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Bài 1:
a: \(=6x^3-10x^2+6x\)
b: \(=-2x^3-10x^2-6x\)
Bài 4:
a: =>3x+10-2x=0
=>x=-10
c: =>3x2-3x2+6x=36
=>6x=36
hay x=6
Bài 1:
\(a,=6x^3-10x^2+6x\\ b,=-2x^3-10x^2-6x\)
Bài 4:
\(a,\Leftrightarrow3x+10-2x=0\Leftrightarrow x=-10\\ b,\Leftrightarrow x\left(2x^2+9x-5\right)-\left(2x^3+9x^2+x+4,5\right)=3,5\\ \Leftrightarrow2x^3+9x^2-5x-2x^3-9x^2-x-4,5=3,5\\ \Leftrightarrow-6x=8\Leftrightarrow x=-\dfrac{4}{3}\\ c,\Leftrightarrow3x^2-3x^2+6x=36\Leftrightarrow x=6\)
Bài 1:
\(a,=7xy\left(2x-3y+4xy\right)\\ b,=x\left(x+y\right)-5\left(x+y\right)=\left(x-5\right)\left(x+y\right)\\ c,=\left(x-y\right)\left(10x+8\right)=2\left(5x+4\right)\left(x-y\right)\\ d,=\left(3x+1-x-1\right)\left(3x+1+x+1\right)\\ =2x\left(4x+2\right)=4x\left(2x+1\right)\\ e,=5\left[\left(x-y\right)^2-4z^2\right]=5\left(x-y-2z\right)\left(x-y+2z\right)\\ f,=x^2+8x-x-8=\left(x+8\right)\left(x-1\right)\\ g,\left(x+y\right)^3-\left(x+y\right)=\left(x+y\right)\left[\left(x+y\right)^2-1\right]\\ =\left(x+y\right)\left(x+y-1\right)\left(x+y+1\right)\\ h,=x^2+3x+x+3=\left(x+3\right)\left(x+1\right)\)
a: \(=2x^2-8x+3x-12=2x^2-5x-12\)
b: \(=3x^2-6x+x-2=3x^2-5x-2\)
\(a,=2x^3-14x^2-6x\\ b,=-8x^4y^2+4xy^4-28x^2y^3\\ c,=-10x^5-15x^4+25x^3\\ d,=x^3-4x^2-2x^2+8x+3x-12=x^3-6x^2+11x-12\\ e,=10x^4+4x^3-15x^2-6x-5x-2=10x^4+4x^3-15x^2-11x-2\\ g,=6x-3-5x+15=x+12\)
[(x2-2xy+2xy2).(x+2y)-(x2+4y2).(x-y)]2xy
=( x3 + 2x2y-2x2y-4xy2+2x2y2+4xy3-x3+x2y-4xy2+4y3 )2xy
=2xy(2x2y2-8xy2+4xy3+x2y+4y3)
= 4x3y3-16x2y3+8x2y4+2x3y2+8xy4
Trả lời:
[ ( x2 - 2xy + 2xy2 ) ( x + 2y ) - ( x2 + 4y2 ) ( x - y ) ] 2xy
= [ ( x3 + 2x2y - 2x2y - 4xy2 + 2x2y2 + 4xy3 ) - ( x3 - x2y + 4xy2 - 4y3 ) ] 2xy
= ( x3 + 2x2y - 2x2y - 4xy2 + 2x2y2 + 4xy3 - x3 + x2y - 4xy2 + 4y3 ) 2xy
= ( x2y - 8xy2 + 2x2y2 + 4xy3 + 4y3 ) 2xy
= 2x3y2 - 16x2y3 + 4x3y3 + 8x2y4 + 8xy4
b) N= (x-y)3-x2+2xy-y2=(x-y)3-(x2-2xy+y2)=(x-y)3-(x-y)2
thay x-y=5 vào N ta được: N= -53-52=-150
a) đề sai k vậy bạn?
a: \(M=x^3+x^2-y^3+y^2+xy-3xy-95\)
\(=\left(x-y\right)^3+\left(x-y\right)^2-95\)
\(=7^3+7^2-95=297\)
b: \(N=3\left[\left(x+y\right)^2-2xy\right]-2\left(x+y\right)+6xy-100\)
\(=3\cdot\left(25-2xy\right)-10+6xy-100\)
=75-6xy-10+6xy-100
=-35
\(1997.2003=\left(2000-3\right)\left(2000+3\right)=2000^2-3^2=4000000-9=3999991\)
\(1997\cdot2003=\left(2000-3\right)\left(2000+3\right)=3999991\)