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a ) \(5.\left(x-7\right)=0\)
\(\Leftrightarrow x-7=5.0\)
\(\Leftrightarrow x-7=0\)
\(\Leftrightarrow x=7\)
b ) \(34.\left(2.x-6\right)=0\)
\(\Leftrightarrow2.x-6=34.0\)
\(\Leftrightarrow2.x-6=0\)
\(\Leftrightarrow2.x=0+6\)
\(\Leftrightarrow2.x=6\)
\(\Leftrightarrow x=6\div2\)
\(\Leftrightarrow x=3\)
c ) \(25+\left(15-x\right)=30\)
\(\Leftrightarrow25+\left(15-x\right)=-\left(x-40\right)\)
\(\Leftrightarrow-\left(x-40\right)=2.3.5\)
\(\Leftrightarrow40-x=30\)
\(\Leftrightarrow-x=-10\)
\(\Leftrightarrow x=10\)
d ) \(43-\left(24-x\right)=20\)
\(\Leftrightarrow24-x=43-20\)
\(\Leftrightarrow24-x=23\)
\(\Leftrightarrow x=24-23\)
\(\Leftrightarrow x=1\)
e ) \(2.\left(x-5\right)-17=25\)
\(\Leftrightarrow2.\left(x-5\right)=25+17\)
\(\Leftrightarrow2.\left(x-5\right)=42\)
\(\Leftrightarrow x-5=42\div2\)
\(\Leftrightarrow x-5=21\)
\(\Leftrightarrow x=21+5\)
\(\Leftrightarrow x=26\)
f ) \(24+3.\left(5-x\right)=27\)
\(\Leftrightarrow3.\left(5-x\right)=27-24\)'
\(\Leftrightarrow3.\left(5-x\right)=3\)
\(\Leftrightarrow5-x=3\div3\)
\(\Leftrightarrow5-x=1\)
\(\Leftrightarrow x=5-1\)
\(\Leftrightarrow x=4\)
g ) \(15\div x-2=3\)
\(\Leftrightarrow15\div x=3+2\)
\(\Leftrightarrow15\div x=5\)
\(\Leftrightarrow x=15\div5\)
\(\Leftrightarrow x=3\)
h ) \(\left(32-x\div5\right)\div13=2\)
\(\Leftrightarrow32-x\div5=2\times13\)
\(\Leftrightarrow32-x\div5=26\)
\(\Leftrightarrow x\div5=32-26\)
\(\Leftrightarrow x\div5=6\)
\(\Leftrightarrow x=5.6\)
\(\Leftrightarrow x=30\)
g ) \(\left(6-2x\right)\left(x-8\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}6-2x=0\\x-8=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=3\\x=8\end{matrix}\right.\)
Vậy \(x\in\left\{3;8\right\}\)
Mình làm hết nhaa !!
a)5.(x-7)=0
x-7=0:5
x-7=0
x=0+7
x=7
Vậy x=7
b)34.(2x-6)=0
2x-6 =0:34
2x-6 =0
2x=0+6
2x=6
x=6:2
x=3
Vậy x= 3
c)25+(15-x)=30
15-x=30-25
15-x=5
x=15-5
x=10
Vậy x=10
d)43-(24-x)=20
24-x =43-20
24-x=23
x=24-23
x=1
vậy x=1
e)2(x-5)-17=25
2(x-5)=25+17
2(x-5)=42
x-5=42:2
x-5=21
x=21+5
x=26
Vậy x=26
f)24+3(5-x)=27
3(5-x)=27-24
3(5-x)=3
5-x =3:3
5-x=1
x=5-1
x=4
Vậy x=4
g)15:x-2=3
15:x=3+2
15:x=5
x=15:5
x=3
Vậy x=3
h)( 32-x:5):13=2
32-x:5 =2.13
32-x :5=26
x:5= 32-26
x:5=6
x=6.5
x=30
Vậy x=30
k)(6-2x)(x-8)=0
➩6-2x=0 hoặc x-8=0
2x=6-0 x=0+8
2x=6 x=8
x=6:2
x=3
Vậy x=3 hoặc x=8
\(\left|x\right|=a\Leftrightarrow\hept{\begin{cases}x=a,x\ge0\\x=-a,x< 0.\end{cases}}\)
