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Giải:
a) \(\dfrac{56.2,7+56.3,5}{0,62}\)
\(=\dfrac{56.6,2}{0,62}\)
\(=56.10=560\)
b) \(371.65+371.14+629.79\)
\(=371\left(65+14\right)+629.79\)
\(=371.79+629.79\)
\(=79\left(371+629\right)\)
\(=79.1000=79000\)
c) \(0,48.700-2,4.45.2\)
\(=4,8.70-4,8.45\)
\(=4,8\left(70-45\right)\)
\(=4,8.25=120\)
e) \(3,2.950+8.175.4+320.73\)
\(=32.95+32.175+32.730\)
\(=32\left(95+175+730\right)\)
\(=32.1000=32000\)
Vậy ...
Giải:
a) 56.2,7+56.3,50,6256.2,7+56.3,50,62
=56.6,20,62=56.6,20,62
=56.10=560=56.10=560
b) 371.65+371.14+629.79371.65+371.14+629.79
=371(65+14)+629.79=371(65+14)+629.79
=371.79+629.79=371.79+629.79
=79(371+629)=79(371+629)
=79.1000=79000=79.1000=79000
c) 0,48.700−2,4.45.20,48.700−2,4.45.2
=4,8.70−4,8.45=4,8.70−4,8.45
=4,8(70−45)=4,8(70−45)
=4,8.25=120=4,8.25=120
e) 3,2.950+8.175.4+320.733,2.950+8.175.4+320.73
=32.95+32.175+32.730=32.95+32.175+32.730
=32(95+175+730)=32(95+175+730)
=32.1000=32000=32.1000
__________
a: \(\left(3965-2378\right)-\left(437-1378\right)-528\)
\(=3965-2378-437+1378-528\)
\(=\left(3965-437-528\right)-\left(2378-1378\right)\)
\(=3000-1000=2000\)
b: \(\left(-457\right)+\left(-123\right)+23+237\)
\(=\left(-457+237\right)+\left(-123+23\right)\)
\(=-220-100=-320\)
c: \(\left(-329\right)-\left(15-101\right)-\left(25-440\right)\)
\(=-329-15+101-25+440\)
\(=\left(440-15-25\right)+\left(-329+101\right)\)
\(=400-228=172\)
(135,4 - 84,3) :2,5 - 10,46
= 51,1 :2,5 - 10,46
= 20,44 - 10,46 = 9,98
Tương tự nha
a, (38 - 29 + 43) - (43 + 38)
= 38 - 29 + 43 - 43 - 38
= (38 - 38) + (43 - 43) - 29
= -29
b, 271 - [(-43) + 271 - (-17)]
= 271 - (-43 + 271 + 17)
= 271 + 43 - 271 - 17
= (271 - 271) + (43 - 17)
= 26
@Dương Taurus
c, (-11)2.3 - [3 - (-50).(-4)]
= 121.3 - [(3 + 50.(-4)]
= 363 - 3 + 200
= 560
d, 4.52 + 81.32 - (13 - 4)2
= 4.25 + 81.9 - 132 + 42
= 100 + 729 - 169 + 16
= 676
@Dương Taurus
\(A=-7+\frac{3}{4}-\frac{1}{3}-6+\frac{5}{4}-\frac{4}{3}-3-\frac{7}{4}+\frac{5}{3}\)
\(A=\left(-7-6-3\right)+\left(\frac{3}{4}+\frac{5}{4}-\frac{7}{4}\right)+\left(\frac{5}{3}-\frac{1}{3}-\frac{4}{3}\right)\)
\(A=-16+\frac{1}{4}+0\)
\(A=-15\frac{3}{4}\)
\(A=\left(-7+\frac{3}{4}-\frac{1}{3}\right)-\left(6-\frac{5}{4}+\frac{4}{3}\right)-\left(3+\frac{7}{4}-\frac{5}{3}\right)\)
\(=-7+\frac{3}{4}-\frac{1}{3}-6+\frac{5}{4}-\frac{4}{3}-3-\frac{7}{4}+\frac{5}{3}\)
\(=\left(-7-6-3\right)+\left(\frac{3}{4}+\frac{5}{4}-\frac{7}{4}\right)+\left(\frac{-1}{3}-\frac{4}{3}+\frac{5}{3}\right)\)
\(=-16-\frac{1}{4}\)
a,\(\left(5,1-3,5\right)-\left(3,5+5,1\right)\)
\(=5,1-3,5-3,5-5,1\)
\(=\left[5,1-5,1\right]\)\(-\)\(\left[3,5-3,5\right]\)
\(=0-0\)
\(=0\)
b,c bn tự làm nha