Question

[Vũ Như Ngọc]

Bài 1 So sánh

\(\left(\frac{-1}{16}\right)^{100}\)va \(\left(\frac{-1}{2}\right)^{500}\)

Bài 2 So sánh

A =\(\frac{100^{100}+1}{100^{99}+1}\)Va B =\(\frac{100^{69}+1}{100^{68}+1}\)

Các p ơi giúp mink vs

Answer 1

[Đinh Thùy Linh]

Bài 1: \(\left(\frac{-1}{16}\right)^{100}=\frac{1}{\left(2^4\right)^{100}}=\frac{1}{2^{400}}>\frac{1}{2^{500}}=\left(\frac{-1}{2}\right)^{500}.\)

Bài 2: \(100^{99}+1>100^{68}+1\Rightarrow\frac{1}{100^{99}+1}< \frac{1}{100^{68}+1}\Rightarrow\frac{-99}{100^{99}+1}>\frac{-99}{100^{68}+1}\)

\(\Rightarrow100+\frac{-99}{100^{99}+1}>100+\frac{-99}{100^{68}+1}\Rightarrow\frac{100^{100}+1}{100^{99}+1}>\frac{100^{69}+1}{100^{68}+1}\)