Question

[Maoromata]

c1 : chứng minh \(\left(\frac{1}{cos2x}+1\right)tanx=tan2x\)
c2 : chứng minh \(\frac{cos7a+cos5a+cos3a+cosa}{sin7a+sin5a+sin3a+sina}=cot4a\)

Answer 1

[Nguyễn Việt Lâm]

\(\left(\frac{1}{cos2x}+1\right)tanx=\left(\frac{cos2x+1}{cos2x}\right).\frac{sinx}{cosx}=\frac{2cos^2x}{cos2x}.\frac{sinx}{cosx}\)

\(=\frac{2sinx.cosx}{cos2x}=\frac{sin2x}{cos2x}=tan2x\)

\(\frac{cos7a+cosa+cos5a+cos3a}{sin7a+sina+sin5a+sin3a}=\frac{2cos4a.cos3a+2cos4a.cosa}{2sin4a.cos3a+2sin4a.cosa}\)

\(=\frac{cos4a\left(2cos3a+2cosa\right)}{sin4a\left(2cos3a+2cosa\right)}=\frac{cos4a}{sin4a}=cot4a\)