a) x=-5 hoặc x=5
b) |-11|=11
|x|=|-11|=11
x<0
x=-11
c) |13|=13
|x|=|13|=13, x<0
x=-13
d) |x|+|-6|=|25|
|x|+6=25
|x|=25-6=19
x=19 hoặc x=-19
Tìm x εIN biết
a) 390 - (x-8) = 168:13
b) (x-140) : 7 = 27 - 24
c) x- 6 :2 - ( 48 - 24 ) :2 :6 - 3 = 0
d) x+5.2-(32+16.3:6-15)=0
b) \(\left(x-140\right):7=27-24\)
\(\left(x-140\right):7=3\)
\(x-140=21\)
\(x=161\)
vay \(x=161\)
c) \(x-6:2-\left(48-24\right):2:6-3=0\)
\(x-3-24:2:6-3=0\)
\(x-3-2-3=0\)
\(x-8=0\)
\(x=8\)
vay \(x=8\)
d) \(x+5.2-\left(32+16.3:6-15\right)=0\)
\(x+10-\left(32+8-15\right)=0\)
\(x+10-25=0\)
\(x-15=0\)
\(x=15\)
vay \(x=15\)
a) \(390-\left(x-8\right)=168:13\)
\(390-x+8=\frac{168}{13}\)
\(x+8=390-\frac{168}{13}\)
\(x+8=\frac{5070}{13}-\frac{168}{13}\)
\(x+8=\frac{4902}{13}\)
\(x=\frac{4902}{13}-8\)
\(x=\frac{4798}{13}\)
vay \(x=\frac{4798}{13}\)
x(x+2)=0
suy ra x=0 hoặc x+2=0
5-2x=-7
2x=-7+5
2x=-(7-5)
2x=-2
x=-2:2
x=-1
Vậy x=-1
NHỚ TÍCH MK NHA
Tự học giúp bạn có được một gia tài
Jim Rohn – Triết lý cuộc đời
a) 22 + (2x -13) = 83 => 2x -13 = 61 => x = 37.
b) 51 - (-12 + 3x) = 27 => 63 - 3x = 27 => x = 12.
c) - (2x + 2) + 21 = - 23 => 2x + 2 = 44 => x = 21.
d) 25 - (25 - x) = 0 => 25 - 25 + x = 0 => x = 0.
a) 2000.2000..>.. 1990.2010
b) 25.33 -10 ..<..31.26+10
d)32.53 -10 ..<..53.31+32
e) 1998.1998..>..1996.2000
-Bài này không có ý c hả bạn?
a.x-25=0+110
x+25=110
x=85
b.118-x=142-124
118-x=18
x=100
c.3x+22=124-42
3x+22=82
3x=88-22
3x=66
x=22
d.x-2=18
x=20
e.x-32=18.16
x-32=288
x=320
f.19-2x=294:42
19-2x=7
2x=19-7
2x=12
x=6
Dung thi k cho minh nha!!!
a) \(\left(x+22\right)\left(x-13\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x+22=0\\x-13=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=-22\\x=13\end{cases}}}\)
Vậy \(x\in\left\{-22;13\right\}\)
b) \(\left(-x+25\right)\left(32-x\right)=0\)
\(\Leftrightarrow\left(25-x\right)\left(32-x\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}25-x=0\\32-x=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=25\\x=32\end{cases}}}\)
Vậy \(x\in\left\{25;32\right\}\)
a)\(\left(x+22\right)\left(x-13\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x+22=0\\x-13=0\end{cases}\Rightarrow\orbr{\begin{cases}x=-22\\x=13\end{cases}}}\)
b) \(\left(-x+25\right)\left(32-x\right)=0\)
\(\Rightarrow\orbr{\begin{cases}-x+25=0\\32-x=0\end{cases}\Rightarrow\orbr{\begin{cases}x=25\\x=32\end{cases}}}\)
hok tốt!!