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22 tháng 9 2019

a) \(43x^3y^3-32x^2y^2\)

\(=x^2y^2\left(43xy-32\right)\)

b) \(ax-bx+ab-x^2\)

\(=\left(ax+ab\right)-\left(bx+x^2\right)\)

\(=a\left(b+x\right)-x\left(b+x\right)\)

\(=\left(a-x\right)\left(b+x\right)\)

c) \(12a^2b-18ab^2-30b^2\)

\(=6b\left(2a^2-3ab-5b\right)\)

d) \(27a^2\left(b-1\right)-9a^3\left(1-b\right)\)

\(=27a^2\left(b-1\right)+9a^3\left(b-1\right)\)

\(=\left(27a^2+9a^3\right)\left(b-1\right)\)

\(=9a^2\left(b-1\right)\left(a+3\right)\)

11 tháng 10 2019

Nhanh lên

11 tháng 10 2019

a) 16x2(x - y)2 - 10y(y - x)3

= 16x2(y - x)2 - 10y(y - x)3

= 2(y - x)2[8x2 - 5y(y - x)]

= 2(y - x)2(8x2 + 5xy - 5y2)

b) a2 -b2 + 4ab - 9 (sai đề)

19 tháng 10 2020

a) x2 - 4x + 2 = (x2 - 4x + 4) - 2 = (x - 2)2 - 2 = \(\left(x-2+\sqrt{2}\right)\left(x-2-\sqrt{2}\right)\)

b)  x2 - 12x + 11 = x2 - x - 11x + 11 = x(x - 1) - 11(x - 1) = (x - 1)(x - 11)

c) 3x2 + 6x - 9 = 3x2 - 3x + 9x - 9 = 3x(x - 1) + 9(x - 1) = (3x + 9)(x - 1) = 3(x + 3)(x - 1)

d) 2x2 - 6x + 2 = 2(x2 - 3x + 1) = 2(x2 - 3x + 9/4 - 5/4) = 2[(x - 3/2)2 - 5/4] = \(2\left(x-\frac{3}{2}+\sqrt{\frac{5}{4}}\right)\left(x-\frac{3}{2}-\sqrt{\frac{5}{4}}\right)\) 

19 tháng 10 2020

1. 

a) \(x^2-4x+2=\left(x^2-4x+4\right)-2=\left(x-2\right)^2-2=\left(x-2-\sqrt{2}\right)\left(x-2+\sqrt{2}\right)\)

b) \(x^2-12x+11=\left(x^2-12x+36\right)-25=\left(x-6\right)^2-5^2=\left(x-6-5\right)\left(x-6+5\right)=\left(x-11\right)\left(x-1\right)\)

c) \(3x^2+6x-9=3\left(x^2+2x-3\right)=3\left[\left(x^2+2x+1\right)-4\right]=3\left[\left(x+1\right)^2-2^2\right]=3\left(x-1\right)\left(x+3\right)\)

d) \(2x^2-6x+2=2\left(x^2-3x+1\right)=2\left(x^2-2.x.\frac{3}{2}+\frac{9}{4}-\frac{5}{4}\right)=2\left[\left(x-\frac{3}{2}\right)^2-\frac{5}{4}\right]\)

\(=2\left(x-\frac{3}{2}-\frac{\sqrt{5}}{2}\right)\left(x-\frac{3}{2}+\frac{\sqrt{5}}{2}\right)\)

7 tháng 10 2020

a) ( 3x - 1 )2 - 16 = ( 3x - 1 )2 - 42 = ( 3x - 1 - 4 )( 3x - 1 + 4 ) = ( 3x - 5 )( 3x + 3 ) = 3( 3x - 5 )( x + 1 )

b) ( 5x - 4 )2 - 49x2 = ( 5x - 4 )2 - ( 7x )2 = ( 5x - 4 - 7x )( 5x - 4 + 7x ) = ( -2x - 4 )( 12x - 4 ) = -2( x + 2 ).4( 3x - 1 ) = -8( x + 2 )( 3x - 1 )

c) ( 2x + 5 )2 - ( x - 9 )2 = [ ( 2x + 5 ) - ( x - 9 ) ][ ( 2x + 5 ) + ( x - 9 ) ] = ( 2x + 5 - x + 9 )( 2x + 5 + x - 9 ) = ( x + 14 )( 3x - 4 )

d) ( 3x + 1 )2 - 4( x - 2 )2 = ( 3x + 1 )2 - 22( x - 2 )2 = ( 3x + 1 )2 - [ 2( x - 2 ) ]2 = ( 3x + 1 )2 - ( 2x - 4 )2 = [ ( 3x + 1 ) - ( 2x - 4 ) ][ ( 3x + 1 ) + ( 2x - 4 ) ] = ( 3x + 1 - 2x + 4 )( 3x + 1 + 2x - 4 ) = ( x + 5 )( 5x - 3 )

e) 9( 2x + 3 )2 - 4( x + 1 )2 = 32( 2x + 3 )2 - 22( x + 1 )2 = [ 3( 2x + 3 ) ]2 - [ 2( x + 1 ) ]2 = ( 6x + 9 )2 - ( 2x + 2 )2 = [ ( 6x + 9 ) - ( 2x + 2 ) ][ ( 6x + 9 ) + ( 2x + 2 ) ] = ( 6x + 9 - 2x - 2 )( 6x + 9 + 2x + 2 ) = ( 4x + 7 )( 8x + 11 )

