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1 tháng 8 2020

a) \(2x^2y^2-\frac{4}{3}x^2y+2xy\)

\(=xy\left(2xy-\frac{4}{3}x+2\right)\)

b) 2xy2.(x + 5y) - 4xy(5y + x)

= (5y + x)(2xy2 - 4xy)

= 2xy(5y + x)(y - 2)

c) 25 - 4x2 - y2 + 4xy

= 25 - (4x2 - 4xy + y2)

= 52 - (2x + y)2

= (5 - 2x - y)(5 + 2x + y)

d) x2 + 4x - 2xy - 4y +y2

= (x2 - 2xy + y2) + (4x - 4y)

= (x - y)2 + 4(x - y)

= (x - y)(x - y + 4)

e) 12y3 - 3x2y + 12xy - 12y

= 3y(4y2 - x2 + 4x - 4)

= 3y[4y2 - (x - 2)2]

= 3y(2y - x + 2)(2y + x - 2)

f) 64x4 + y4

= (8x2)2 + 16x2y2 + y4 - 16x2y2

= (8x2 + y2)2 - (4xy)2

= (8x2 + y2 - 4xy)(8x2 + y2 + 4xy)

1 tháng 8 2020

a) \(2x^2y^2-\frac{4}{3}x^2y+2xy\)

b) \(2xy^2\left(x+5y\right)-4xy\left(5y+x\right)\)

\(=\left(x+5y\right)\left(2xy^2-4xy\right)\)

\(=2\left(x+5y\right)\left(xy^2-2xy\right)\)

c) \(25-4x^2-y^2+4xy\)

\(=25-\left(4x^2+y^2-4xy\right)\)

\(=5^2-\left[\left(2x\right)^2-2.2x.y+y^2\right]\)

\(=5^2-\left(2x-y\right)^2\)

\(=\left(5-2x+y\right)\left(5+2x-y\right)\)

d) \(x^2+4x-2xy-4y+y^2\)

\(=\left(x^2-2xy+y^2\right)+\left(4x-4y\right)\)

\(=\left(x-y\right)^2+4\left(x-y\right)\)

\(=\left(x-y\right)\left(x-y\right)+4\left(x-y\right)\)

\(=\left(x-y\right)\left(x-y+4\right)\)

e) \(12y^3-3x^2y+12xy-12y\)

f) \(64x^4+y^4\)

\(=\left(8x^2\right)^2+16x^2y^2+\left(y^2\right)^2-16x^2y^2\)

\(=\left(8x^2+y^2\right)^2-\left(4xy\right)^2\)

\(=\left(8x^2+y^2+4xy\right)\left(8x^2+y^2-4xy\right)\)

12 tháng 7 2019

a,\(xy+3x-7y-21\)

\(=x\left(y+3\right)-7\left(y+3\right)\)

\(=\left(y+3\right)\left(x-7\right)\)

12 tháng 7 2019

\(b,2xy-15-6x+5y\)

\(=\left(2xy-6x\right)+\left(-15+5y\right)\)

\(=2x\left(y-3\right)-5\left(3-y\right)\)

\(=2x\left(y-3\right)+5\left(y-3\right)\)

\(=\left(y-3\right)\left(2x+5\right)\)

23 tháng 11 2017

a) \(x^2-y^2-5x-5y\)

\(=\left(x^2-y^2\right)-\left(5x+5y\right)\)

\(=\left(x-y\right)\left(x+y\right)-5\left(x+y\right)\)

\(=\left(x+y\right)\left(x-y-5\right)\)

b) \(5x^3-5x^2y-10x^2+10xy\)

\(=\left(5x^3-5x^2y\right)-\left(10x^2-10xy\right)\)

\(=5x^2\left(x-y\right)-10x\left(x-y\right)\)

\(=\left(x-y\right)\left(5x^2-10x\right)\)

\(=5x\left(x-y\right)\left(x-2\right)\)

c) \(x^3-2x^2-x+2\)

\(=\left(x^3-2x^2\right)-\left(x-2\right)\)

\(=x^2\left(x-2\right)-\left(x-2\right)\)

\(=\left(x-2\right)\left(x^2-1\right)\)

\(=\left(x-2\right)\left(x-1\right)\left(x+1\right)\)

d) \(-y^2+2xy-x^2+3x-3y\)

\(=-\left(y^2-2xy+x^2\right)+\left(3x-3y\right)\)

\(=-\left(y-x\right)^2+3\left(x-y\right)\)

\(=-\left(x-y\right)^2+3\left(x-y\right)\)

\(=\left(x-y\right)\left[-\left(x-y\right)+3\right]\)

\(=\left(x-y\right)\left(-x+y+3\right)\)

g) \(4x^2-8x+3\)

\(=4x^2-6x-2x+3\)

\(=\left(4x^2-6x\right)-\left(2x-3\right)\)

\(=2x\left(2x-3\right)-\left(2x-3\right)\)

\(=\left(2x-3\right)\left(2x-1\right)\)

h) \(2x^2-5x-7\)

\(=2x^2+2x-7x-7\)

\(=\left(2x^2+2x\right)-\left(7x+7\right)\)

\(=2x\left(x+1\right)-7\left(x+1\right)\)

\(=\left(x+1\right)\left(2x-7\right)\)

k) \(x^4+4\)

\(=x^4+4x^2+4-4x^2\)

\(=\left[\left(x^2\right)^2+2.x^2.2+2^2\right]-4x^2\)

\(=\left(x^2+2\right)^2-\left(2x\right)^2\)

\(=\left(x^2+2-2x\right)\left(x^2+2+2x\right)\)

3 tháng 10 2017

đề bài đâu

ucche

3 tháng 10 2017

cô hk ghi nha bn

sorry nha

14 tháng 12 2018

a.

=5z(x^2-2x-y^2)

c. =4x^2+6x-2x-3

=(4x^2-2x)+(6x-3)

2x(2x-1)+3(2x-1)

=(2x-1)(2x+3)

a: \(5x^2z-10xyz-5y^2z\)

\(=5z\left(x^2-2xy-y^2\right)\)

b: \(4x^2+4x-3\)

\(=4x^2+6x-2x-3\)

\(=2x\left(2x+3\right)-\left(2x+3\right)\)

\(=\left(2x+3\right)\left(2x-1\right)\)

c: Sửa đề: \(x^2-xy-12y^2\)

\(=x^2-4xy+3xy-12y^2\)

\(=x\left(x-4y\right)+3y\left(x-4y\right)\)

\(=\left(x-4y\right)\left(x+3y\right)\)

d: \(3x+3y-x^2-2xy-y^2\)

\(=3\left(x+y\right)-\left(x+y\right)^2\)

\(=\left(x+y\right)\left(3-x-y\right)\)

30 tháng 7 2018

từ từ ít ít từng câu thôi bạn ơi

16 tháng 11 2018

b.10x(x-y)-6y(y-x)=10x(x-y)+6y(x-y)=(10x+6y)(x-y)

16 tháng 11 2018

c.3x2+5y-3xy-5x=(3x2--3xy)-(5x-5y)=3x(x-y)-5(x-y)=(3x-5)(x-y)