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a) \(\left(x.7+8\right):5=10\)
\(x.7+8=10.5\)
\(x.7+8=50\)
\(x.7=50-8\)
\(x.7=42\)
\(x=42:7\)
\(x=6\left(tm\right)\)
Vậy ......................
b) \(\left(x+5\right).19:13=57\)
\(\left(x+5\right).19=57.13\)
\(\left(x+5\right).19=741\)
\(x+5=741:19\)
\(x+5=39\)
\(x=39-5\)
\(x=34\left(tm\right)\)
Vậy ..................
c) \(4\left(36-4x\right)=64\)
\(36-4x=64:4\)
\(36-4x=18\)
\(4x=36-18\)
\(4x=18\)
\(x=\dfrac{18}{4}\)
Vậy ....................
d) \(7,6:1,9.x=3,2\)
\(4x=32\)
\(x=32:4\)
\(x=8\left(tm\right)\)
Vậy ................
\(60+x-34=43\Rightarrow x=43+34-60=17\)
\(23x-6.23+69x=230\)
\(\Rightarrow23x+69x=230+6.23\)
\(\Rightarrow92x=368\Rightarrow x=368:92\Rightarrow x=4\)
\(\left(15.24-x\right):0,25=100:0,25\)
\(\Rightarrow\left(360-x\right)=100:0,25.0,25\)
\(\Rightarrow360-x=100\Rightarrow x=360-100=260\)
\(\left(7x+8\right):5=10\Rightarrow\left(7x+8\right)=10.5\)
\(\Rightarrow7x+8=50\Rightarrow7x=50-8\Rightarrow7x=42\Rightarrow x=42:7=6\)
\(280:\left(7+3x\right)=4\Rightarrow\left(7+3x\right)=280:4\)
\(\Rightarrow7+3x=70\Rightarrow3x=70-7\Rightarrow3x=63\Rightarrow x=63:3=21\)
\(\left(x+5\right)x19:13=57\)
\(\Rightarrow\left(x+5\right)x19=57.13\)
\(\Rightarrow\left(x+5\right)=741:19\Rightarrow x+5=39\Rightarrow x=39-5=34\)
\(4\left(36-4x\right)=64\)
\(\Rightarrow\left(36-4x\right)=64:4\)
\(\Rightarrow36-4x=16\)
\(\Rightarrow4x=36-16\Rightarrow4x=20\Rightarrow x=20:4=5\)
\(\left(7,6:1,9\right)x=3,2\)
\(\Rightarrow4x=3,2\Rightarrow x=3,2:4=0,8\)
\(\left(x:2+50\right):5=12\)
\(\Rightarrow x:2+50=12.5\)
\(\Rightarrow x:2=60-50\Rightarrow x:2=10\Rightarrow x=10.2=20\)
A = ( -4/5 + 4/3 ) + (-5/4 + 14/5) - 7/3
= 8/15 + 31/20 - 7/3
= 25/12 - 7/3
= -1/4
B = 8/3 x 2/5 x 3/8 x 10x 19/92
= 16/15 x 15/4 x 19/92
= 4x19/92
= 19/23
C = - \(\dfrac{5}{7}\) x \(\dfrac{2}{11}\) + \(\dfrac{-5}{7}\) x \(\dfrac{9}{14}\) + \(\dfrac{1}{57}\)
= - \(\dfrac{10}{77}\) - \(\dfrac{45}{98}\) + \(\dfrac{1}{57}\)
= - \(\dfrac{635}{1078}\) + \(\dfrac{1}{57}\)
= - \(\dfrac{36195}{61446}\) + \(\dfrac{1078}{61446}\)
= - \(\dfrac{35117}{61446}\)
các bn lm đến đâu cx dc miễn là lm hộ mk cái ạ, ai đang lm vào nhắn tin vs mk để mk bít nha
a; \(-\dfrac{8}{3}+\dfrac{7}{5}-\dfrac{71}{15}< x< -\dfrac{13}{7}+\dfrac{19}{14}-\dfrac{7}{2}\)
-\(\dfrac{19}{15}\) - \(\dfrac{71}{15}\) < \(x\) < -\(\dfrac{1}{2}\) - \(\dfrac{7}{2}\)
-6 < \(x\) < -4
vì \(x\) \(\in\) Z nên \(x\) = -5
A. x = 2
B. \(\dfrac{3}{8}=\dfrac{6}{x}\)\(\Leftrightarrow x=\dfrac{6.8}{3}=16\)
C. x = 3
D. \(x=\dfrac{4.6}{8}=3\)
E. \(x=\dfrac{7}{3}\)
G.\(\dfrac{14}{13}=\dfrac{28}{10-x}\)
<=>\(14\left(10-x\right)=364\)
<=> 10 - x = 26
<=> x = -16
H. \(3\left(x+2\right)=4\left(x-5\right)\)
<=> 3x + 6 = 4x - 20
<=> -x = -26
<=> x = 26
K. \(\dfrac{x}{2}=\dfrac{8}{x}\)
<=> \(x^2=16\)
<=> \(\left[{}\begin{matrix}x=4\\x=-4\end{matrix}\right.\)
M. \(\left(x-2\right)^2=100\)
<=> \(\left[{}\begin{matrix}x-2=10\\x-2=-10\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=12\\x=-8\end{matrix}\right.\)
a=2
b=16
c=3
d=3
mik chỉ biết thế này thôi(ko chắc đúng=3)
a) (x.7 + 8) : 5 = 10
x.7 + 8 = 10.5
x.7 + 8 = 50
x.7 = 50 - 8
x.7 = 42
x = 42 : 7
x = 6
b) (x + 5).19 : 13 = 57
(x + 5).19 = 57 . 13
(x + 5).19 = 741
x + 5 = 741 : 19
x + 5 = 39
x = 39 - 5
x = 34
c) 4.(36 - 4.x) = 64
36 - 4x = 64 : 4
36 - 4x = 16
4x = 36 - 16
4x = 20
x = 20 : 4
x = 5
d) 7,6 : 19 . x = 3,2
0,4 . x = 3,2
x = 3,2 : 0,4
x = 8
e) (x : 2 + 50) : 5 = 12
x : 2 + 50 = 12 . 5
x : 2 + 50 = 60
x : 2 = 60 - 50
x : 2 = 10
x = 10 . 2
x = 20
g) 280 : (17 + 3.x) = 4
17 + 3x = 280 : 4
17 + 3x = 70
3x = 70 - 17
3x = 53
x = 53/3
h) 6.(28 - 8.x) = 72
28 - 8x = 72 : 6
28 - 8x = 12
8x = 28 - 12
8x = 16
x = 16 : 8
x = 2
i) (x - 15) : 3 : 12 = 6
(x - 15) : 3 = 6 . 12
(x - 15) : 3 = 72
x - 15 = 72 . 3
x - 15 = 216
x = 216 + 15
x = 231