Question

[dung doan]

B1 Giai các phương trình sau

1 3(2x-1)-(3+x)=x-2

2 4x+3-2(x-1)=0

3\(\frac{x}{x+1}-\frac{2}{x-2}=1\)

Answer 1

[Nguyễn Việt Lâm]

a/ \(6x-3-3-x=x-2\)

\(\Leftrightarrow4x=4\Rightarrow x=1\)

b/ \(4x+3-2x+2=0\)

\(\Rightarrow2x=-5\Rightarrow x=-\frac{5}{2}\)

c/ ĐKXĐ: ...

\(1-\frac{1}{x+1}-\frac{2}{x-2}=1\)

\(\Leftrightarrow\frac{1}{x+1}=\frac{-2}{x-2}\)

\(\Leftrightarrow x-2=-2x-2\)

\(\Rightarrow x=0\)