Question

[Kim Taehiong]

\(a,3^{16}:3=\)dưới dạng 1 lũy thừa

\(b,3^6.3^4.3^2.3\)= dưới dạng 1 lũy thừa

\(c,\left(\frac{-1}{4}\right).\left(6\frac{2}{11}\right)+\left(3\frac{9}{11}\right).\frac{-1}{4}\)

\(d,\left(\frac{-1}{2}\right)^3+\frac{1}{2}:5\)

\(g,1\frac{1}{25}+\frac{2}{21}-\frac{1}{25}+\frac{19}{21}\)

Answer 1

[Vy Thị Hoàng Lan ( Toán Học )]

\(a,3^{16}:3=3^{16-1}=3^{15}\)

\(b,3^6.3^4.3^2.3=3^{6+4+2+1}=3^{13}\)

\(c,\left(-\frac{1}{4}\right).\left(6\frac{2}{11}\right)+\left(3\frac{9}{11}\right).\left(-\frac{1}{4}\right)=\left(-\frac{1}{4}\right).\frac{68}{11}+\frac{42}{11}.\left(-\frac{1}{4}\right)\)

\(=\left(-\frac{1}{4}\right)\left(\frac{68}{11}+\frac{42}{11}\right)\)

\(=\left(-\frac{1}{4}\right).10\)

\(=-\frac{10}{4}=-\frac{5}{2}\)

\(d,\left(-\frac{1}{2}\right)^3+\frac{1}{2}:5=\left(-\frac{1}{2}\right)\left(\left(\frac{1}{2}\right)^2-\frac{1}{5}\right)\)

\(=-\frac{1}{2}.\left(\frac{1}{4}-\frac{1}{5}\right)\)

\(=-\frac{1}{2}.\frac{1}{20}\)

\(=-\frac{1}{40}\)

\(g,1\frac{1}{25}+\frac{2}{21}-\frac{1}{25}+\frac{19}{21}=\frac{26}{25}+\frac{2}{21}-\frac{1}{25}+\frac{19}{21}\)

\(=\left(\frac{26}{25}-\frac{1}{25}\right)+\left(\frac{2}{21}+\frac{19}{21}\right)\)

\(=1+1\)

\(=2\)