Question

[Kim Ngân Trương]

 giúp

Answer 1

[Nguyễn Lê Phước Thịnh]

a: \(P=27-27x+9x^2-x^3\)

\(=3^3-3\cdot3^2\cdot x+3\cdot3\cdot x^2-x^3=\left(3-x\right)^3\)

Khi x=-17 thì \(P=\left[3-\left(-17\right)\right]^3=\left(3+17\right)^3=20^3=8000\)

b: \(Q=x^3+3x^2+3x\)

\(=x^3+3x^2+3x+1-1\)

\(=\left(x+1\right)^3-1\)

Khi x=99 thì \(Q=\left(99+1\right)^3-1=100^3-1=1000000-1=999999\)

Answer 2

[Kim Ngân Trương]

giúp,có tick ạ