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a) y × 2/5 + y × 3/5 = 5/7
y x ( 2/5 + 3/5) = 5/7
y x 5/5 = 5/7
y x 1 = 5/7
y = 5/7 : 1
y = 5/7
b) y × 7/2 - y × 3/2 = 3/4
y x ( 7/2 - 3/2) = 3/4
y x 4/2 = 3/4
y x 2 = 3/4
y = 3/4 : 2
y = 3/4 x 1/2
y = 3/8
`a,yxx(2/5+3/5)=5/7`
`y xx1=5/7`
`y=5/7:1`
`y=5/7`
`b,y xx(7/2-3/2)=3/4`
`y xx2=3/4`
`y =3/4:2`
`y=3/2`
\(1)\frac{12}{7}\times \frac{7}{4}+\frac{35}{11}:\frac{245}{121}\)
\(=3+\frac{35}{11}\times \frac{121}{245}\)
\(=3+\frac{11}{7}\)
\(= 3\frac{1}{7}(=\frac{22}{7})\)
a) y + 3/7 x 21/9 = 5
y + 3/7 x 7/3 = 5
y + 1 = 5
y = 4
b) y x 3/5 - 1/2 = 4/5
y x 3/5 = 4/5 + 1/2
y x 3/5 = 13/10
y = 13/6
c) 9/8 - y + 2/5 = 1/4
y - 2/5 = 9 /8 - 1/4
y - 2/5 = 7/8
y = 51/40
d) y - 6/5 : 2/3 = 5/6
y - 9/5 = 5/6
y = 79/30
e) y : 7/8 + 3/4 = 7/4
y : 7/8 = 1
y = 7/8
Bài 5:
Chiều rộng là: 35/4:2-11/3=17/24(m)
Chiều rộng kém chiều dài:
11/3-17/24=71/24(m)
Bài 1:
a,Ta có:\(\frac{3}{5}=\frac{3\times2}{5\times2}=\frac{6}{10}\) (1)
\(\frac{4}{5}=\frac{4\times2}{5\times2}=\frac{8}{10}\) (2)
Từ (1) và (2)=> Một phân số tối giản nằm giữa hai phân số trên là:\(\frac{7}{10}\)
b,Ta có:\(\frac{3}{5}=\frac{3\times3}{5\times3}=\frac{9}{15}\)
\(\frac{4}{5}=\frac{4\times3}{5\times3}=\frac{12}{15}\)
=> hai phân số ở giữa là:\(\frac{10}{15}=\frac{2}{3};\frac{11}{12}\)
a: =>x=3/7+3/5=15/35+21/35=36/35
b: =>x/35=4/5-5/7=28/35-25/35=3/35
=>x=3
c: =>x<3/4+8/4=11/4
=>\(x\in\left\{0;1;2;3\right\}\)
d: =>5/3<x<5/6+24/6=29/6
=>\(x\in\left\{2;3;4\right\}\)
e: =>x<10/12-9/12=1/12
=>x=0
f: =>2/3<x<12/6-5/6=7/6
=>x=1
a) 5/7 + y/35 = 4/5
y/35 = 4/5 - 5/7
y/35= 3/35
Vậy y=3 "
chúc bạn học tốt <3
Bài 2 :
a, \(\dfrac{y}{35}=\dfrac{4}{5}-\dfrac{5}{7}=\dfrac{28-25}{35}=\dfrac{3}{35}\Rightarrow y=3\)
b, \(y+\dfrac{4}{5}=\dfrac{4}{5}+\dfrac{15+21}{35}=\dfrac{4}{5}+\dfrac{36}{35}\Leftrightarrow y+\dfrac{4}{5}=\dfrac{28+36}{35}=\dfrac{64}{35}\)
\(\Leftrightarrow y=\dfrac{64}{35}-\dfrac{4}{5}=\dfrac{64-28}{35}=\dfrac{36}{35}\)
a)3/4 × (5/6 + 7/8)
=3/4 × 41/24
=41/32
b)3/5 × y=4/7
y=4/7:3/5
y=20/21
a) \(\frac{5}{7}+\frac{y}{35}=\frac{4}{5}\Leftrightarrow\frac{y}{35}=\frac{4}{5}-\frac{5}{7}\)
\(\Rightarrow\frac{y}{35}=\frac{28}{35}-\frac{25}{35}\Leftrightarrow\frac{y}{35}=\frac{3}{35}\)
\(\Rightarrow y=3\)
b) \(y+\frac{4}{5}=\frac{4}{5}+\left(\frac{3}{7}+\frac{3}{5}\right)\Leftrightarrow y=\left(\frac{4}{5}-\frac{4}{5}\right)+\left(\frac{3}{7}+\frac{3}{5}\right)\)
\(\Rightarrow y=\frac{3}{7}+\frac{3}{5}\Leftrightarrow y=\frac{15}{35}+\frac{21}{35}\)
\(\Rightarrow y=\frac{36}{35}\)
a). \(\frac{y}{35}\)= \(\frac{4}{5}\)- \(\frac{5}{7}\)
\(\frac{y}{35}\)= \(\frac{3}{35}\)
b). y + \(\frac{4}{5}\)= \(\frac{4}{5}\)+ \(\frac{25}{35}\)
y+ \(\frac{4}{5}\)= \(\frac{53}{35}\)
y = \(\frac{53}{35}\)- \(\frac{4}{5}\)
y = \(\frac{5}{7}\)