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a) 12 : { 400 : [500 – (125 + 25 . 7)]}
=12 : { 400 : [500 – (125 + 175)]}
=12 : [ 400 : [500 – 300)]
=12 : (400:200)
=12:2=6
b) 5 . 22 – 18 : 3
=5.4-6
=20-6=14
c) 18 : 3 + 182 + 3.(51 : 17)
=5+182+3.3
=187+9=196
d) 25 . 8 – 12.5 + 170 : 17 – 8
=200-60+10-8
=142
e) 2.52+ 3: 710 – 54: 33
=2.25+3:1-54:27
=50+3-2
=51
f) 189 + 73 + 211 + 127
=(189+211)+(73+127)
=400+200=600
g) 375 : {32 – [ 4 + (5. 32– 42)]} – 14 )
=375 : {32 – [ 4 + (160– 42)]} – 14 )
=375 : [32 – ( 4 + 118) – 14 ]
=375:(32-122-14)
=375:-104
=-375/104
h) (52022 + 52021) : 52021
=(52022:52021)+(52021:52021)
=5+1=6
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a) 2017 + 5.[ 300 - \(\left(17-7\right)^2\)]
= 2017 + 5.[ 300 - \(10^2\)]
= 2017 + 5.[ 300 - 100]
= 2017 + 5. 200
= 2017 + 1000
= 3017
b) \(5^{27}\).5.\(5^{25}\)-|-125|
= \(5^{27}\). 5 . \(5^{25}\) - 125
= \(5^{53}\) - 125
= \(5^{53}\) - \(5^3\)
= \(5^{53}\)+ 3
c) (\(5^{25}\).18+ \(5^{15}\).7) : \(5^{17}\)
= [ (\(5^{25}\) . \(5^{15}\)) . ( 18 . 7) ] : \(5^{17}\)
= [ \(5^{40}\) . 126 ] : \(5^{17}\)
= [ \(5^{40}\) : \(5^{17}\) ] . 126
= \(5^{23}\) . 126
Phần c) chưa chắc làm đúng nha
Học tốt :'3
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\(2011+5\left[300-\left(17-7\right)^2\right]\)
\(=2011+5\left[300-10^2\right]\)
\(=2011+5\left[300-100\right]\)
\(=2011+5.200\)
\(=2011+1000\)
\(=3011\)
học tốt
![](https://rs.olm.vn/images/avt/0.png?1311)
= 2015 + 5 x [300-100]
= 2015 + 5 x 200
= 2015 + 1000
= 3015
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a) 3.52 + 15.22 - 26 : 2
= 3.25 + 15.4 - 13
= 75 + 60 - 13
= 135 - 13
= 122
b) 2021 + 5.[300 - (17 - 7)2]
= 2021 + 5.[300 - 102]
= 2021 + 5.[300 - 100]
= 2021 + 5.200
= 2021 + 1000
= 3021
c) 32.5 + 23.10 - 81
= 9.5 + 8.10 - 81
= 45 + 80 - 81
= 125 - 81
= 44
a) 3.52 + 15.22 - 26 : 2
= 3. 25 + 15 . 4 - 26 : 2
= 75 + 60 - 13
= 135 - 13
= 122
b) 2021 + 5[300 - (17 - 7)2 ]
= 2021 + 5[300 - 102 ]
=2021 + 5[300 - 100]
=2021 + 5.200
=2021 + 1000
= 3021
c) 32 . 5 + 23 . 10 - 81
= 9 . 5 + 8 . 10 - 81
= 45 + 80 - 81
= 125 - 81
= 44
![](https://rs.olm.vn/images/avt/0.png?1311)
- 2011+5[300-(17-7)2]
- =2011+5[300-100]
- =2011+5+200
- =2011+205
=2216
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a. 7x-2x=617:615 + 44:11
=> 5x=62 + 4
=> 5x=36 + 4
=> 5x=40
=> x=40:5
=> x=8
b. 2x.(22)2=(23)2
=> 2x.24=26
=> 2x=26:24
=> 2x=22
=> x=2.
c. Theo đề => \(x\in BC\left(5,7\right)\)
Ta có: 5=5; 7=7
=> BCNN(5, 7)=5.7=35
=> \(x\in BC\left(5,7\right)=B\left(35\right)=\left\{0;35;70;105;140;175;210;245;280;315;...\right\}\)
Mà x < 300
Vậy x thuộc { 0; 35; 70; ...; 245; 280 }.
\(2021+5\left[300-\left(17-7\right)^2\right]\)
\(=2021+5\left[300-10^2\right]\)
\(=2021+5\left[300-100\right]\)
\(=2021+5\cdot200\)
\(=2021+1000=3021\)
b) 2021 + 5 [300 - (17 - 7)2]
= 2021 + 5 [ 300 - 102]
= 2021 + 5 [ 300 - 100]
= 2021 + 5 . 200
= 2021 + 1000
= 3021