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Từ 0,2 đến 4,7 có số số hạng là: \(\left(4,7-0,2\right):0,5+1=10\left(số\right)\)
⇒ Tổng 10 số đó là: \(\dfrac{\left(4,7+0,2\right)\cdot10}{2}=24,5\)
\(\left(x+0,2\right)+\left(x+0,7\right)+...+\left(x+4,7\right)=65,5\\ \Leftrightarrow10x+24,5=65,5\\ \Leftrightarrow10x=41\\ \Leftrightarrow x=4,1\)
Vậy x = 4,1
a) TH1: \(x< 2,5\) , ta có:
\(2,5-x=1,3\)
\(x=2,5-1,3=1,2\)
TH2: \(x\ge2,5\), ta có:
\(x-2,5=1,3\)
\(x=1,3+2,5=3,8\)
Vậy \(\orbr{\begin{cases}x=1,2\\x=3,8\end{cases}}\)
b) \(1,6-\left|x-0,2\right|=0\)
\(\Rightarrow\left|x-0,2\right|=1,6\)
TH1: \(x< 0,2\) ta có:
\(0,2-x=1,6\Rightarrow x=0,2-1,6=-1,4\)
TH2: \(x\ge0,2\) ta có:
\(x-0,2=1,6\Rightarrow x=1,6+0,2=1,8\)
Vậy \(\orbr{\begin{cases}x=-1,4\\x=1,8\end{cases}}\)
\(0,2:x=\dfrac{31}{1}-\dfrac{1}{4}\)
\(0,2:x=\dfrac{123}{4}\)
\(x=\dfrac{123}{4}\) x \(0,2\)
\(x=6,15\)
a) Ta có: \(x:3\dfrac{1}{15}=1\dfrac{1}{2}\)
\(\Leftrightarrow x:\dfrac{46}{15}=\dfrac{3}{2}\)
nên \(x=\dfrac{3}{2}\cdot\dfrac{46}{15}=\dfrac{23}{5}\)
b) Ta có: \(\left(1\dfrac{1}{5}-0.2\right)\cdot x=1\)
\(\Leftrightarrow\left(1+\dfrac{1}{5}-\dfrac{1}{5}\right)\cdot x=1\)
hay x=1
a, \(x:3\dfrac{1}{15}=1\dfrac{1}{12}\Leftrightarrow x:\dfrac{46}{15}=\dfrac{13}{12}\Leftrightarrow x=\dfrac{299}{90}\)
b, \(\left(1\dfrac{1}{5}-0,2\right)x=1\Leftrightarrow\left(\dfrac{6}{5}-\dfrac{1}{5}\right)x=1\Leftrightarrow x=1\)
1: =>x=3/5-1/5=2/5
b: =>x/3=5/8+1/8=3/4
=>x=9/4
3: =>10/3x=3+1/4+6+3/4=10
=>x=10:10/3=3
\(a,\frac{23}{15}-\frac{2}{3}x=0,2\)
\(\frac{2}{3}x=\frac{4}{3}\)
\(x=2\)
\(b,\frac{x}{3}=\frac{2}{3}+\left(\frac{-1}{7}\right)\)
\(\Rightarrow\frac{x}{3}=\frac{11}{21}\)
\(\Rightarrow x.21=3.11\)
\(\Rightarrow21x=33\)
\(\Rightarrow x=\frac{11}{7}\)
a. \(\frac{23}{15}-\frac{2}{3}x=0,2\)
\(\frac{23}{15}-\frac{2}{3}x=\frac{1}{5}\)
\(\frac{2}{3}x=\frac{23}{15}-\frac{1}{5}\)
\(\frac{2}{3}x=\frac{4}{3}\)
\(x=\frac{4}{3}:\frac{2}{3}\)
\(x=2\)
Vậy \(x=2\)
b. \(\frac{x}{3}=\frac{2}{3}+\frac{-1}{7}\)
\(\frac{x}{3}=\frac{11}{21}\)
\(\frac{7x}{21}=\frac{11}{21}\)
\(\Rightarrow7x=11\)
\(x=11:7\)
\(x=\frac{11}{7}\)
Vậy\(x=\frac{11}{7}\)
-0.01
(-8,3)\(x\) + (-11,7).\(x\) = 0,2
\(x\).( -8,3 - 11,7) = 0,2
\(x\).(-20) = 0,2
\(x\) = 0,2: (-20)
\(x\) = -0,01