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\(5\left(x+4\right)-3\left(x-2\right)=x\)
\(\Leftrightarrow5x+20-3x+6=x\)
\(\Leftrightarrow2x+26=x\)
\(\Leftrightarrow2x-x=-26\)
\(\Leftrightarrow x=-26\)
\(\left(x-3\right)\left(x^2+1\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x-3=0\\x^2+1=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=3\\x^2=-1\Rightarrow\varnothing\end{cases}\Leftrightarrow x=3}\)
2:
a: =>2/3:x=1,4-2,4=-1
=>x=-2/3
b: =>x/5=25/30-19/30=6/30=1/5
=>x=1
3:
Số học sinh giỏi là 40*1/4=10 bạn
Số học sinh khá là 30*3/5=18 bạn
Số học sinh TB là 30-18=12 bạn
1.
a.= (-5/24+3/4+7/12): -9/4
=(-5/24+18/24+14/24) . -4/9
= 9/8 .-4/9=-1/2
b. =(3/5+83/200-3/200).8/3 .1/4
=(120/200+83/200-3/200) .2/3
=1.2/3=2/3
2.
a. 1/3(2x-5)=-2/3-3/2
1/3(2x-5)=-13/6
2x-5=-13/2
2x=-3/2
x=-3/2:2=-3/4
b. 1/3x-1/2x=3/4
x(1/3-1/2)=3/4
x.1/6=3/4
x=9/2
a, `(x-9)^4=(x-9)^7`
`(x-9)^4-(x-9)^7=0`
`(x-9)^4 . [(1-(x-9)^3]=0`
TH1: `(x-9)^4=0`
`x-9=0`
`x=9`
TH2: `1-(x-9)^3=0`
`(x-9)^3=1^3`
`x-9=1`
`x=10`
b, `(3x-15)^10=(3x-15)^15`
`(3x-15)^10 . [1-(3x-15)^5]=0`
TH1: `(3x-15)^10=0`
`3x-15=0`
`x=5`
TH2: `1-(3x-15)^5=0`
`(3x-15)^5=1^5`
`3x-15=1`
`x=16/3` (Loại)
c, `(x-8)^3=(x-8)^6`
`(x-8)^3 .[1-(x-8)^3]=0`
TH1: `(x-8)^3=0`
`x=8`
TH2: `1-(x-8)^3=0`
`x-8=1`
`x=9`
Bài 1:
a) \(\left(375-180\right):15\)
\(=195:15\)
\(=13\)
b) \(678\left(276+49\right)-678\left(149+76\right)\)
\(=678.325-678.225\)
\(=678\left(325-225\right)\)
\(=678.100\)
\(=67800\)
Bài 2:
\(12:\left\{390:\left[500-\left(125+35.7\right)\right]\right\}\)
\(=12:\left\{390:\left[500-\left(125+245\right)\right]\right\}\)
\(=12:\left\{390:\left[500-370\right]\right\}\)
\(=12:\left\{390:130\right\}\)
\(=12:3\)
\(=4\)
Bài 3:
a) \(2.3^x=54\)
\(\Leftrightarrow3^x=54:2\)
\(\Leftrightarrow3^x=27\)
\(\Leftrightarrow3^x=3^3\)
\(\Leftrightarrow x=3\)
b) \(3^2.3^x=81\)
\(\Leftrightarrow9.3^x=81\)
\(\Leftrightarrow3^x=81:9\)
\(\Leftrightarrow3^x=9\)
\(\Leftrightarrow3^x=3^2=\left(-3\right)^2\)
\(\Leftrightarrow x=2\)
c) \(\left(x-1\right)^3=8\)
\(\Leftrightarrow\left(x-1\right)^3=2^3\)
\(\Leftrightarrow x-1=2\)
\(\Leftrightarrow x=2+1\)
\(\Leftrightarrow x=3\)
Bài 4:
\(A=100+98+96+...+2-97-95-...-1\)
\(\Leftrightarrow A=\left(100+98+96+...+2\right)-\left(97+95+...+1\right)\)
\(\Leftrightarrow A=\left[\left(100+2\right).50:2\right]-\left[\left(97+1\right).49:2\right]\)
\(\Leftrightarrow A=2550-2401\)
\(\Leftrightarrow A=149\)