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32,4 . 6,34 + 3,66 . 32,4 + 0,5
= 32,4 × (6,34 + 3,66) + 0,5
= 32,4 × 10 + 0,5
= 324 + 0,5
= 324,5
/x-1/=(-6).(-3)
/x-1/=18
\(\rightarrow x-1\in\left\{-18;18\right\}\)
\(\Rightarrow x\in\left\{-17;19\right\}\)
a chia cho 7 dư 4 nên a có dạng \(a=7.k+4\left(k\in N\right)\)
b chia cho 7 dư 6 nên b có dạng \(b=7.m+6\left(m\in N\right)\)
Ta có:\(a.b=\left(7k+4\right).\left(7m+6\right)=7k.7m+4.7m+6.7k+6.4\)
\(=49.k.m+28.m+42.k+24=49.k.m+28.m+42.k+21+3\) chia cho 7 dư 3
\(\dfrac{11}{8}:x-\dfrac{2}{5}+-\dfrac{1}{6}=-\dfrac{1}{5}\\ =>\dfrac{11}{8}:x-\dfrac{2}{5}=-\dfrac{1}{5}-\left(-\dfrac{1}{6}\right)\\ =>\dfrac{11}{8}:x-\dfrac{2}{5}=-\dfrac{1}{5}+\dfrac{1}{6}\\ =>\dfrac{11}{8}:x-\dfrac{2}{5}=-\dfrac{6}{30}+\dfrac{5}{30}\\ =>\dfrac{11}{8}:x-\dfrac{2}{5}=-\dfrac{1}{30}\\ =>\dfrac{11}{8}:x=-\dfrac{1}{30}+\dfrac{2}{5}\\ =>\dfrac{11}{8}:x=-\dfrac{1}{30}+\dfrac{12}{30}\\ =>\dfrac{11}{8}:x=\dfrac{11}{30}\\ =>x=\dfrac{11}{8}:\dfrac{11}{30}\\ =>x=\dfrac{11}{8}.\dfrac{30}{11}\\ =>x=\dfrac{30}{8}\\ =>x=\dfrac{15}{4}\\ \dfrac{4}{7}x-\dfrac{1}{3}x+\left(-\dfrac{16}{21}\right)=-\dfrac{2}{3}\\ =>\left(\dfrac{4}{7}-\dfrac{1}{3}\right)x=-\dfrac{2}{3}-\left(-\dfrac{16}{21}\right)\\ =>\left(\dfrac{12}{21}-\dfrac{7}{21}\right)x=-\dfrac{2}{3}+\dfrac{16}{21}\\ =>\dfrac{5}{21}x=-\dfrac{14}{21}+\dfrac{16}{21}\\ =>\dfrac{5}{21}x=\dfrac{2}{21}\\ =>x=\dfrac{2}{21}:\dfrac{5}{21}\)
\(=>x=\dfrac{2}{21}.\dfrac{21}{5}\\ =>x=\dfrac{2}{5}\\ -\dfrac{11}{12}x+\dfrac{15}{2}\left(x+-\dfrac{1}{5}\right)=\dfrac{67}{8}\\ =>-\dfrac{11}{12}x+\dfrac{15}{2}.x-\dfrac{1}{5}=\dfrac{67}{8}\\ =>\left(-\dfrac{11}{12}+\dfrac{15}{2}\right)x=\dfrac{67}{8}+\dfrac{1}{5}\\ =>\left(-\dfrac{11}{12}+\dfrac{90}{12}\right)x=\dfrac{335}{40}+\dfrac{8}{40}\\ =>\dfrac{79}{12}x=\dfrac{343}{40}\\ =>x=\dfrac{343}{40}:\dfrac{79}{12}\\ =>x=\dfrac{343}{40}.\dfrac{12}{79}\\ =>x=\dfrac{343.12}{40.79}\\ =>x=\dfrac{343.3}{10.79}\\ =>x=\dfrac{1029}{790}\)
a/5 - 2/b = 2/15
=> ab/5b - 10/5b = 2/15
Mà 5b giống nhau, khi thực hiện phép trừ ta giữ nguyên => 5b = 15 => b = 15:5 = 3
=> 3a/15 - 10/15 = 2/15
Từ đó tính được b.a = 3.a = 10 + 2 = 12
\(\left(2.x-15\right).11=11\)
\(\left(2.x-15\right)=11:11\)
\(2.x-15=1\)
\(2.x=1+15\)
\(2.x=16\)
\(x=16:2\)
\(x=8\)
Vậy \(x=8\)
Chúc bạn học tốt !!!
( 2x - 15 ) 11 = 11
2x - 15 = 11 : 11
2x - 15 = 1
2x = 1 + 15
2x = 16
x = 16 : 2
x = 8
Vậy x = 8