Question

[Nguyễn Quốc Huy]

a=1/1.2+1/2.3+1/3.4+.......1/19.20

Ai giải giúp mik với< cảm ơn ạ!

Answer 1

[Xyz OLM]

Ta có A = \(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{19.20}=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{19}-\frac{1}{20}=1-\frac{1}{20}\)

\(=\frac{19}{20}\)

Answer 2

[FL.Han_]

\(A=\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{19.20}\)

\(=\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}...+\frac{1}{19}-\frac{1}{20}\)

\(=\frac{1}{1}-\frac{1}{20}\)

\(=\frac{19}{20}\)