OP
3
K
Khách
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Các câu hỏi dưới đây có thể giống với câu hỏi trên
OP
3
S
1 tháng 5 2019
\(a,\frac{5}{6}+\frac{7}{12}-\frac{2}{3}\)
\(=\frac{10}{12}+\frac{7}{12}-\frac{8}{12}\)
\(=\frac{10+7-8}{12}\)
\(=\frac{9}{12}\)
\(=\frac{3}{4}\)
\(b,\frac{3}{4}-1\frac{1}{2}+50\%:\frac{5}{12}\)
\(=\frac{3}{4}-\frac{3}{2}+\frac{1}{2}:\frac{5}{12}\)
\(=\frac{3}{4}-\frac{6}{4}+\frac{1}{2}.\frac{12}{5}\)
\(=\frac{-3}{4}+\frac{6}{5}\)
\(=\frac{-15}{20}+\frac{24}{20}\)
\(=\frac{9}{20}\)
\(c,\frac{2}{7}.5\frac{1}{4}-\frac{2}{7}.3\frac{1}{4}\)
\(=\frac{2}{7}.\left(5\frac{1}{4}-3\frac{1}{4}\right)\)
\(=\frac{2}{7}.\left[\left(5-3\right)+\left(\frac{1}{4}-\frac{1}{4}\right)\right]\)
\(=\frac{2}{7}\left[2+0\right]\)
\(=\frac{2}{7}.2\)
\(=\frac{4}{7}\)
~Study well~
OP
8
OP
6
TS
5 tháng 6 2016
Số hạng trên là
( 1000 - 10 ) : 10 + 1 = 100 số hạng
Tổng trên là
( 1000 + 10 ) x 100 : 2 = 50500
Đáp số : 50500
GN
GV Nguyễn Trần Thành Đạt
Giáo viên
3 tháng 8 2023
\(2\left(x-3\right)+2^3=3^2.2\\ 2\left(x-3\right)=18-8\\ 2\left(x-3\right)=10\\ x-3=\dfrac{10}{2}\\ x-3=5\\ x=5+3\\ x=8\\ ----\\ 2^2.3-3\left(x-4\right)=2^3-2\\ 12-3\left(x-4\right)=6\\ 3\left(x-4\right)=12-6\\ 3\left(x-4\right)=6\\ x-4=6:3\\ x-4=2\\ x=2+4\\ x=6\\ ----\\ 7.2^2-4\left(2x+1\right)=2^3\\ 28-4\left(2x+1\right)=8\\ 4\left(2x+1\right)=28-8\\ 4\left(2x+1\right)=20\\ 2x+1=20:4\\ 2x+1=5\\ 2x=5-1\\ 2x=4\\ x=\dfrac{4}{2}=2\\ ---\\ 600-2\left(x-3\right)^8=11.2^3\\ 600-2\left(x-3\right)^8=88\\ 2\left(x-3\right)^8=600-88\\ 2\left(x-3\right)^8=512\\ \left(x-3\right)^8=\dfrac{512}{2}\\ \left(x-3\right)^8=256=2^8=\left(-2\right)^8\\ x-3=2.hoặc.x-3=-2\\ x=5.hoặc.x=1\)
LM
Lê Minh Vũ
CTVHS
14 tháng 6 2023
\(\left(-\dfrac{1}{2}\right)^2\div\dfrac{1}{4}-2\times\left(-\dfrac{1}{2}\right)^2\\= \dfrac{1}{4}\div\dfrac{1}{4}-2\times\dfrac{1}{4}\\ =1-\dfrac{1}{2}\\ =\dfrac{1}{2}\)
\(\left(-2\right)^3\times-\dfrac{1}{24}+\left(\dfrac{4}{3}-1\dfrac{5}{6}\right)\div\dfrac{5}{12}\)
= \(-6\times-\dfrac{1}{24}+\left(\dfrac{4}{3}-\dfrac{11}{6}\right)\div\dfrac{5}{12}\)
= \(\dfrac{1}{4}+-\dfrac{1}{2}\div\dfrac{5}{12}\)
= \(\dfrac{1}{4}+-\dfrac{6}{5}\)
= \(\dfrac{1}{4}-\dfrac{6}{5}\)
= \(-\dfrac{19}{20}\)
\(\left(6\dfrac{4}{9}+\dfrac{7}{11}\right)-\left(4\dfrac{4}{9}-2\dfrac{4}{11}\right)\\ =\dfrac{58}{9}+\dfrac{7}{11}-\dfrac{40}{9}+\dfrac{26}{11}\\ =\dfrac{58}{9}-\dfrac{40}{9}+\dfrac{7}{11}+\dfrac{26}{11}\\ =12+3\\ =15\)
TA
14 tháng 6 2023
\(a,\left(\dfrac{-1}{2}\right)^2:\dfrac{1}{4}-2\left(-\dfrac{1}{2}\right)^2\)
\(=\left(-\dfrac{1}{2}\right)^2\left(4-2\right)\)
\(=\dfrac{1}{4}.2=\dfrac{1}{2}\)
\(b,\left(-2\right)^3.\dfrac{-1}{24}+\left(\dfrac{4}{3}-1\dfrac{5}{6}\right):\dfrac{5}{12}\)
\(=\left(-8\right).\dfrac{-1}{24}+\left(-\dfrac{1}{2}\right).\dfrac{12}{5}\)
\(=\dfrac{1}{3}+\left(-\dfrac{1}{5}\right)=\dfrac{2}{15}\)
\(c,\left(6\dfrac{4}{9}+\dfrac{7}{11}\right)-\left(4\dfrac{4}{9}-2\dfrac{4}{11}\right)\)
\(=\dfrac{701}{99}-\dfrac{206}{99}=\dfrac{495}{99}=5\)
\(d,10\dfrac{1}{5}-5\dfrac{1}{2}.\dfrac{60}{11}+\dfrac{3}{15\%}\)
\(=\dfrac{51}{5}-30+20=\dfrac{1}{5}\)
\(e,\dfrac{5}{7}.\dfrac{5}{11}+\dfrac{5}{7}.\dfrac{2}{11}-\dfrac{5}{7}.\dfrac{14}{11}\)
\(=\dfrac{5}{7}\left(\dfrac{5}{11}+\dfrac{2}{11}-\dfrac{14}{11}\right)=\dfrac{5}{7}.\left(-\dfrac{7}{11}\right)\)
\(=-\dfrac{5}{11}\)
\(f,\dfrac{-5}{7}.\dfrac{2}{11}+\left(-\dfrac{5}{7}\right).\dfrac{9}{11}+1\dfrac{5}{7}\)
\(=\left(-\dfrac{5}{7}\right)\left(\dfrac{2}{11}+\dfrac{9}{11}\right)+\dfrac{12}{7}\)
\(=\left(-\dfrac{5}{7}\right)+\dfrac{12}{7}=1\)
a) \(\frac{5}{6}+\frac{7}{12}-\frac{2}{3}\)=\(\frac{10}{12}+\frac{7}{12}-\frac{8}{12}\)=\(\frac{9}{12}=\frac{3}{4}\)
b) \(\frac{3}{4}-1\frac{1}{2}+50\%:\frac{5}{12}\)=\(\frac{3}{4}-\frac{3}{2}+\frac{1}{2}:\frac{5}{12}\)=\(\frac{3}{4}-\frac{3}{2}+\frac{6}{5}\)=\(\frac{30}{40}-\frac{60}{40}+\frac{48}{40}\)= \(\frac{18}{40}\)=\(\frac{9}{20}\)
c)ghi lại đề hộ mk, mk ko rõ
Bạn nhìn ở trên mới ghi lại