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a) \(\frac{3}{2}-\frac{5}{6}:x=\frac{5}{15}-\frac{3}{15}\)
\(\Leftrightarrow\frac{3}{2}-\frac{5}{6}:x=\frac{2}{15}\)
\(\Leftrightarrow\frac{5}{6}:x=\frac{3}{2}-\frac{2}{15}\)
\(\Leftrightarrow\frac{5}{6}:x=\frac{41}{30}\)
\(\Leftrightarrow x=\frac{5}{6}:\frac{41}{30}\)
\(\Leftrightarrow x=\frac{25}{41}\)
b) \(x-\frac{6}{7}.\frac{14}{8}=\frac{1}{2}-\frac{2}{5}\)
\(\Leftrightarrow x-\frac{3}{2}=\frac{1}{10}\)
\(\Leftrightarrow x=\frac{1}{10}+\frac{3}{2}\)
\(\Leftrightarrow x=\frac{8}{5}\)
c) \(x:\frac{6}{5}+\frac{2}{3}=\frac{7}{3}\)
\(\Leftrightarrow x:\frac{6}{5}=\frac{7}{3}-\frac{2}{3}\)
\(\Leftrightarrow x:\frac{6}{5}=\frac{5}{3}\)
\(\Leftrightarrow x=\frac{5}{3}.\frac{6}{5}\)
\(\Leftrightarrow x=2\)

Tìm \(x\):
a; \(x\) + 35,2 = [25,6 + 3,14] x 3
\(x+\) 35,2 = 28,74 x 3
\(x\) + 35,2 = 86,22
\(x\) = 86,22 - 35,2
\(x\) = 51,02
b; \(\frac{17}{5}\) : \(x\) = \(\frac{34}{5}\) : \(\frac43\)
\(\frac{17}{5}\) : \(x\) = \(\frac{34}{5}\) x \(\frac34\)
\(\frac{17}{5}\) : \(x\) = \(\) \(\frac{51}{10}\)
\(x\) = \(\frac{17}{5}\) : \(\frac{51}{10}\)
\(x\) = \(\frac{17}{5}\) x \(\frac{10}{51}\)
\(x\) = \(\frac23\)
c; [\(x\) - \(\frac12\)] x \(\frac53\) = \(\frac74\) - \(\frac12\)
[\(x\) - \(\frac12\)] x \(\frac53\) = \(\frac74-\frac24\)
[\(x-\frac12\)] x \(\frac53\) = \(\frac54\)
\(x-\frac12\) = \(\frac54\) : \(\frac53\)
\(x-\frac12\) = \(\frac54\) x \(\frac35\)
\(x\) - \(\frac12\) = \(\frac34\)
\(x=\frac34+\frac12\)
\(x=\frac34+\frac24\)
\(x=\) \(\frac54\)
d; [72 - 4 x \(x\)] : 9 = 4
72 - 4 x \(x\) = 4 x 9
72 - 4 x \(x\) = 36
4 x \(x\) = 72 - 36
4 x \(x\) = 36
\(x\) = 36 : 4
\(x\) = 9

Câu 1:
a. $3\frac{2}{3}+2\frac{1}{2}=(3+2)+(\frac{2}{3}+\frac{1}{2})=5+\frac{7}{6}=6+\frac{1}{6}=6\frac{1}{6}$
b. \(2\frac{1}{2}\times 3\frac{2}{5}=\frac{5}{2}\times \frac{17}{5}=\frac{17}{2}\)
c.
\(3\frac{1}{3}: 4\frac{1}{4}=\frac{10}{3}: \frac{17}{4}=\frac{40}{51}\)
d.
\(3\frac{1}{2}+4\frac{5}{7}-5\frac{5}{14}=(3+4-5)+(\frac{1}{2}+\frac{5}{7}-\frac{5}{14})=2+\frac{6}{7}=2\frac{6}{7}\)
Câu 2:
a. $x\times \frac{2}{7}=\frac{6}{11}$
$x=\frac{6}{11}: \frac{2}{7}=\frac{21}{11}$
b. $x: \frac{3}{2}=\frac{1}{4}$
$x=\frac{1}{4}\times \frac{3}{2}=\frac{3}{8}$

a. 6 và 5/3 + 7 và 13/8 +3 và 1/3- 4 và 5/8
=23/3+69/8+4/3-37/8
=391/24+4/3+37/8=141/8-37/8=103/8
b.=(27/5+69/11)-(17/5-52/11)
=642/55+73/55=13

\(\frac{7}{4}-x.\frac{3}{4}=\frac{5}{19}\)
\(\Rightarrow1+\frac{3}{4}-x.\frac{3}{4}=\frac{5}{9}\)
\(\Rightarrow\frac{3}{4}.\left(1-x\right)=\frac{5}{9}-1=-\frac{4}{9}\)
\(\Rightarrow1-x=-\frac{4}{9}:\frac{3}{4}=-\frac{16}{27}\)
\(\Rightarrow x=1-\left(-\frac{16}{27}\right)=1+\frac{16}{27}=1\frac{16}{27}\)

6 2/7 + 7 3/5 + 8 6/9 + 9 1/4 + 2/5 + 5/7 + 1/3 x 3/4 + 1967
= 44/7 + 38/5 + 78/9 + 37/4 + 2/5 + 5/7 + 1/3 + 1967
= ( 44/7 + 5/7 ) + ( 38/5 + 2/5 ) + ( 26/3 + 1/3 ) + ( 37/4 + 3/4 ) +1967
= 7 + 8 + 9 + 10 + 1967
= 15 + 9 + 10 + 1967
= 24 + 10 + 1967
= 34 + 1967
= 2001

\(\frac29\) : \(\frac29\) x \(\frac12\)
= \(\frac29\) x \(\frac92\) x \(\frac12\)
= 1 x \(\frac12\)
= \(\frac12\)
\(\frac27\) : \(\frac23\) - \(\frac17\)
= \(\frac27\times\frac32\) - \(\frac17\)
= \(\frac37\) - \(\frac17\)
= \(\frac27\)
\(\frac23\) x \(\frac34\) x \(\frac45\) : \(\frac15\)
= \(\frac12\) x \(\frac45\) : \(\frac15\)
= \(\frac25\) : \(\frac15\)
= \(\frac25\) x \(\frac51\)
= \(\frac21\)
= 2
a) \(x\times\frac{5}{7}=\frac{1}{4}+\frac{1}{5}\)
\(x\times\frac{5}{7}=\frac{9}{20}\)
\(x=\frac{9}{20}\div\frac{5}{7}\)
\(x=\frac{63}{100}\)
a(2) : \(2\frac{3}{3}\div x=\frac{2}{5}-\frac{1}{3}\)
\(\frac{9}{3}\div x=\frac{1}{15}\)
\(x=\frac{9}{3}\div\frac{1}{15}\)
\(x=45\)