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a: Sửa đề: \(\left[\left(6\dfrac{3}{7}-\dfrac{0,75x-2}{0,35}\right)\cdot2.8+1.75\right]\cdot0.05=2.35\)
\(\Leftrightarrow\left(\dfrac{45}{7}-\dfrac{15x-40}{7}\right)\cdot2.8+1,75=47\)
\(\Leftrightarrow\dfrac{45-15x+40}{7}\cdot2,8=45,25\)
\(\Leftrightarrow\dfrac{85-15x}{7}=\dfrac{905}{56}\)
=>8(85-15x)=905
=>680-120x=905
=>120x=-225
hay x=-15/8
b: \(\dfrac{3}{5}-\dfrac{2}{7}< \dfrac{2}{3}x+\dfrac{3}{4}< \dfrac{1}{2}+\dfrac{7}{9}\)
\(\Leftrightarrow\dfrac{11}{35}-\dfrac{3}{4}< \dfrac{2}{3}x< \dfrac{23}{18}-\dfrac{3}{4}\)
\(\Leftrightarrow-\dfrac{61}{140}< \dfrac{2}{3}x< \dfrac{19}{36}\)
\(\Leftrightarrow-\dfrac{183}{280}< x< \dfrac{19}{24}\)
x - 2 =3
x =3+2
x =5
\(6\frac{3}{7}-0,75x-\frac{2}{0,35}\times2,8=10\)
\(\frac{45}{7}-\frac{3}{4}x-\frac{40}{7}\times\frac{28}{10}=10\)
\(\frac{45}{7}-\frac{3}{4}x=10+4\)
\(\frac{3}{4}x=\frac{45}{7}-14\)
\(\frac{3}{4}x=-\frac{53}{7}\)
\(x=-\frac{53}{7}:\frac{3}{4}\)
\(x=\frac{-212}{21}\)
* \(\dfrac{15}{12}:x=\left(\dfrac{5}{6}-\dfrac{1}{2}\right).\dfrac{5}{4}\)
\(\dfrac{15}{12}:x=\dfrac{1}{3}.\dfrac{5}{4}\)
\(\dfrac{15}{12}:x=\dfrac{5}{12}\)
\(x=\dfrac{15}{12}:\dfrac{5}{12}\)
\(x=3\)
* \(y:0,15=\left(2,8+0,38\right):0,75\)
\(y:0,15=3,18:0,75\)
\(y:15=4,24\)
\(y=4,24.15\)
\(y=63,6\)