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a: \(A=3\cdot\dfrac{1}{8}\cdot\dfrac{-1}{3}+6\cdot\dfrac{1}{8}\cdot\dfrac{1}{9}+3\cdot\dfrac{1}{2}\cdot\dfrac{-1}{27}\)
\(=\dfrac{-1}{8}+\dfrac{1}{12}-\dfrac{1}{18}=-\dfrac{7}{72}\)
b: \(B=\left(-1\cdot3\right)^2+\left(-1\right)\cdot3-1+27\)
\(=9-3-1+27\)
=36-4=32
c: \(C=-0.7xy^2-2x^2y-4.5xy\)
\(=-0.7\cdot\dfrac{1}{2}\cdot1-2\cdot0.25\cdot\left(-1\right)-4.5\cdot0.5\cdot\left(-1\right)\)
\(=\dfrac{-7}{20}+\dfrac{1}{2}+\dfrac{9}{2}\cdot\dfrac{1}{2}\)
\(=\dfrac{12}{5}\)
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giải
A=x(x^2-x+1)+1/2x^2(2-2x)
=x^2-x^2+x+x^2-x^3
=x^2+x-x^3
B=3x(x-2)-x(1+3x)
=3x^2-6x-x-3x^2
=-6x-x
C=x(x^2+xy+y^2)-y(x^2+xy+y^2)
=x^3+x^2y+xy^2-yx^2-xy^2-y^3
=x^3+x^2y-xy^2-y^3
D=3x(x^2-2x-3)-x^2(3x-2)+5(x^2-x)
=3x^3-6x^2-9x-3x^3+2x^2+5x^2-5x
=x^2-14x
chúc bạn học tốt nha
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1) \(x^3+y^3+z^3-3xyz\)
\(=\left(x+y\right)^3+z^3-3xy\left(x+y+z\right)\)
\(=\left(x+y+z\right)\left(x^2+y^2+z^2-xy-yz-zx\right)\)
3) \(ab\left(x^2+y^2\right)+xy\left(a^2+b^2\right)\)
\(=abx^2+aby^2+a^2xy+b^2xy\)
\(=ax\left(bx+ay\right)+by\left(ay+bx\right)\)
\(=\left(ay+bx\right)\left(ax+by\right)\)
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x+y+1=0 suy ra x+y=1
Làm câu A nhé B,C tương tự
A= x^2.(x+y-2)-(xy+y^2-2y)+(y+x-1)=0-y.(x+y-2)+1=1
Hok tốt
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A = 5x(x - y) - y(5x - y)
A = 5x2 - 5xy - 5xy + y2
A = 5x2 - 10xy + y2 (1)
Thay x = -1; y = 3 vào (1), ta có:
5.(-1)2 - 10.(-1).3 + 32 = 44
B = 4y(x2 - 3xy + 3y2) - 2xy(2x - 6y - 3)
B = 4x2y - 12x2 + 12y3 - 4x2y + 12xy2 + 6xy
B = 12y3 + 6xy (1)
Thay x = 5; y = -1 vào (1), ta có:
12.(-1)3 + 6.5.(-1) = -42
C = 5x2(x - y2) + 3x(xy2 - y) - 5x3
C = 5x3 - 5x2y2 + 3x2y2 - 3xy - 5x3
C = -2x2y2 - 3xy (1)
Thay x = -2; y = -5 vào (1), ta có:
-2.(-2)2.(-5)2 - 3.(-2).(-5) = -230
D = 6x2(y2 - xy + 2x2y) - 3xy(2xy - x2 + 4x3)
D = 6x2y2 - 6x3y + 12x4y - 6x2y2 + 3x3y - 12x4y
D = -3x3y (1)
Thay x = 11; y = -1 vào (1), ta có:
-3.113.(-1) = 3993
\(A+B=2x^2y+x^2-1\)
\(A-B=-2xy^2+5x^2+1\)