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\(\Rightarrow B=\frac{\frac{3}{2}.\left(\frac{1}{6}-\frac{1}{16}+\frac{1}{16}-\frac{1}{26}+\frac{1}{26}-\frac{1}{36}\right)}{\frac{33}{10}.\left(\frac{1}{6}-\frac{1}{16}+\frac{1}{16}-\frac{1}{26}+\frac{1}{26}-\frac{1}{36}\right)}=\frac{\frac{3}{2}}{\frac{33}{10}}=\frac{3}{2}:\frac{33}{10}=\frac{5}{11}\)
\(\frac{15.\left(\frac{1}{616}.\frac{1}{6.16}.\frac{1}{6.16}\right)}{33.\left(\frac{1}{6.16}.\frac{1}{6.16}.\frac{1}{6.16}\right)}=\frac{15}{35}\)
\(A=\frac{\frac{3}{2}\left(\frac{1}{6}-\frac{1}{16}+\frac{1}{16}-\frac{1}{26}+\frac{1}{26}-\frac{1}{36}\right)}{\frac{33}{10}\left(\frac{1}{6}-\frac{1}{16}+\frac{1}{16}-\frac{1}{26}+\frac{1}{26}-\frac{1}{36}\right)}=\frac{\frac{3}{2}}{\frac{33}{10}}=\frac{3}{2}:\frac{33}{10}=\frac{5}{11}\)
Ta có:\(A=\frac{\frac{15}{6.16}+\frac{15}{16.26}+\frac{15}{26.36}}{\frac{33}{6.16}+\frac{63}{16.26}+\frac{93}{26.36}}\)
=>\(A=\frac{\left(\frac{1}{6.16}+\frac{1}{16.26}+\frac{1}{26.36}\right).15}{\frac{33}{6.16}+\frac{\frac{21}{11}.33}{16.26}+\frac{\frac{31}{11}.33}{26.36}}\)
=>\(A=\frac{\left(\frac{1}{6.16}+\frac{1}{16.26}+\frac{1}{26.36}\right).15}{\frac{21}{11}.\frac{31}{11}.33.\left(\frac{1}{6.16}+\frac{1}{16.26}+\frac{1}{26.36}\right)}\)
=>\(A=\frac{15}{\frac{21}{11}.\frac{31}{11}.33}\)
=>\(A=\frac{15}{\frac{1953}{11}}\)
=>\(A=\frac{55}{651}\)
Vậy \(A=\frac{55}{651}\)