\(\frac{5}{6}\)<...">
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a,-3/5.2/7+-3/7.3/5+-3/7

=-3/7.2/5+(-3/7).3/5+(-3/7) 

=-3/7(2/5+3/5+1)

=-3/7.2

=-6/7

5 tháng 4 2019

a) A = \(\frac{101}{19}.\) \(\frac{61}{218}-\frac{101}{218}.\frac{42}{19}+\frac{117}{218}\)

        \(\frac{101}{218}.\frac{61}{19}-\frac{101}{218}.\frac{42}{19}+\frac{117}{218}\)

        =\(\frac{101}{218}.\left(\frac{61}{19}-\frac{42}{19}\right)+\frac{117}{218}\)

        =\(\frac{101}{218}.\frac{19}{19}+\frac{117}{218}\)

        =\(\frac{101}{218}.1+\frac{117}{218}\)

        =\(\frac{101}{218}+\frac{117}{218}\)

        =\(\frac{218}{218}\)\(=1\)

b) B = \(\left(\frac{5}{2011^2}+\frac{7}{2012^2}-\frac{9}{2013^2}\right).\left(\frac{4}{5}-\frac{3}{4}-\frac{1}{20}\right)\)

        =     \(\left(\frac{5}{2011^2}+\frac{7}{2012^2}-\frac{9}{2013^2}\right)\)\(.\left(\frac{1}{20}-\frac{1}{20}\right)\)

        \(\left(\frac{5}{2011^2}+\frac{7}{2012^2}-\frac{9}{2013^2}\right).0\)

        = \(0\)

30 tháng 1 2020

a) \(\frac{2}{5}+\left(\frac{3}{4}-\frac{7}{10}\right)\)

\(=\frac{2}{5}+\frac{1}{20}\)

\(=\frac{9}{20}\)

b) \(\frac{-1}{8}-\left(\frac{2}{3}-\frac{11}{12}\right)\)

\(=-\frac{1}{8}-\left(-\frac{1}{4}\right)\)

\(=\frac{1}{8}\)

c) \(\frac{7}{5}-\left(\frac{1}{6}+\frac{9}{10}\right)\)

\(=\frac{7}{5}-\frac{16}{15}\)

\(=\frac{1}{3}\)

d) \(\frac{2}{3}+\left(-\frac{1}{4}\right)+\frac{7}{12}-\left(-\frac{1}{4}\right)-\frac{5}{6}\)

\(=\left(\frac{2}{3}+\frac{7}{12}-\frac{5}{6}\right)+\left(-\frac{1}{4}+\frac{1}{4}\right)\)

\(=\left(\frac{5}{4}-\frac{5}{6}\right)+0\)

\(=\frac{5}{12}\)

e) \(2-\left\{\frac{1}{2}-\left[2-\left(\frac{1}{2}+2\right)-\frac{1}{2}\right]+2\right\}\)

\(=2-\left[\frac{1}{2}-\left(2-\frac{5}{2}-\frac{1}{2}\right)+2\right]\)

\(=2-\left[\frac{1}{2}-\left(-1\right)+2\right]\)

\(=2-\frac{7}{2}\)

\(=-\frac{3}{2}\)