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\(\text{a)}\left(2^{17}+17^2\right)\left(9^{15}-15^9\right)\left(4^2-2^4\right)\)
\(=\left(2^{17}+17^2\right)\left(9^{15}-15^9\right)\left[\left(2^2\right)^2-2^4\right]\)
\(=\left(2^{17}+17^2\right)\left(9^{15}-15^9\right)\left(2^4-2^4\right)\)
\(=\left(2^{17}-17^2\right)\left(9^{15}-15^9\right).0\)
\(=0\)
\(\text{b)}\left(7^{1997}-7^{1995}\right):\left(7^{1994}.7\right)=\frac{7^{1997}-7^{1995}}{7^{1994}.7}=\frac{7^{1995}\left(7^2-1\right)}{7^{1995}}=7^2-1=48\)
a)\(\frac{2}{3}+\frac{3}{4}+\frac{5}{6}\)
\(=\frac{8+9+10}{12}\)
\(=\frac{27}{12}=\frac{9}{4}\)
b)\(\frac{15}{8}-\frac{7}{12}+\frac{5}{6}\)
\(=\frac{45-14+20}{24}\)
\(=\frac{51}{24}=\frac{17}{8}\)
2)
a)\(\frac{2}{5}+\frac{7}{13}+\frac{3}{5}+\frac{1}{7}\)
\(=\frac{2}{5}+\frac{3}{5}+\frac{7}{13}+\frac{1}{7}\)
\(=1+\frac{7}{13}+\frac{1}{7}\)
\(=\frac{20}{13}+\frac{1}{7}\)
\(=\frac{153}{91}\)
Tí tớ trả lời tiếp
a) \(\frac{-5}{8}\cdot\left(\frac{4}{9}+\frac{-7}{12}\right)\)
\(=\frac{-5}{8}\cdot\frac{-5}{36}\)
\(=\frac{25}{288}\)
b) \(\left(-3,2\right)\cdot\frac{-15}{64}+\left(0,8-2\frac{4}{5}\right):3\frac{1}{2}\)
\(=\frac{3}{4}+\left(-2\right):\frac{7}{2}\)
\(=\frac{3}{4}+\frac{-4}{7}\)
\(=\frac{5}{28}\)
=))
NHớ tick và theo dõi mik nhá!