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a)`BC (24;20;30); 4=23.3; 20=22.5; 30=2.3.5; ` suy ra `BCNN(24;20;30)=23.3.5=120 suy ra `BC(24;20;30)=`B(120)=\(\left\{0;120;240;360;....\right\}\) b)BC(2;3;7;5); ` 2=2; 3=3; 7=7; 5=5; ` suy ra` `BCNN(2;3;5;7)=2.3.5.7=210 suy ra `BC`(2;3;5;7)=B(210)=\(\left\{0;210;420;630;...\right\}\)
c)BC(34;45;54); 34=2.17; 45=32.5; 54=2.33; suy raBCNN(34;45;54)=2.33.5.17=4590 suy ra BC(34;45;54)=B(4590)=\(\left\{0;4590;9180;13770;...\right\}\)
BCNN(30,225,54)=1350
BCNN(5,15)=15
BCNN(9,12,18)=36
UCLN(9,25)=1
UCLN(6,9,15)=3
BCNN(6,10,15)=30
Ta có
AB+BC=10: BC-AB=4\(\Rightarrow\)2BC=14\(\Rightarrow\)BC=7
\(\Rightarrow\)AB=3\(\Rightarrow\)AC=5
Ta có : \(AB+AC+BC=15\)
\(AB+BC=10\)
\(\Rightarrow\) \(AC=15-10=5\)
Mà \(BC-AB=4\)
\(\Rightarrow\) \(BC=\frac{10+4}{2}=\frac{14}{2}=7\)
\(\Rightarrow\) \(AB=BC-4=7-4=3\)
Vậy \(AC=5;AB=3;BC=7\)
a) BC (13,15) = {195; 390...}
b) BC (30,100) = {300; 600;900...}
c) BC (7, 9, 11) = {693; 1386; ...}
d) BC (24,28,40) = {13440; 26880; 6720;..}
#Học tốt!!!
\(220,33-\overline{ab,cd}=\overline{abc,d}\)
\(\left(220,33-\overline{ab,cd}\right)\times100=abc\times100\)
\(22033-\overline{abcd}=\overline{abcd}\times10\)
\(22033=\overline{abcd}\times10+\overline{abcd}\)
\(22033=\overline{abcd}\times11\)
\(\overline{abcd=}22033\div11=2003\)
a)Ta có:7=7.1 ; 9=3.3 ; 11=11.1
=>BC(7;9;11)=1
b)Ta có:24=(2^3).3 ; 28=(2^2).7: ;40=(2^3).5
=>BC(24;28;40)=2^2=4
Nhớ giữ lời hứa nhé
Mình nhầm.
a)7=7.1 ; 9=(3^2) ; 11=11.1
BC(7;9;11)=7.(3^2).11=693
b)Ta có:24=(2^3).3 ; 28=(2^2).7 ; 40=(2^3).5
BC(24;28;40)=2^3.3.5.7=840
Xin lỗi nhé
Ta có :
10 = 2 . 5
16 = 42
7 = 7
=> BC ( 10; 16; 7 ) = 2 . 5 . 42 . 7
=> BC ( 10; 16; 7 ) = 560
BCLN (10,16,7) = 560