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LT
0
LM
1
19 tháng 3 2017
a. x= 2/3 : 3/7
=> x = 14/9
b.x= 11/3 . 8/11
=> x = 8/3
c.x = 2/5 : -1/4
=> x =-8/5
cho mk nhé!
DP
12 tháng 8 2017
b, \(\left(x+\frac{1}{2}\right)^2-\frac{1}{3}=\frac{1}{9}\)
\(\Leftrightarrow\left(x+\frac{1}{2}\right)^2=\frac{4}{9}\)
\(\Leftrightarrow\left(x+\frac{1}{2}\right)^2=\left(\frac{2}{3}\right)^3\)
\(\Leftrightarrow x+\frac{1}{2}=\frac{2}{3}\Rightarrow x=\frac{1}{6}\)
c, \(\left(x-\frac{1}{2}\right)^3+\frac{1}{4}=\frac{3}{8}\)
\(\Leftrightarrow\left(x-\frac{1}{2}\right)^3=\frac{1}{8}\)
\(\Leftrightarrow\left(x-\frac{1}{2}\right)^3=\left(\frac{1}{2}\right)^3\)
\(\Leftrightarrow\orbr{\begin{cases}x-\frac{1}{2}=\frac{1}{2}\\x-\frac{1}{2}=-\frac{1}{2}\end{cases}}\)\(\Rightarrow\orbr{\begin{cases}x=1\\x=0\end{cases}}\)
NT
0
DN
1
7 tháng 10 2016
mình chỉ làm phần 2 thui
3C=32+33+34+....+391
3C-C=391-31
C=(391-31):3
k nha
T
7 tháng 10 2023
Bài 1.
\(a,\left(2^4\cdot3\cdot5^2\right):\left\{450:\left[450-\left(4\cdot5^3-2^3\cdot5^2\right)\right]\right\}\)
\(=\left(16\cdot3\cdot25\right):\left\{450:\left[450- \left(4\cdot125-8\cdot25\right)\right]\right\}\)
\(=\left(48\cdot25\right):\left\{450:\left[450-\left(500-200\right)\right]\right\}\)
\(=1200:\left[450:\left(450-300\right)\right]\)
\(=1200:\left(450:150\right)\)
\(=1200:3\)
\(=400\)
\(---\)
\(b,3^3\cdot5^2-20\left\{90-\left[164-2\cdot\left(7^8:7^6+7^0\right)\right]\right\}\)
\(=27\cdot25-20\left\{90-\left[164-2\cdot\left(7^2+1\right)\right]\right\}\)
\(=675-20\left\{90-\left[164-2\cdot\left(49+1\right)\right]\right\}\)
\(=675-20\left[90-\left(164-2\cdot50\right)\right]\)
\(=675-20\left[90-\left(164-100\right)\right]\)
\(=675-20\left(90-64\right)\)
\(=675-20\cdot26\)
\(=675-520\)
\(=155\)
\(---\)
\(c,\left[\left(18^7:18^6-17\right)\cdot2022-1986\right]\cdot5\cdot1^{2022}-13^2\cdot2020^0\)
\(=\left[\left(18-17\right)\cdot2022-1986\right]\cdot5\cdot1-169\cdot1\)
\(=\left(1\cdot2022-1986\right)\cdot5-169\)
\(=\left(2022-1986\right)\cdot5-169\)
\(=36\cdot5-169\)
\(=180-169\)
\(=11\)
Bài 2.
\(a) (2^x+1)^2+3\cdot(2^2+1)=2^2\cdot10\\\Rightarrow (2^x+1)^2+3\cdot(4+1)=4\cdot10\\\Rightarrow (2^x+1)^2+3\cdot5=40\\\Rightarrow (2^x+1)^2+15=40\\\Rightarrow (2^x+1)^2=40-15\\\Rightarrow (2^x+1)^2=25\\\Rightarrow (2^x+1)^2= (\pm 5)^2\\\Rightarrow \left[\begin{array}{} 2^x+1=5\\ 2^x+1=-5 \end{array} \right.\\ \Rightarrow \left[\begin{array}{} 2^x=4\\ 2^x=-6 (vô.lí) \end{array} \right. \\ \Rightarrow 2^x=2^2\\\Rightarrow x=2\)
Vậy \(x=2\).
\(---\)
\(b)3\cdot(x-7)+2\cdot(x+5)=41\\\Rightarrow 3\cdot x+3\cdot(-7)+2\cdot x+2\cdot5=41\\\Rightarrow 3x-21+2x+10=41\\\Rightarrow (3x+2x)+(-21+10)=41\\\Rightarrow 5x-11=41\\\Rightarrow 5x=41+11\\\Rightarrow 5x=52\\\Rightarrow x=\dfrac{52}{5}\)
Vậy \(x=\dfrac{52}{5}\).
\(Toru\)
B = 1 + 3 + 32 + ... + 390
3B = 3 + 32 + 33 + ... + 391
3B - B = ( 3 + 32 + 33 + ... + 391 ) - ( 1 + 3 + 32 + ... + 390 )
2B = 391 - 1
B = \(\dfrac{3^{91}-1}{2}\)
thank !