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Giải:
a) \(\dfrac{56.2,7+56.3,5}{0,62}\)
\(=\dfrac{56.6,2}{0,62}\)
\(=56.10=560\)
b) \(371.65+371.14+629.79\)
\(=371\left(65+14\right)+629.79\)
\(=371.79+629.79\)
\(=79\left(371+629\right)\)
\(=79.1000=79000\)
c) \(0,48.700-2,4.45.2\)
\(=4,8.70-4,8.45\)
\(=4,8\left(70-45\right)\)
\(=4,8.25=120\)
e) \(3,2.950+8.175.4+320.73\)
\(=32.95+32.175+32.730\)
\(=32\left(95+175+730\right)\)
\(=32.1000=32000\)
Vậy ...
Giải:
a) 56.2,7+56.3,50,6256.2,7+56.3,50,62
=56.6,20,62=56.6,20,62
=56.10=560=56.10=560
b) 371.65+371.14+629.79371.65+371.14+629.79
=371(65+14)+629.79=371(65+14)+629.79
=371.79+629.79=371.79+629.79
=79(371+629)=79(371+629)
=79.1000=79000=79.1000=79000
c) 0,48.700−2,4.45.20,48.700−2,4.45.2
=4,8.70−4,8.45=4,8.70−4,8.45
=4,8(70−45)=4,8(70−45)
=4,8.25=120=4,8.25=120
e) 3,2.950+8.175.4+320.733,2.950+8.175.4+320.73
=32.95+32.175+32.730=32.95+32.175+32.730
=32(95+175+730)=32(95+175+730)
=32.1000=32000=32.1000
__________
0,48x700-2,4x45x2
=0,48x(700-5x45x2)
=0,48x(700-450)
=0,48x250
=120
4,5+3,5+2,5+1,5+0,5-4-3-2-1
=(4,5-4)+(3,5-3)+(2,5-2)+(1,5-1)+0,5
=0,5+0,5+0,5+0,5+0,5
=0,5x5
=2,5
tìm x , biết :
a . 1,5 . x + 2,5 = 1
\(1,5.x=-1,5\)
\(x=\dfrac{-1,5}{1,5}\)
\(x=-1\)
b . ( 0,5 . x - 1,3 ) : 0,5 = -1,7
\(0,5.x-1,3=-0,85\)
\(0,5x=-2,15\)
\(x=\dfrac{-2,15}{0,5}\)
\(x=-4,3\)
c . 1,75 .x - 1,5 . x = 0,84
\(x\left(1,75-1,5\right)=0,84\)
\(x.0,25=0,84\)
\(x=3,36\)
d . x + 75% . x + 125% = 1
\(x+\dfrac{75}{100}.x+\dfrac{125}{100}=1\)
\(x+\dfrac{3}{4}.x+\dfrac{5}{4}=1\)
\(x+\dfrac{3}{4}.x=-\dfrac{1}{4}\)
\(x.\left(1+\dfrac{3}{4}\right)=-\dfrac{1}{4}\)
\(x.1,75=-\dfrac{1}{4}\)
\(x=-\dfrac{1}{7}\)
e . x - 25% .x + 75% = 1
\(x-\dfrac{25}{100}.x+\dfrac{75}{100}=1\)
\(x-\dfrac{1}{4}.x+\dfrac{3}{4}=1\)
\(x-\dfrac{1}{4}.x=\dfrac{1}{4}\)
\(x.\left(1-\dfrac{1}{4}\right)=\dfrac{1}{4}\)
\(x.\dfrac{3}{4}=\dfrac{1}{4}\)
\(x=\dfrac{1}{3}\)
f . | x - 1,5 | = 2,37
TH1 : \(x-1,5=2,37\)
\(x=2,37+1,5\)
\(x=3,87\)
TH2 : \(x-1,5=-2,37\)
\(x=-2,37+1,5\)
\(x=-0,87\)
\(a,x+3,79=15,12\)\(\Rightarrow x=15,12-3,79\)\(\Rightarrow x=11,33\)
\(b,12,1-x=5,49\)\(\Rightarrow x=12,1-5,49\Rightarrow x=6,61\)
\(c,60,45:x=1,5\)\(\Rightarrow x=60,45:1,5\Rightarrow x=40,3\)
\(d,3,5.x-1,5.x=12,5\)
\(\Rightarrow x\left(3,5-1,5\right)=12,5\)
