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a) \(\frac{2}{5}x-x=\frac{\left(-2018\right)^0}{5^2}\\ x\left(\frac{2}{5}-1\right)=\frac{1}{25}\\ x\left(\frac{2}{5}-\frac{5}{5}\right)=\frac{1}{25}\\ x\cdot\frac{-3}{5}=\frac{1}{25}\\ x=\frac{1}{25}:\frac{-3}{5}\\ x=\frac{1}{25}\cdot\frac{-5}{3}\\ x=\frac{-1}{15}\)Vậy \(x=\frac{-1}{15}\)
b) \(\left|-1\frac{1}{2}x+2x\right|-\frac{7}{4}=0,5\\ \left|x\left(-1\frac{1}{2}+2\right)\right|-\frac{7}{4}=\frac{1}{2}\\ \left|x\cdot\frac{1}{2}\right|=\frac{1}{2}+\frac{7}{4}\\ \left|x\cdot\frac{1}{2}\right|=\frac{2}{4}+\frac{7}{4}\\ \left|x\cdot\frac{1}{2}\right|=\frac{9}{4}\\ \Rightarrow\left[{}\begin{matrix}x\cdot\frac{1}{2}=\frac{9}{4}\\x\cdot\frac{1}{2}=\frac{-9}{4}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\frac{9}{4}:\frac{1}{2}\\x=\frac{-9}{4}:\frac{1}{2}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\frac{9}{4}\cdot2\\x=\frac{-9}{4}\cdot2\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\frac{9}{2}\\x=\frac{-9}{2}\end{matrix}\right.\)Vậy \(x\in\left\{\frac{9}{2};\frac{-9}{2}\right\}\)
c) \(x+\left(x+\frac{2}{7}\right)+\frac{-5}{11}=\frac{4}{11}\\ x+x+\frac{2}{7}=\frac{4}{11}-\frac{-5}{11}\\ 2x+\frac{2}{7}=\frac{4}{11}+\frac{5}{11}\\ 2x+\frac{2}{7}=\frac{9}{11}\\ 2x=\frac{9}{11}-\frac{2}{7}\\ 2x=\frac{63}{77}-\frac{22}{77}\\ 2x=\frac{41}{77}\\ x=\frac{41}{77}:2\\ x=\frac{41}{77\cdot2}\\ x=\frac{41}{154}\)Vậy \(x=\frac{41}{154}\)
d) \(\left|0,25x-20\%\right|+\frac{3}{8}=1\frac{3}{8}\\ \left|\frac{1}{4}x-\frac{1}{5}\right|=1\frac{3}{8}-\frac{3}{8}\\ \left|\frac{1}{4}x-\frac{1}{5}\right|=1\\ \Rightarrow\left[{}\begin{matrix}\frac{1}{4}x-\frac{1}{5}=1\\\frac{1}{4}x-\frac{1}{5}=-1\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}\frac{1}{4}x=1+\frac{1}{5}\\\frac{1}{4}x=\left(-1\right)+\frac{1}{5}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}\frac{1}{4}x=\frac{5}{5}+\frac{1}{5}\\\frac{1}{4}x=\frac{-5}{5}+\frac{1}{5}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}\frac{1}{4}x=\frac{6}{5}\\\frac{1}{4}x=\frac{-4}{5}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\frac{6}{5}:\frac{1}{4}\\x=\frac{-4}{5}:\frac{1}{4}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\frac{6}{5}\cdot4\\x=\frac{-4}{5}\cdot4\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\frac{24}{5}\\x=\frac{-16}{5}\end{matrix}\right.\)Vậy \(x\in\left\{\frac{24}{5};\frac{-16}{5}\right\}\)
a) \(x+\frac{5}{12}=-1\frac{2}{7}\)
\(\Leftrightarrow x+\frac{5}{12}=\frac{-9}{7}\)
\(\Leftrightarrow x=\frac{-143}{84}\)
Vậy ...
b) \(4\frac{1}{2}x:\frac{5}{12}=0,5\)
\(\Leftrightarrow\frac{9}{2}x=\frac{5}{24}\)
\(\Leftrightarrow x=\frac{5}{108}\)
vậy...
c) \(7,5.1\frac{3}{4}x=6\frac{2}{5}\)
\(\Leftrightarrow\frac{105}{8}x=\frac{32}{5}\)
\(\Leftrightarrow x=\frac{256}{525}\)
Vậy ...
a) 187 - {[497 - ( 8 x X + 11) : X] : 3 - 78} = 150
=> {[497 - ( 8 x X + 11) : X] : 3 - 78} = 187 - 150
=> {[497 - (8 x X + 11) : X] : 3 - 78} = 37
=> [497 - (8 x X +11): X ] : 3 - 78 = 37
=> [497 - (8 x X + 11) : X] : 3 = 115
=> 497 - ( 8 x X + 11) : X = 345
=> (8 x X + 11) : X = 497 - 345 = 152
=> 8X + 11 = 152X
=> 152X - 8X = 11
=> 144X = 11
=> X = 11/144
b) 19,96 + 4,19 - 24,15 : \(\left(x:\frac{1}{4}-\frac{1}{4}\right)=23,15\)
=> 19,96 + 4,19 - 24,15 : \(\left(x\cdot4-\frac{1}{4}\right)=23,15\)
=> 24,15 - 24,15 : \(\left(x\cdot4-\frac{1}{4}\right)\)= 23,15
=> 24,15 : \(\left(x\cdot4-\frac{1}{4}\right)\)= 1
=> \(x\cdot4-\frac{1}{4}=24,15\)
=> \(x\cdot4=24,15+\frac{1}{4}=24,4\)
=> x = 24,4 : 4 = 6,1
Còn câu c tương tự
a, \(1\frac{1}{2}.x-0,5x+20\%x=31\)
\(\frac{3}{2}x-\frac{1}{2}x+\frac{1}{5}x=31\)
\(x\left(\frac{3}{2}-\frac{1}{2}+\frac{1}{5}\right)=31\)
\(x.\frac{6}{5}=31\)
\(x=\frac{155}{6}\)
b, \(\frac{x-2}{7}=\frac{-7}{2-x}\)
\(\Rightarrow\frac{x-2}{7}=\frac{-7}{-\left(x-2\right)}\)
\(\Rightarrow-\left(x-2\right)\left(x-2\right)=7.\left(-7\right)=-49\)
\(\Rightarrow\left(x-2\right)^2=49=7^2\)
\(\Rightarrow\orbr{\begin{cases}x-2=7\\x-2=-7\end{cases}\Rightarrow}\orbr{\begin{cases}x=9\\x=-5\end{cases}}\)