Question

[Huong Nguyen]

C2H4--- >C2H5OH--- >CH3COOH --->CH3COOC2H5

C2H4--- >C2H4Br2

C2H4--- >P.E

Answer 1

[Trương Hồng Hạnh]

C2H4 + H2O => (140^oC,H2SO4đ) C2H5OH

C2H5OH + O2 => (men giấm) CH3COOH + H2O

CH3COOH + C2H5OH => (pứ hai chiều, H2SO4đ) CH3COOC2H5 + H2O

C2H4 + Br2 => C2H4Br2

nCH2=CH2 => (t^o,xt,P) (-CH2-CH2-)_n:PE

Answer 2

[Minh Nhân]

C2H4 + H2O -axit-> C2H5OH

C2H5OH + O2-mg-> CH3COOH + H2O

CH3COOH + C2H5OH<-H2SO4đ,to-> CH3COOC2H5 + H2O

C2H4 + Br2 --> C2H4Br2

nCH2=CH2 -to,p,xt-> (-CH2-CH2-)n