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a) 15x2 + 10x = 5x ( 3x +2 )
b) x2 - y2 +2x -2y
= (x-y) (x+y) + 2(x-y)
= (x - y) ( x + y + 2)
c) 3x2 + 6xy + 3y2 -12 z2
= 3 ( x2 +2xy+y2) -12z2
= 3 (x+y)2 - 12 z2
= 3 [(x+y)2 - 4z2 ]
= 3( x + y - 2z )( x + y + 2z)
d) x2 - 5 -6 = x2 -11
= (x - √11)(x+√11)
a, \(15x^2+10x=5x\left(3x+2\right)\)
b, \(x^2-y^2+2x-2y=\left(x-y\right)\left(x+y\right)+2\left(x-y\right)\)
\(=\left(x-y\right)\left(x+y+2\right)\)
c, \(3x^2+6xy+3y^2-12z^2\)
\(=3\left(x^2+2xy+y^2-4z^2\right)\)
\(=3\left[\left(x+y\right)^2-\left(2z\right)^2\right]=3\left(x+y-2z\right)\left(x+y+2z\right)\)
d, \(x^2-5x-6=x^2-6x+x-6=x\left(x+1\right)-6\left(x+1\right)=\left(x-6\right)\left(x+1\right)\)
\(a,4x^4-8x^3+4x^2\)
\(=4x^2\cdot\left(x^2-2x+1\right)\)
\(=4x^2\cdot\left(x-1\right)^2\)
\(b,x^2-y^2+5\cdot\left(y-x\right)\)
\(=\left(x-y\right)\cdot\left(x+y\right)-5\cdot\left(x-y\right)\)
\(=\left(x-y\right)\cdot\left(x+y-5\right)\)
\(c,3x^2-6xy+3y^2-12z^2\)
\(=3\cdot\left(x^2-2xy+y^2-4x^2\right)\)
\(=3\cdot\left[\left(x-y\right)^2-\left(2x\right)^2\right]\)
\(=3\cdot\left(x-y-2x\right)\cdot\left(x-y+2x\right)\)
Bài làm
a) 4x - 8y
<=> 4( x - 2y )
b) 12x( x - 2y ) - 8y( x - 2y )
<=> ( 12x - 8y )( x - 2y )
<=> 4( 3x - 2y )( x - 2y )
c) 2x + 2y - x2 - xy
= 2( x + y ) - x( x + y )
= ( x + y )( 2 - x )
d) x2 - 4y2
<=> ( x - 2y )( x + 2y )
e) x3 + x2y - 4x - 4y
<=> x2( x + y ) - 4( x + y )
<=> ( x - 2 )( x + 2 )( x + y )
g) 3x2 - 6xy + 3y2 - 12x3
<=>3( x2 - 3xy + y2 - 4x3 )
# Học tốt #
a)4(x-2y)
b)(x-2y)(12x-8y)
=4(x-2y)(3x-2y)
c)2(x+y)-x(x+y)
=(2-x)(x+y)
d)(x-2y)(x+2y)
e)x2(x+y)-4(x+y)
=(x+y)(x2-4)
=(x+y)(x-2)(x+2)
g)3(x2-2xy+y2-4z3)
=3[(x-y)2-4z3]
????????????phải là 4z2chứ nhỉ.....
Bài làm
a) 4x2 - 6x
= 2x( 2x - 3 )
b) 9x4y3 + 3x2y4
= 3x2y3( 3x2 + y )
c) x3 - 2x2 + 5x
= x( x2 - 2x + 5 )
d) 3x( x - 1 ) + 5( x - 1 )
= ( x - 1 )( 3x + 5 )
e) 2x2( x + 1 ) + 4( x + 1 )
= ( x + 1 )( 2x2 + 4 )
= ( x + 1 )2( x2 + 2 )
= 2( x + 1 )( x2 + 2 )
f) -3x - 6xy + 9xz
= -( 3x + 6xy - 9xz )
= -3x( 1 + 2y - 3z )
# Học tốt #
a) \(3x^2y+6xy^2=3xy\left(x+2y\right)\)
b) \(x^2-y^2+4x+4\)
\(=\left(x^2-y^2\right)+4\left(x+1\right)\)
\(=\left(x-y\right)\left(x+y\right)+4\left(x+1\right)\)
c) \(x^2-2x-24\)
\(=x^2+6x-4x-24\)
\(=x\left(x+6\right)-4\left(x+6\right)\)
\(=\left(x+6\right)\left(x-4\right)\)
Chúc bạn học tốt nhé!
