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a) Vì \(\frac{-24}{42}=-\frac{24:6}{42:6}=-\frac{4}{7};\frac{32}{-56}=-\frac{32:8}{56:8}=-\frac{4}{7}\)
Mà \(-\frac{4}{7}=-\frac{4}{7}\)
\(\Rightarrow\frac{-24}{42}=\frac{32}{-56}\)
b) Vì \(\frac{36}{84}=\frac{36:12}{84:12}=\frac{3}{7};\frac{42}{98}=\frac{42:14}{98:14}=\frac{3}{7}\)
Mà \(\frac{3}{7}=\frac{3}{7}\)
\(\Rightarrow\frac{36}{84}=\frac{42}{98}\)
c) Vì \(\frac{1717}{2323}=\frac{1717:101}{2323:101}=\frac{17}{23};\frac{171717}{232323}=\frac{171717:10101}{232323:10101}=\frac{17}{23}\)
Mà \(\frac{17}{23}=\frac{17}{23}\)
\(\Rightarrow\frac{1717}{2323}=\frac{171717}{232323}\)
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1, ta có :
45=32.5
30=2.3.5
75=52.3
=> ƯCLN(45;30;75)=3.5=15
2, ta có :
64=26
84=22.3.7
144=24.32
ƯCLN(64;84;144)=22.3=12
a)=-50
b)=-33
c)=13
d)=46
e)=-33
f)=-54
g)=29
h)=-11
i)=-120
k)=-196
l)=-108
m)=100
a)=-50
b)=-33
c)=13
d)=46
e)=-33
f)=-54
g)=29
h)=-11
i)=-120
k)=-196
l)=-108
m)=100
a) 54=2.33; 48=23.6 b)45=5.32 ; 60=22.3.5 c)48=24.3 ; 72=22.32 ;90=2.32.5
TSNT chung:2 TSNT chung:3;5 TSNT chung:2;3
ƯCLN(54;48)=2=2 ƯCLN(45;60)=3.5=15 ƯCLN(48;72;90)=2.3=6
ƯC(54;48)=Ư(2)={1;2} ƯC(45;60)=Ư(15)={1;3;5;15} ƯC(48;72;60)=Ư(6)={1;2;3;6}
a,M=3/8+3/7+3/15=>M=843/840>840/840=>M=843/840>1(dpcm)
b,P=41/90+31/72+21/40+11/45+(-1)/36=293/180>180/180(dpcm)
\(\dfrac{42}{98}=\dfrac{36}{84}=\dfrac{72}{168}\)
\(\dfrac{72}{45}=\dfrac{144}{90}=\dfrac{104}{65}\)