛᶰシ๖ۣۜT๖ۣۜR๖ۣۜÂ๖ۣ...]

a)\(\dfrac{3}{4}+\dfrac{1}{4}:x=-2\) 

          \(\dfrac{1}{4}:x=-2-\dfrac{3}{4}\) 

          \(\dfrac{1}{4}:x=\dfrac{-11}{4}\) 

                 \(x=\dfrac{1}{4}:\dfrac{-11}{4}\) 

                \(x=\dfrac{-1}{11}\) 

b) \(2x-\dfrac{10}{3}=\dfrac{3}{5}\) 

            \(2x=\dfrac{3}{5}+\dfrac{10}{3}\) 

            \(2x=\dfrac{59}{15}\) 

              \(x=\dfrac{59}{15}:2\) 

             \(x=\dfrac{59}{30}\) 

c) \(\left(\dfrac{1}{4}-x\right)^2-125\%=1\dfrac{13}{16}\) 

     \(\left(\dfrac{1}{4}-x\right)^2=\dfrac{29}{16}+\dfrac{5}{4}\) 

      \(\left(\dfrac{1}{4}-x\right)^2=\dfrac{49}{16}\) 

\(\Rightarrow\left(\dfrac{1}{4}-x\right)^2=\left(\dfrac{7}{4}\right)^2\) hoặc \(\left(\dfrac{1}{4}-x\right)^2=\left(\dfrac{-7}{4}\right)^2\) 

        \(\dfrac{1}{4}-x=\dfrac{7}{4}\) hoặc \(\dfrac{1}{4}-x=\dfrac{-7}{4}\) 

               \(x=\dfrac{-3}{2}\) hoặc \(x=2\)