Câu hỏi của Mai Nguyễn Bảo Thắng

Question

.A) x/x+1=1/2 ,    B)  x/2=x/3 , C) x+1/2=x+1/2017, i)3/x=x/2017 , O) x:3=x+1/2 , m) x+1/2=x+2/3 ,P) x+1/2=x , M) 2/x=x/8 , Q) x2/2=8/x2 , r) x3/2=32/x

Edogawa Conan · Accepted Answer

a) $\frac{x}{x+1}=\frac{1}{2}$=> 2x = x + 1=> 2x - x = 1=> x = 1b) $\frac{x}{2}=\frac{x}{3}$=> 3x = 2x=> 3x - 2x = 0=> x = 0c) $\frac{x+1}{2}=\frac{x+1}{2017}$=> $2017\left(x+1\right)=2\left(x+1\right)$=> 2017x + 2017 = 2x + 2=> 2017x - 2x = 2 - 2017=> 2015x = -2015=> x = -2015 : 2015=> x = -1i) $\frac{3}{x}=\frac{x}{2017}$=> x2 = 2017.3=> x2 = 6051=> $\orbr{\begin{cases}x=\sqrt{6051}\x=-\sqrt{6051}\end{cases}}$còn lại tự lmCâu trả lời: a) $\frac{x}{x+1}=\frac{1}{2}$=> 2x = x + 1=> 2x - x = 1=> x = 1b) $\frac{x}{2}=\frac{x}{3}$=> 3x = 2x=> 3x - 2x = 0=> x = 0c) $\frac{x+1}{2}=\frac{x+1}{2017}$=> $2017\left(x+1\right)=2\left(x+1\right)$=> 2017x + 2017 = 2x + 2=> 2017x - 2x = 2 - 2017=> 2015x = -2015=> x = -2015 : 2015=> x = -1i) $\frac{3}{x}=\frac{x}{2017}$=> x2 = 2017.3=> x2 = 6051=> $\orbr{\begin{cases}x=\sqrt{6051}\x=-\sqrt{6051}\end{cases}}$còn lại tự lm

Vy Thị Hoàng Lan ( Toán Học ) · Answer

$a,\frac{x}{x+1}=\frac{1}{2}$$\Rightarrow x=\frac{1}{2}.\left(x+1\right)$$\Rightarrow x=\frac{1}{2}x+\frac{1}{2}$$\Rightarrow x-\frac{1}{2}x=\frac{1}{2}$$\Rightarrow\frac{1}{2}x=\frac{1}{2}$$\Rightarrow x=1$$b,\frac{x}{2}=\frac{x}{3}$$\Rightarrow x=\frac{x}{3}.2$$\Rightarrow x=\frac{2x}{3}$$\Rightarrow3x=2x$$\Rightarrow x=0$$c,\frac{x+1}{2}=\frac{x+1}{2017}$$\Rightarrow x+1=\frac{x+1}{2017}.2$$\Rightarrow x+1=\frac{2x+2}{2017}$$\Rightarrow2017x+2017=2x+2$$\Rightarrow2017x-2x=2-2017$$\Rightarrow2015x=-2015$$\Rightarrow x=-1$$i,\frac{3}{x}=\frac{x}{2017}$$\Rightarrow x=3:\frac{x}{2017}$$\Rightarrow x=\frac{6051}{x}$$\Rightarrow x^2=6051$$\Rightarrow x=\sqrt{6051}$$o,\frac{x}{3}=\frac{x+1}{2}$$\Rightarrow x=\frac{x+1}{2}.3$$\Rightarrow x=\frac{3x+3}{2}$$\Rightarrow2x=3x+3$$\Rightarrow-x=3$$\Rightarrow x=-3$$m,\frac{x+1}{2}=\frac{x+2}{3}$$\Rightarrow x+1=\frac{x+2}{3}.2$$\Rightarrow x+1=\frac{2x+4}{3}$$\Rightarrow3x+3=2x+4$$\Rightarrow x=1$$p,\frac{x+1}{2}=x$$\Rightarrow2x=x+1$$\Rightarrow x=1$$m,\frac{2}{x}=\frac{x}{8}$$\Rightarrow x=2:\frac{x}{8}$$\Rightarrow x=\frac{16}{x}$$\Rightarrow x^2=16$$\Rightarrow x=4$$Q,\frac{x^2}{2}=\frac{8}{x^2}$$\Rightarrow x^2=\frac{8}{x^2}.2$$\Rightarrow x^2=\frac{16}{x^2}$$\Rightarrow x^4=16$$\Rightarrow x=2$$r,\frac{x^3}{2}=\frac{32}{x}$$\Rightarrow x^3=\frac{32}{x}.2$$\Rightarrow x^3=\frac{64}{x}$$\Rightarrow x^4=64$$\Rightarrow x=\sqrt[4]{64}$Câu trả lời: $a,\frac{x}{x+1}=\frac{1}{2}$$\Rightarrow x=\frac{1}{2}.\left(x+1\right)$$\Rightarrow x=\frac{1}{2}x+\frac{1}{2}$$\Rightarrow x-\frac{1}{2}x=\frac{1}{2}$$\Rightarrow\frac{1}{2}x=\frac{1}{2}$$\Rightarrow x=1$$b,\frac{x}{2}=\frac{x}{3}$$\Rightarrow x=\frac{x}{3}.2$$\Rightarrow x=\frac{2x}{3}$$\Rightarrow3x=2x$$\Rightarrow x=0$$c,\frac{x+1}{2}=\frac{x+1}{2017}$$\Rightarrow x+1=\frac{x+1}{2017}.2$$\Rightarrow x+1=\frac{2x+2}{2017}$$\Rightarrow2017x+2017=2x+2$$\Rightarrow2017x-2x=2-2017$$\Rightarrow2015x=-2015$$\Rightarrow x=-1$$i,\frac{3}{x}=\frac{x}{2017}$$\Rightarrow x=3:\frac{x}{2017}$$\Rightarrow x=\frac{6051}{x}$$\Rightarrow x^2=6051$$\Rightarrow x=\sqrt{6051}$$o,\frac{x}{3}=\frac{x+1}{2}$$\Rightarrow x=\frac{x+1}{2}.3$$\Rightarrow x=\frac{3x+3}{2}$$\Rightarrow2x=3x+3$$\Rightarrow-x=3$$\Rightarrow x=-3$$m,\frac{x+1}{2}=\frac{x+2}{3}$$\Rightarrow x+1=\frac{x+2}{3}.2$$\Rightarrow x+1=\frac{2x+4}{3}$$\Rightarrow3x+3=2x+4$$\Rightarrow x=1$$p,\frac{x+1}{2}=x$$\Rightarrow2x=x+1$$\Rightarrow x=1$$m,\frac{2}{x}=\frac{x}{8}$$\Rightarrow x=2:\frac{x}{8}$$\Rightarrow x=\frac{16}{x}$$\Rightarrow x^2=16$$\Rightarrow x=4$$Q,\frac{x^2}{2}=\frac{8}{x^2}$$\Rightarrow x^2=\frac{8}{x^2}.2$$\Rightarrow x^2=\frac{16}{x^2}$$\Rightarrow x^4=16$$\Rightarrow x=2$$r,\frac{x^3}{2}=\frac{32}{x}$$\Rightarrow x^3=\frac{32}{x}.2$$\Rightarrow x^3=\frac{64}{x}$$\Rightarrow x^4=64$$\Rightarrow x=\sqrt[4]{64}$

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