f) 4b2c2 - ( b2 + c2 - a2 )2 = ( 2bc )2 - ( b2 + c2 - a2 )2 = [ 2bc - ( b2 + c2 - a2 ) ][ 2bc + ( b2 + c2 - a2 ] = ( 2bc - b2 - c2 + a2 )( 2bc + b2+ c2 - a2 ) = [ a2 - ( b2 - 2bc + c2 ) ][ ( b2 + 2bc + c2 ) - a2 ] = [ a2 - ( b - c )2 ][ ( b + c )2 - a2 ] = ( a - b + c )( a + b - c )( b + c - a )( b + c + a )

7 tháng 10 2020

g) ( ax + by )2 - ( ay + bx )2 

= [ ( ax + by ) - ( ay + bx ) ][ ( ax + by ) + ( ay + bx ) ]

= ( ax + by - ay - bx )( ax + by + ay + bx )

= [ a( x - y ) - b( x - y ) ][ a( x + y ) + b( x + y ) ]

= ( a - b )( x - y )( x + y )( a + b )

h) ( a2 + b2 - 5 )2 - 4( ab + 2 )2 

= ( a2 + b2 - 5 )2 - 22( ab + 2 )2 

= ( a2 + b2 - 5 )2 - [ 2( ab + 2 ) ]2 

= ( a2 + b2 - 5 )2 - ( 2ab + 4 )2 

= [ ( a2 + b2 - 5 ) - ( 2ab + 4 ) ][ ( a2 + b2 - 5 ) + ( 2ab + 4 ) ]

= ( a2 + b2 - 5 - 2ab - 4 )( a2 + b2 - 5 + 2ab + 4 )

= [ ( a2 - 2ab + b2 ) - 9 ][ ( a2 + 2ab + b2 ) - 1 ]

= [ ( a - b )2 - 32 ][ ( a + b )2 - 12 ]

= ( a - b - 3 )( a - b + 3 )( a + b - 1 )( a + b + 1 )

i) ( 4x2 - 3x - 18 )2 - ( 4x2 + 3x )2

= [ ( 4x2 - 3x - 18 ) - ( 4x2 + 3x ) ][ ( 4x2 - 3x - 18 ) + ( 4x2 + 3x ) ]

= ( 4x2 - 3x - 18 - 4x2 - 3x )( 4x2 - 3x - 18 + 4x2 + 3x )

= ( -6x - 18 )( 8x2 - 18 )

= -6( x + 3 ).2( 4x2 - 9 )

= -12( x + 3 )( 2x - 3 )( 2x + 3 )

k) 9( x + y - 1 )2 - 4( 2x + 3y + 1 )2

= 32( x + y - 1 )2 - 22( 2x + 3y + 1 )2

= [ 3( x + y - 1 ) ]2 - [ 2( 2x + 3y + 1 ) ]2

= ( 3x + 3y - 3 )2 - ( 4x + 6y + 2 )2

= [ ( 3x + 3y - 3 ) - ( 4x + 6y + 2 ) ][ ( 3x + 3y - 3 ) + ( 4x + 6y + 2 ) ]

= ( 3x + 3y - 3 - 4x - 6y - 2 )( 3x + 3y - 3 + 4x + 6y + 2 )

= ( -x - 3y - 5 )( 7x + 9y - 1 )

l) -4x2 + 12xy - 9y2 + 25

= 25 - ( 4x2 - 12xy + 9y2 )

= 52 - ( 2x - 3y )2

= ( 5 - 2x + 3y )( 5 + 2x - 3y )

m) x2 - 2xy + y2 - 4m2 + 4mn - n2

= ( x2 - 2xy + y2 ) - ( 4m2 - 4mn + n2 )

= ( x - y )2 - ( 2m - n )2

= ( x - y - 2m + n )( x - y + 2m - n )

30 tháng 9 2015

 

a) x3+y3+z3-3xyz

=(x+y)3+z3-3x2y-3xy2-3xyz

=(x+y+z).[(x+y)2+(x+y).z+z2]-3xy.(x+y+z)

=(x+y+z)(x2+2xy+y2+zx+zy+z2)-3xy.(x+y+z)

=(x+y+z)(x2+2xy+y2+zx+zy+z2-3xy)

=(x+y+z)(x2+y2+zx+zy+z2-zy)

 

b)a2(b-c)+b2(c-a)+c2(a-b)

=a2b-a2c+b2c-b2a+c2a-c2b

=(a2b-c2b)+(-a2c+c2a)+(b2c-b2a)

=b.(a2-c2)-ac.(a-c)-b2.(a-c)

=b.(a+c)(a-c)-ac.(a-c)-b2.(a-c)

=(a-c)[b.(a+c)-ac-b2]

=(a-c)(ab+bc-ac-b2)

=(a-c)[(ab-ac)+(bc-b2)]

=(a-c)[a.(b-c)-b.(b-c)]

=(a-c)(b-c)(a-b)