\(\Rightarrow x.2=12,25\Rightarrow x=12,25:2=6,125\)
\(d,12,5.x-2,5.x-50=2,5.10\)
\(\Rightarrow12,5.x-2,5.x-50=25\)
\(\Rightarrow x\left(12,5-2,5\right)=25+50\)
\(\Rightarrow x.10=75\)
\(\Rightarrow x=75:10=7,5\)
a) x=11,33 b) x=6,61 c)40,3
Mình chỉ biết làm tới đó thôi. xin lỗi nha
a, 2 x 3 x 4 x 8 x 50 x 25 x 125 b, 45 x 128 - 90 x 64
= ( 2 x 50 ) x ( 4 x 25 ) x ( 8 x 125 ) x 3 = 45 x ( 128 - 2 x 64 )
= 100 x 100 x 1000 x 3 = 45 x 0
= 30000000 = 0
c, 0,48 x 500 - 2,4 x 40 x 2
= 0,48 x 100 x 5 - 2,4 x 10 x 4 x 2
= 48 x 5 - 24 x 8
= 24 x ( 2 x 5 - 8 )
= 24 x 2
= 48
d, \(\frac{1998\times1996+1997\times11+1985}{1997\times1996-1995\times1996}\)
\(=\frac{1998\times1996+\left(1996+1\right)\times11+1985}{1996\times\left(1997-1995\right)}\)
\(=\frac{1998\times1996+1996\times11+11+1985}{1996\times2}\)
\(=\frac{1998\times1996+1996\times11+1996}{1996\times2}\)
\(=\frac{1996\times\left(1998+11+1\right)}{1996\times2}\)
\(=\frac{1996\times2010}{1996\times2}\)
\(=\frac{2010}{2}\)
\(=1005\)
a, \(2.3.4.8.50.25.125\)
\(=\left(2.50\right)\left(4.25\right)\left(8.125\right).3\)
\(=100.100.1000.3\)
\(=10000000.3\)
\(=30000000\)
b, \(45.128-90.64\)
\(=45.2.64-90.4\)
\(=90.64-90.64\)
\(=0\)
c, \(0,48.500-2,4.40.2\)
\(=0,48.100.5-2,4.2.10.4\)
\(=48.5-4,8.10.4\)
\(=48.5-48.4\)
\(=48\left(5-4\right)\)
\(=48.1\)
\(=48\)
d, \(\frac{1998.1996+1997.11+1985}{1997.1996-1995.1996}\) \(\)
\(=\frac{1998.1996+\left(1996+1\right).11+1985}{1996\left(1997-1995\right)}\)
\(=\frac{1998.1996+1996.11+11+1985}{1996.2}\)
\(=\frac{1998.1996+1996.11+1996}{1996.2}\)
\(=\frac{1996\left(1998+11+1\right)}{1996.2}\)
\(=\frac{1998+11+1}{2}\)
\(=\frac{2010}{2}\)
\(=1005\)
a ) x = − 3 4 + 4 5 ⇔ x = 1 20 b ) x = − 4 9 : 2 , 5 ⇔ x = − 8 45 c ) 3 , 5 − 2 x = 1 7 : 2 3 7 ⇔ 3 , 5 − 2 x = 1 17 ⇔ 2 x = 3 , 5 − 1 17 ⇔ 2 x = 117 34 ⇔ x = 117 34 : 2 = 117 68
\(a,\frac{1}{3}+\frac{6}{11}.\frac{22}{5}-\frac{3}{4}:1,5=\frac{1}{3}+\frac{6.2}{5}-\frac{3}{4}:\frac{3}{2}=\frac{1}{3}+\frac{12}{5}-\frac{1}{2}=\frac{10}{30}+\frac{72}{5}-\frac{15}{30}=\frac{67}{30}\)
\(b, 3.3,5.6+2.6,4.9+1,8=18.3,5+18.6,4+1,8=18\left(3,5+6,4\right)+1,8=18.9,9+1,8=1,8.99+1,8=1,8\left(1+99\right)=1,8.100=180\)
b ) 3 x 3,5 x 6 + 2 x 6,4 x 9 + 1,8
= 18 x 3,5 + 18x 6,4 + 18 x 0,1
= 18 ( 3,5 + 6,4 + 0,1)
= 18 x 10
= 180
yêu cầu là gì hả bạn êk~~