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a: (3x^2-4)(x+3y)
=3x^2*x+3x^2*3y-4x-4*3y
=3x^3+9x^2y-4x-12y
b: (c+3)(x^2+3x)
=c*x^2+c*3x+3x^2+9x
=cx^2+3cx+3x^2+9x
c: (xy-1)(xy+5)
=xy*xy+5xy-xy-5
=x^2y^2+4xy-5
d: (3x+5y)(2x-7y)
=3x*2x-3x*7y+5y*2x-5y*7y
=6x^2-21xy+10xy-35y^2
=6x^2-11xy-35y^2
e: -(x-1)(-x^2+2y)
=(x-1)(x^2-2y)
=x^3-2xy-x^2+2y
f: (-x^2+2y)(x^2+2y)
=(2y)^2-x^4
=4y^2-x^4
a: =-1/5x^5y^2
b: =-9/7xy^3
c: =7/12xy^2z
d: =2x^4
e: =3/4x^5y
f: =11x^2y^5+x^6
a: =>A-B=3x^2y-4xy^2+x^2y-2xy^2=4x^2y-6xy^2
b: =>B-A=-7xy^2+8x^2y-5xy^2+6x^2y=-12xy^2+14x^2y
=>A-B=12xy^2-14x^2y
c: =>B-A=8x^2y^3-4x^3y-3x^2y^3+5x^3y^2=5x^2y^3+x^3y^2
=>A-B=-5x^2y^3-x^3y^2
d: =>A-B=2x^2y^3-7x^3y+6x^2y^3+3x^3y^2=8x^2y^3-7x^3y+3x^3y^2
a)\(^{ }\left(-2\right)^5:\left(-2\right)^3=\left(-2\right)^{5-3}=\left(-2\right)^2=4\)
b)\(\left(-y\right)^7:\left(-y\right)^3=\left(-y\right)^{7-3}=\left(-y\right)^4\)
c)\(x^{12}:\left(-x^{10}\right)=-\left(x^{12}\right):\left(x^{10}\right)=-\left(x^{12-10}\right)=-\left(x^2\right)\)
d)\(\left(2x^6\right):\left(2x\right)^3=2\left(x^6\right):8\left(x^3\right)=\frac{2}{8}x^{6-3}=\frac{1}{4}x^3\)
e)\(\left(-3x\right)^5;\left(-3x\right)^3=\left(-3x\right)^{5-3}=\left(-3x\right)^2\)
f)\(\left(xy^2\right)^4:\left(xy^2\right)^2=\left(xy^2\right)^{4-2}=\left(xy^2\right)^2\)
Bài làm
a) \(\left(-2\right)^5:\left(-2\right)^3\)
\(=\left(-2\right)^{5-3}\)
\(=\left(-2\right)^2\)
\(=4\)
b) \(\left(-y\right)^7:\left(-y\right)^3=\left(-y\right)^{7-3}=\left(-y\right)^4=y^4\)
c) \(x^{12}:\left(-x\right)^{10}=x^{12}:x^{10}=x^{12-10}=x^2\)
d) \(\left(2x\right)^6:\left(2x\right)^3=\left(2x\right)^{6-3}=\left(2x\right)^3=8x^3\)
e) \(\left(-3x\right)^5:\left(-3x\right)^2=\left(-3x\right)^{5-2}=\left(-3x\right)^3=-27x^3\)
f) \(\left(xy^2\right)^4:\left(xy^2\right)^2=\left(xy^2\right)^{4-2}=\left(xy^2\right)^2=x^2y^4\)
# Học tốt #
a) (-2)5 : (-2)3 = (-2)2
b) (-y)7 : (-y)3 = (-y)4
c) x12 : (-x10) = (-x)12
d) 2x6 : 2x3 = 2x3
e) (-3x)5 : (-3x)2 = (-3x)3
f) (xy2)4 : (xy2)2 = (xy2)2
a) \(=x^2-2x+x-2=x^2-x-2\)
b) \(=2x^2-8x-3x+12=2x^2-11x+12\)
c) \(=\left(x^2+2x-3\right)\left(x-2\right)=x^3-2x^2+2x^2-4x-3x+6=x^3-7x+6\)
d) \(=x^2+\dfrac{1}{2}x-5x-\dfrac{5}{2}=x^2-\dfrac{9}{2}x-\dfrac{5}{2}\)
e) \(=3x^2+\dfrac{3}{2}x+x+\dfrac{1}{2}=3x^2+\dfrac{5}{2}x+\dfrac{1}{2}\)
f) \(=5x^3-\dfrac{2}{3}x^4y-10x+\dfrac{4}{3}x^2y+30-4xy\)
a) Xem lại đề
b) x³ - 4x²y + 4xy² - 9x
= x(x² - 4xy + 4y² - 9)
= x[(x² - 4xy + 4y² - 3²]
= x[(x - 2y)² - 3²]
= x(x - 2y - 3)(x - 2y + 3)
c) x³ - y³ + x - y
= (x³ - y³) + (x - y)
= (x - y)(x² + xy + y²) + (x - y)
= (x - y)(x² + xy + y² + 1)
d) 4x² - 4xy + 2x - y + y²
= (4x² - 4xy + y²) + (2x - y)
= (2x - y)² + (2x - y)
= (2x - y)(2x - y + 1)
e) 9x² - 3x + 2y - 4y²
= (9x² - 4y²) - (3x - 2y)
= (3x - 2y)(3x + 2y) - (3x - 2y)
= (3x - 2y)(3x + 2y - 1)
f) 3x² - 6xy + 3y² - 5x + 5y
= (3x² - 6xy + 3y²) - (5x - 5y)
= 3(x² - 2xy + y²) - 5(x - y)
= 3(x - y)² - 5(x - y)
= (x - y)[(3(x - y) - 5]
= (x - y)(3x - 3y - 5)
\(a,=x^2-10x+25\\ b,=4x^2+12x+9\\ c,=4x^2-12x+9\\ d,=9x^2+12x+4\\ e,=x^3y^3-8\\ d,=x^2y^2-25\)