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\(\left(\frac{3}{7}+\frac{1}{2}\right)^2=\left(\frac{13}{14}\right)^2=\frac{169}{196}\)
\(\frac{5^4\cdot20^4}{25^5\cdot4^5}=\frac{5^4\cdot4^4\cdot5^4}{5^5\cdot5^5.4^5}=\frac{1}{100}\)
\(\left(\frac{3}{7}\right)^{21}:\left(\frac{9}{49}\right)^6=\left(\frac{3}{7}\right)^{21}:\left[\left(\frac{3}{7}\right)^2\right]^6=\left(\frac{3}{7}\right)^{21}:\left(\frac{3}{7}\right)^{12}=\left(\frac{3}{7}\right)^9\)
\(3-\left(-\frac{6}{7}\right)^0+\left(\frac{1}{2}\right)^2:2\)
\(=3-1+\frac{1}{4}:2=3-1+\frac{1}{8}=\frac{17}{8}\)
( 2^9 .16 + 2^9 . 34 ) chia 2^10
=2^9 . ( 16 + 34 ) chia 2^10
=2^9 . 50 chia 2^10
=2^9 chia 2^10 . 50
= 0,5 .50=25
a)25.4:32=25.22:25=25+2-5=22=4
b)3.27:34=3.33:34=34:34=1
c)(29.16+29.32):210
=29.(16+32):210
=48:210-9
=48:2
=24
d)Bạn chữa lại dề nha
(34.57-92.21):35
=(34.57-34.22):35
=34.(57-22):35
=34.35:35
=34
=81
Tính
a) đáp án là 90
b)đáp án là âm 9
c)đáp án là âm 10
tìm x
a) xbằng 5
b) x bằng 3
c) x bằng 3
\(A=\frac{3^4.5^7-9^2.21}{3^5}=\frac{3^4.5^7-3^4.21}{3^5}=\frac{3^4.\left(5^7-21\right)}{3^5}=\frac{78125-21}{3}=\frac{78104}{3}\)
Vậy : \(A=\frac{78104}{3}\)
\(B=\frac{2^9.16+2^8.68}{2^{10}}=\frac{2^9.16+2^8.2.34}{2^{10}}=\frac{2^9.16+2^9.34}{2^{10}}\)
\(=\frac{2^9.\left(16+34\right)}{2^{10}}=\frac{2^9.50}{2^{10}}=\frac{50}{2}=25\)
Vậy :\(B=25\)
\(a,\left(3^4.5^7-9^2.21\right):3^5\)
\(=\left(81.78125-81.21\right):243\)
\(=\left[81.\left(78125-21\right)\right]:243\)
\(=\left[81.78104\right]:243\)
\(=6326424:243\)
\(=26034\)(dư 162)
\(\frac{78104}{3}\)