Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a) y + 3/7 x 21/9 = 5
y + 3/7 x 7/3 = 5
y + 1 = 5
y = 4
b) y x 3/5 - 1/2 = 4/5
y x 3/5 = 4/5 + 1/2
y x 3/5 = 13/10
y = 13/6
c) 9/8 - y + 2/5 = 1/4
y - 2/5 = 9 /8 - 1/4
y - 2/5 = 7/8
y = 51/40
d) y - 6/5 : 2/3 = 5/6
y - 9/5 = 5/6
y = 79/30
e) y : 7/8 + 3/4 = 7/4
y : 7/8 = 1
y = 7/8
a, ta thấy cả hai vế đều có 4/5 mà lại bằng nhau nên x bằng số hạng còn lại ở vế phải
x=3/7+3/5
x=36/35
b,x là số hạng chưa biết nên
x=4/5-5/7
x=3/35
\(x+\frac{4}{5}=\frac{45}{5}-\left(\frac{3}{7}+\frac{3}{5}\right)\)
\(x+\frac{4}{5}=9-\frac{36}{35}\)
\(x+\frac{4}{5}=\frac{279}{35}\)
\(\Rightarrow x=\frac{251}{35}\)
\(x+\frac{4}{5}=\frac{45}{5}-\left(\frac{3}{7}+\frac{3}{5}\right)\)
\(\Leftrightarrow x+\frac{4}{5}=9-\left(\frac{3}{7}+\frac{3}{5}\right)\)
\(\Leftrightarrow x+\frac{4}{5}=9-\frac{3}{7}-\frac{3}{5}\)
\(\Leftrightarrow x+\frac{4}{5}=\frac{315}{35}-\frac{15}{35}-\frac{21}{35}\)
\(\Leftrightarrow x+\frac{4}{5}=\frac{279}{35}\)
\(\Leftrightarrow x=\frac{279}{35}-\frac{4}{5}\)
\(\Leftrightarrow x=\frac{251}{35}\)
\(1)\frac{12}{7}\times \frac{7}{4}+\frac{35}{11}:\frac{245}{121}\)
\(=3+\frac{35}{11}\times \frac{121}{245}\)
\(=3+\frac{11}{7}\)
\(= 3\frac{1}{7}(=\frac{22}{7})\)
`x + 4/5= 45/5 -( 3/7 + 3/5)`
`=> x+ 4/5=9 - 36/35`
`=> x+ 4/5=279/35`
`=> x= 279/35 -4/5`
`=>x= 251/35`
__
`5/7 + x/35 = 4/5`
`=> x/35 = 4/5-5/7`
`=> x/35 =28/35 - 25/35`
`=> x/35= 3/35`
`=>x=3`
`@ `\(MinYewCou\)
\(a,x+\dfrac{4}{5}=\dfrac{45}{5}-\left(\dfrac{3}{7}+\dfrac{3}{5}\right)\)
\(x+\dfrac{4}{5}=9-\dfrac{3}{7}-\dfrac{3}{5}\)
\(x+\dfrac{4}{9}=\dfrac{279}{35}\)
\(x=\dfrac{279}{35}-\dfrac{4}{9}\)
\(x=\dfrac{251}{35}\)
\(b,\dfrac{5}{7}+\dfrac{x}{35}=\dfrac{4}{5}\)
\(\dfrac{5}{7}+\dfrac{x}{35}-\dfrac{4}{5}=0\)
\(\dfrac{25}{35}+\dfrac{x}{35}-\dfrac{28}{35}=0\)
\(25+x-28=0\)
\(x=3\)
A) \(\frac{4}{5}\)x\( y\)=\(\frac{5}{7}:\frac{3}{14}=\frac{10}{3}\)
\(\Rightarrow y=\frac{10}{3}:\frac{4}{5}=\frac{10}{3}.\frac{5}{4}=\frac{25}{6}\)
B) \(\Rightarrow\frac{22}{5}:y=\frac{44}{5}:\frac{5}{2}=\frac{44}{5}.\frac{2}{5}=\frac{88}{25}\)
\(\Rightarrow y=\frac{22}{5}:\frac{88}{25}=\frac{22}{5}.\frac{25}{88}=\frac{5}{4}\)
\(12:y=\frac{3}{4}+\frac{4}{5}\)
\(12:y=\frac{15}{20}+\frac{16}{20}\)
\(12:y=\frac{31}{20}\)
\(y=12:\frac{31}{20}\)
\(y=12x\frac{20}{31}\)
\(y=\frac{240}{31}\)
\(\frac{4}{5}xY=1\)
\(y=1:\frac{4}{5}\)
\(y=1x\frac{5}{4}\)
\(y=\frac{5}{4}\)
\(\frac{37}{63}-y=\frac{1}{7}\)
\(y=\frac{37}{63}-\frac{1}{7}\)
\(y=\frac{37}{63}-\frac{9}{63}\)
\(y=\frac{28}{63}\)
\(y=\frac{4}{9}\)
\(y:\frac{3}{7}=\frac{3}{42}+\frac{5}{7}\)
\(y:\frac{3}{7}=\frac{3}{42}+\frac{30}{42}\)
\(y:\frac{3}{7}=\frac{33}{42}\)
\(y:\frac{3}{7}=\frac{11}{14}\)
\(y=\frac{11}{14}x\frac{3}{7}\)
\(y=\frac{33}{98}\)
\(12:y=\frac{3}{4}+\frac{4}{5}\) \(\frac{37}{63}-y=\frac{1}{7}\)
\(12:y=\frac{31}{20}\) \(y=\frac{37}{63}-\frac{1}{7}\)
\(y=12:\frac{31}{20}\) \(y=\frac{4}{9}\)
\(y=\frac{240}{31}\)
\(\frac{4}{5}\cdot y=1\) \(y:\frac{3}{7}=\frac{3}{42}+\frac{5}{7}\)
\(y=1:\frac{4}{5}\) \(y:\frac{3}{7}=\frac{11}{14}\)
\(y=\frac{5}{4}\) \(y=\frac{11}{14}.\frac{3}{7}\)
\(y=\frac{33}{98}\)
a,y +4/5=4/5 + (3/7 + 3/5 )
y +4/5=4/5 + 36/35
vì 2 bên đều có 4/5 nên ta bỏ 4/5 đi
y=36/35
b,5/7 + y/35=4/5
y/35=4/5-5/7
y/35=3/35
y=3