Question

[Đức Anh Ramsay]

Bài 1: (4 điểm)  Thực hiện phép tính:

 a/ \(\dfrac{1-x}{x^2-2x+1}+\dfrac{x+1}{x-1}\)                            b/ \(\dfrac{2x}{3y^4z}.\left(-\dfrac{4y^2z}{5x}\right).\left(-\dfrac{15y^3}{8xz}\right)\)

Answer 1

[Nguyễn Lê Phước Thịnh]

a) Ta có: \(\dfrac{1-x}{x^2-2x+1}+\dfrac{x+1}{x-1}\)

\(=\dfrac{1-x}{\left(x-1\right)^2}-\dfrac{x+1}{1-x}\)

\(=\dfrac{1-x}{\left(1-x\right)^2}-\dfrac{x+1}{1-x}\)

\(=\dfrac{1-x-1}{1-x}=\dfrac{-x}{1-x}=\dfrac{x}{x-1}\)

b) Ta có: \(\dfrac{2x}{3y^4z}\cdot\left(-\dfrac{4y^2z}{5x}\right)\cdot\left(-\dfrac{15y^3}{8xz}\right)\)

\(=\dfrac{2x\cdot4y^2z\cdot15y^3}{3y^4z\cdot5x\cdot8xz}\)

\(=\dfrac{120xy^5z}{120x^2y^4z^2}=\dfrac{y}{xz}\)