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Bài 1:
(x-6)^2020+2(y+3)^2022=0
=>x-6=0 và y+3=0
=>x=6 và y=-3
1.
$(a+b+c)-(a-b+c)=a+b+c-a+b-c=(a-a)+(b+b)+(c-c)=0+2b+0=2b$
2.
$(a-b+c)-(a-b+c)=0$
3.
$(a+b+c)-(b-a+c)=a+b+c-b+a-c=(a+a)+(b-b)+(c-c)=2a+0+0=2a$
4.
$(a-c)-(d+b+a+c)=a-c-d-b-a-c=(a-a)+(-c-c)-d-b=0-2c-d-b=-2c-d-b$
5.
$(a+d-c)-(a+b-c)=a+d-c-a-b+c=(a-a)+(-c+c)+d-b=0+0+d-b=d-b$
6.
$(a-b+c+d)+(a+c-d-b)=a-b+c+d+a+c-d-b$
$=(a+a)+(-b-b)+(c+c)+(d-d)=2a-2b+2c$
7.
$(a+d-c)+(a-b+c)=a+d-c+a-b+c=(a+a)+d+(-c+c)=2a+d$
\(x=\dfrac{4}{27}-\dfrac{2}{3}\)
\(x=-\dfrac{14}{27}\)
x + 6 chia hết cho x + 3
=> x + 3 + 3 chia hết cho x + 3
=> 3 chia hết cho x + 3
=> (x + 3) \(\in\) Ư(3)
=> (x + 3) \(\in\) {-3; -1; 1; 3}
=> x \(\in\) {-6; -4; -2; 0}
1: =>-9/3<x<8/5+9/5=17/5
=>-3<x<17/5
=>\(x\in\left\{-2;-1;0;1;2;3\right\}\)
2: =>-8/20<x/20<1/12
=>-24/60<3x/60<5/60
=>-24<3x<5
=>\(3x\in\left\{-21;-18;...;0;3\right\}\)
=>\(x\in\left\{-7;-6;...;0;1\right\}\)
3: -1/3<x/24<-1/4
=>-8/24<x/24<-6/24
=>-8<x<-6
=>x=-7
4:
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can gì thì nói