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\(B=-\frac{2}{17}+\frac{15}{23}+-\frac{15}{17}+\frac{4}{19}+\frac{8}{23}\)
\(B=\left(-\frac{2}{17}+-\frac{15}{17}\right)+\left(\frac{15}{23}+\frac{8}{23}\right)+\frac{4}{19}\)
\(B=\left(-1\right)+1+\frac{4}{19}\)
\(B=0+\frac{4}{9}=\frac{4}{9}\)
\(C=-\frac{1}{2}+\frac{3}{21}+-\frac{2}{6}+-\frac{5}{30}\)
\(C=-\frac{1}{2}+\frac{1}{7}+-\frac{1}{3}+-\frac{1}{6}\)
\(C=\left(-\frac{1}{2}+-\frac{1}{3}+-\frac{1}{6}\right)+\frac{1}{7}\)
\(C=\left(-1\right)+\frac{1}{7}\)
\(C=-\frac{6}{7}\)
Ủng hộ tk Đúng nhé ! ^^
B= -2 + 15 + (-15) + 4 + 8
17 23 17 19 23
B= [(-2) + (-15)] + [15 + 8] + 4
17 17 23 23 19
B= -1 +1+ 4 vậy B=4
19 19
a, \(\frac{3}{8}+\frac{11}{13}-\frac{9}{13}\)
=\(\frac{3}{8}+\frac{2}{13}\)
=\(\frac{55}{104}.\)
b, \(\frac{2}{7}.\left(\frac{5}{9}+\frac{4}{9}\right)+\frac{2}{7}\)
=\(\frac{2}{7}.\frac{9}{9}+\frac{2}{7}\)
=\(\frac{2}{7}+\frac{2}{7}\)
=\(\frac{4}{7}\)
c, \(\frac{3}{11}.\left(\frac{3}{5}-\frac{5}{3}\right)-\frac{3}{10}.\left(\frac{1}{3}-\frac{2}{5}\right)\)
=\(\frac{3}{11}.-\frac{16}{15}-\frac{3}{10}.-\frac{1}{15}\)
=\(-\frac{16}{55}--\frac{1}{50}\)
=\(-\frac{149}{550}.\)
d, \(\frac{-3}{4}.\frac{11}{23}+\frac{3}{23}.\frac{31}{17}-\frac{3}{17}.\frac{19}{23}\)
=\(-\frac{33}{92}+\frac{93}{391}-\frac{57}{391}\)
=\(-\frac{417}{1564}\)
e, \(\frac{3}{17}.\frac{11}{23}+\frac{3}{23}.\frac{31}{17}-\frac{3}{17}.\frac{19}{23}\)
=\(\frac{33}{391}+\frac{93}{391}--\frac{254}{391}\)
=\(\frac{380}{391}.\)
g, \(\frac{3}{7}.\frac{-5}{12}+\frac{11}{17}:\frac{5}{-12}\)
=\(-\frac{5}{28}+-\frac{132}{85}\)
= \(-1.731512605.\)
k cho mình nha làm mỏi tay quá ,.....................kết bạn với mình nha.......................
A = 18:26+(-5):27+(-22):86+12:39+(-32):43 = 9:13+(-5):27+(-11):43+4:13+(-32):43 = (9:13+4:13)+[(-11):43+(-32):43]+(-5):27 = 1+(-1)+5:27 = -5:27
B =(-10):12+8:15+(-19):56+3:(-18)+28:60 = (-5):6+8:15+(-19):56+1:(-6)+7:15 = [(-5):6+1:(-6)]+(8:15+7:15)+(-19):56 = (-1)+1+(-19):56 = (-19) :56
\(=\frac{16}{3}x\frac{30}{7}=\frac{480}{21}=\frac{160}{7}\)
\(\frac{33}{5}:\frac{21}{4}=\frac{33}{5}x\frac{4}{21}=\frac{132}{105}=\frac{44}{35}\)
\(8\frac{4}{17}-\left(2\frac{5}{9}+3\frac{4}{17}\right)=\frac{140}{17}-\left(\frac{23}{9}+\frac{55}{17}\right)=\frac{140}{17}-\frac{886}{153}=\frac{22}{9}=2,444444444444\)
\(A=8\frac{4}{17}-\left(2\frac{5}{9}+3\frac{4}{17}\right)\)
\(A=8\frac{4}{17}-2\frac{5}{9}-3\frac{4}{17}\)
\(A=\left(8\frac{4}{17}-3\frac{4}{17}\right)-\frac{23}{9}\)
\(A=5-\frac{23}{9}\)
\(A=\frac{45}{9}-\frac{23}{9}\)
\(A=\frac{22}{9}\)
\(A=8\frac{4}{7}-2\frac{5}{9}-3\frac{4}{7}\)
\(A=\left(8\frac{4}{7}-3\frac{4}{7}\right)-2\frac{5}{9}\)
\(A=5-2\frac{5}{9}\)
\(A=4+1-2\frac{5}{9}\)
\(A=4+1-\frac{23}{9}\)
\(A=4+\frac{-14}{9}\)
\(A=1\frac{5}{9}\)