a) 3x2y+6xy2=3xy(x+2y)
b)x2-y2+4x+4=(x2+4x+4)-y2=(x+2)2-y2=(x-y+2)(x+y+2)
c) x2-2x-24=x2-6x+4x-24=x(x-6)+4(x-6)=(x+4)(x-6)
hc tốt
\(b,x^3+x^2y-xy^2-y^3\)
\(=\left(x^{ }^3+x^2y\right)-\left(xy^2+y^3\right)\)
\(=x^2\left(x+y\right)-y^2\left(x+y\right)\)
\(=\left(x^2+y^2\right)\left(x+y\right)\)
a) \(3x^2-3y^2=3\left(x^2-y^2\right)=3\left(x-y\right)\left(x+y\right)\)
b) \(x^2-xy+7x-7y=\left(x^2+7x\right)-\left(xy+7y\right)\)
\(=x\left(x+7\right)-x\left(y+7\right)=x\left(x+7-y-7\right)=x\left(x-y\right)\)
c)\(x^2-3x+2=x^2-2x-x+2=\left(x^2-x\right)-\left(2x-2\right)\)
\(=x\left(x-1\right)-2\left(x-1\right)=\left(x-2\right)\left(x-1\right)\)
d) \(x^3+2x^2y+xy^2-16x=x\left(x^2+2xy+y^2-16\right)\)
\(=x\left[\left(x+y\right)^2-16\right]=x\left(x+y-4\right)\left(x+y+4\right)\)
a) \(3x^2-6xy+3y^2-12z^2\)
\(=3\left(x^2-2xy+y^2-4z^2\right)\)
\(=3\left[\left(x-y\right)^2-\left(2z\right)^2\right]\)
\(=3\left(x-y-2z\right)\left(x-y+2z\right)\)
b) \(x^2-25+y^2+2xy\)
\(=\left(x^2+2xy+y^2\right)-25\)
\(=\left(x+y\right)^2-5^2\)
\(=\left(x+y+5\right)\left(x+y-5\right)\)
a,\(x^2-25+\left(x+5\right)\left(5-2x\right)\)
\(=\left(x-5\right)\left(x+5\right)+\left(x+5\right)\left(5-2x\right)\)
\(=\left(x+5\right)\left(x-5+5-2x\right)=-x\left(x+5\right)\)
b,\(3x^2-6xy+3y^2-12z^2=3\left[\left(x^2-2xy+y^2\right)-4z^2\right]\)
\(=3\left[\left(x-y\right)^2-\left(2z\right)^2\right]=3\left(x-y-2z\right)\left(x-y+2z\right)\)
c,\(x^3-3x^2+4x-12\)
\(=x^2\left(x-3\right)+4\left(x-3\right)=\left(x-3\right)\left(x^2+4\right)\)
d,\(x^2-y^2+4x+4=\left(x+2\right)^2-y^2=\left(x-y+2\right)\left(x+y+2\right)\)
b, (\(x^2\) - \(xy\) ) + (\(x-y\))
= (\(x-y\)).\(x\) + (\(x-y\))
= (\(x-y\)).(\(x\) + 1)
c, \(x^2\) - 2\(x\) - 15
= (\(x^2\) - 2\(x\) + 1) - 16
= (\(x\) - 1)2 - 42
= (\(x-1-4\)).(\(x-1+4\))
= (\(x-5\)).(\(x+3\))