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b ) 5x + x = 39 - 32
=> 6x = 39 - 9
6x = 30
x = 30 : 6
x = 5
a ) 5x + 3x = 36 : 32 . 4 + 12
=> 8x = 36-2 . 4 + 12
8x = 34 . 4 + 12
8x = 81 . 4 + 12
8x = 324 + 12
8x = 336
x = 336 : 8
x = 42
k nha !
1) 8x = 81 x 4 + 12
8x = 324 + 12
8x = 336
x = 336 : 8
x = 42
2) 6x = 30
x = 30 : 6
x = 5
nha ^^
a . 3x+(-24)= -9-(2x)
= 3x+(-24) = -9 +( -2x)
= 3x + 2x = -9 + 24
= 5x = 15
x = 15 : 5
x = 3
b .80+(5x)=9+(-20)
= 80 + 5x = -11
5x = -11 - 80
5x = -91
x = -91 : 5
x = -18,2 = \(\dfrac{-91}{5}\)
x
a) Đặt: \(A=1+2^2+2^3+...+2^{10}\)
\(\Rightarrow2A=2\left(1+2^2+2^3+...+2^9+2^{10}\right)\)
\(\Rightarrow2A=2+2^3+2^4+...+2^{10}+2^{11}\)
\(\Rightarrow2A-A=\left(2+2^3+2^4+...+2^{10}+2^{11}\right)-\left(1+2^2+2^3+...+2^{10}\right)\)
\(\Rightarrow A=\left(2^3-2^3\right)+\left(2^4-2^4\right)+...+\left(2-1\right)+\left(2^{11}-2^2\right)\)
\(\Rightarrow A=0+0+...+1+\left(2^{11}-2^2\right)\)
\(\Rightarrow A=1+2^{11}-2^2=1+2048-4=2045\)
Vậy: \(1+2^2+2^3+...+2^{10}=2045\)
b)
a] \(60-3\left(x-1\right)=2^3\cdot3\)
\(\Rightarrow60-3\left(x-1\right)=24\)
\(\Rightarrow3\left(x-1\right)=36\)
\(\Rightarrow x-1=12\)
\(\Rightarrow x=13\)
b] \(\left(3x-2\right)^3=2\cdot2^5\)
\(\Rightarrow\left(3x-2\right)^3=2^6\)
\(\Rightarrow\left(3x-2\right)^3=\left(2^2\right)^3\)
\(\Rightarrow3x-2=2^2\)
\(\Rightarrow3x=6\)
\(x=2\)
c] \(5^{x+1}-5^x=500\)
\(\Rightarrow5^x\left(5-1\right)=500\)
\(\Rightarrow5^x\cdot4=500\)
\(\Rightarrow5^x=125\)
\(\Rightarrow5^x=5^3\)
\(\Rightarrow x=3\)
d] \(x^2=x^4\)
\(\Rightarrow x=x^2\)
\(\Rightarrow x-x^2=0\)
\(\Rightarrow x\left(1-x\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=0\\1-x=0\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=0\\x=1\end{matrix}\right.\)
a) Ta có: \(18-x=58-\left(-30\right)\)
\(\Leftrightarrow18-x=88\)
\(\Leftrightarrow x=18-88=-70\)
Vậy: x=-70
b) Ta có: \(x-27=\left(-43\right)-9\)
\(\Leftrightarrow x-27=-43-9\)
\(\Leftrightarrow x-27=-52\)
\(\Leftrightarrow x=-25\)
Vậy: x=-25
c) Ta có: \(169-\left(x+4\right)=69\)
\(\Leftrightarrow x+4=169-69\)
\(\Leftrightarrow x+4=100\)
\(\Leftrightarrow x=96\)
Vậy: x=96
d) Ta có: \(\left(5x+3\right)-\left(-24+4\right)=33\)
\(\Leftrightarrow5x+3+24-4-33=0\)
\(\Leftrightarrow5x-10=0\)
\(\Leftrightarrow5x=10\)
\(\Leftrightarrow x=2\)
Vậy: x=2
e) Ta có: \(225-\frac{\left(5x+10\right)}{25}+5=-\left(-20\right)\)
\(\Leftrightarrow225-\frac{5x+10}{25}+5-20=0\)
⇔\(-\frac{5x+10}{25}+210=0\)
\(\Leftrightarrow-\frac{5x+10}{25}=-210\)
⇔\(\frac{5x+10}{25}=210\)
\(\Leftrightarrow5x+10=210\cdot25=5250\)
\(\Leftrightarrow5x=5250-10=5240\)
\(\Leftrightarrow x=1048\)
Vậy: x=1048
a)5x(-20)
=(-100)
b)(-9)x4
=(-36)
t tôi nhé bn