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Bài 1:
\(101\cdot125+101\cdot25-101\cdot50\)
\(=101\cdot\left(125+25-50\right)\)
\(=101\cdot100\)
\(=10100\)
Bài 2:
\(76\cdot115+56\cdot24+59\cdot24\)
\(=76\cdot115+24\cdot\left(56+59\right)\)
\(=76\cdot115+24\cdot115\)
\(=115\cdot\left(76+24\right)\)
\(=115\cdot100\)
\(=11500\)
a) x=-72/-8=9
b) x=-54/6=-9
c) x=-40/-4=10
d) x=-66/6=-11
tick nha
a)(-8)*x=-72
x=(-72)/(-8)
x=9
b)6*x=-54
x=-54/6
x=-9
c)(-4)*x=(-40)
x=(-40)/(-4)
x=10
d)6x=-66
x=-66/6
x=-11
1: \(\Leftrightarrow x=UCLN\left(24;36;150\right)=6\)
2: \(\Leftrightarrow x\in\left\{24;48;72;...\right\}\)
mà 16<=x<=50
nên \(x\in\left\{24;48\right\}\)
3: \(\Leftrightarrow x\inƯ\left(6\right)\)
mà x>-10
nên \(x\in\left\{1;-1;2;-2;3;-3;6;-6\right\}\)
4: \(\Leftrightarrow x\in BC\left(4;5;8\right)\)
\(\Leftrightarrow x\in\left\{...;-40;0;40;80;120;160;200;...\right\}\)
mà -20<x<180
nên \(x\in\left\{0;40;80;120;160\right\}\)
`@` `\text {Ans}`
`\downarrow`
`a)`
`(2x - 1)^2 + 1 = 26`
`\Rightarrow (2x - 1)^2 = 26 - 1`
`\Rightarrow (2x - 1)^2 = 25`
`\Rightarrow (2x - 1)^2 = (+-5)^2`
`\Rightarrow`\(\left[{}\begin{matrix}2x-1=5\\2x-1=-5\end{matrix}\right.\)
`\Rightarrow`\(\left[{}\begin{matrix}2x=6\\2x=-4\end{matrix}\right.\)
`\Rightarrow`\(\left[{}\begin{matrix}x=6\div2\\x=-4\div2\end{matrix}\right.\)
`\Rightarrow`\(\left[{}\begin{matrix}x=3\\x=-2\end{matrix}\right.\)
Vậy, `x \in`\(\left\{-2;3\right\}\)
`b)`
`(2x - 4)^3 + 2 = 66`
`\Rightarrow (2x - 4)^3 = 66 - 2`
`\Rightarrow (2x - 4)^3 = 64`
`\Rightarrow (2x - 4)^3 = 4^3`
`\Rightarrow 2x - 4 = 4`
`\Rightarrow 2x = 8`
`\Rightarrow x = 8 \div 2`
`\Rightarrow x = 3`
Vậy, `x = 3`
`c)`
\(7^{x+2}+5\cdot7^{x+1}+15=603\)
`\Rightarrow 7^x . 7^2 + 5 . 7^x . 7 = 603 - 15`
`\Rightarrow 7^x . 7^2 + 35 . 7^x = 588`
`\Rightarrow 7^x . (7^2 + 35) = 588`
`\Rightarrow 7^x . 84 = 588`
`\Rightarrow 7^x = 588 \div 84`
`\Rightarrow 7^x = 7`
`\Rightarrow 7^x = 7^1`
`\Rightarrow x = 1`
Vậy, `x = 1.`
\(#48Cd\)
\(a)\left(2x-1\right)^2+1=26\)
\(\left(2x-1\right)^2=25\)
\(TH1:2x-1=5\)
\(2x=6\)
\(x=3\)
\(TH2:2x-1=-5\)
\(2x=-4\)
\(x=-2\)
Vậy........
\(b)\left(2x-4\right)^3+2=66\)
\(\left(2x-4\right)^3=64=4^3\)
\(2x-4=4\)
\(2x=8\)
\(x=4\)
\(c)7^x+2+5.7^x+1+15=603\)
\(7^x\left(1+5\right)=603-15-1-2\)
\(7^x.6=585\)
Bạn xem lại phần này nhé . x tìm ra không được chẵn lắm á cậu.
a) x= -72 : (-8)
x = 9
b) x = -54 : 6 = -9
c) x = -40 : 9-4) = 10
d) x = -66 : 6 = -11
(-8).x= -72
x=(-72):(-8)
x=9
6x=-54
x=(-54):6
x=-9
(-4).x=-40
x=40:(-4)
x= -10
6x=-66
x=(-66):6
x= -11
tick mk nha p!