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b) \(\dfrac{3}{4}+\dfrac{1}{4}:x=\dfrac{2}{5}\)
\(\Rightarrow\dfrac{1}{4}:x=\dfrac{2}{5}-\dfrac{2}{4}\)
\(\Rightarrow\dfrac{1}{4}:x=-\dfrac{1}{10}\)
\(\Rightarrow x=\dfrac{1}{4}:\left(-\dfrac{1}{10}\right)\)
\(\Rightarrow x=-\dfrac{3}{2}\)
\(a)18^{20}.45^5.5^{25}.8^{10}\)
\(=\left(2.3^2\right)^{20}.\left(3^2.5\right)^5.5^{25}.\left(2^3\right)^{10}\)
\(=2^{20}.3^{40}.3^{10}.5^5.5^{25}.2^{30}\)
\(=2^{50}.3^{50}.5^{30}\)
\(=6^{50}.5^{30}\)
\(=\left(6^5\right)^{10}.\left(5^3\right)^{10}\)
\(=7776^{10}.125^{10}\)
\(=972000^{10}\)
\(b)\left(x^2.y\right)^5.\left(x^2.y^2\right)^7.\left(xy\right)^6.x^3\)
\(=x^{10}.y^5.x^{14}.y^{14}.x^6.y^6.x^3\)
\(=x^{33}.y^{25}\)
\(=x^{25}.y^{25}.x^8\left(?\right)\)
\(c)2^7.3^8.4^9.9^8\)
\(=2^7.3^8.\left(2^2\right)^9.\left(3^2\right)^8\)
\(=2^7.3^8.2^{18}.3^{16}\)
\(=2^{25}.3^{24}\)\(\left(?\right)\)
a: 2x(x-1/7)=0
=>x(x-1/7)=0
=>x=0 hoặc x=1/7
b: \(\dfrac{3}{4}+\dfrac{1}{4}:x=\dfrac{2}{5}\)
\(\Leftrightarrow\dfrac{1}{4}:x=\dfrac{2}{5}-\dfrac{3}{4}=\dfrac{8}{20}-\dfrac{15}{20}=\dfrac{-7}{20}\)
nên \(x=\dfrac{-1}{4}:\dfrac{7}{20}=\dfrac{-20}{4\cdot7}=\dfrac{-5}{7}\)
c: \(\Leftrightarrow\dfrac{41}{9}:\dfrac{41}{18}-7< x< \left(3.2:3.2+\dfrac{45}{10}\cdot\dfrac{31}{45}\right):\left(-21.5\right)\)
\(\Leftrightarrow2-7< x< \dfrac{\left(1+3.1\right)}{-21.5}\)
\(\Leftrightarrow-5< x< \dfrac{-41}{215}\)
mà x là số nguyên
nên \(x\in\left\{-4;-3;-2;-1\right\}\)
Bài 1:
a) Đề ko rõ, coi lại
b) \(75^{20}=45^{10}.5^{30}\)
\(\Leftrightarrow\left(75^2\right)^{10}=45^{10}.\left(5^3\right)^{10}\)
\(\Leftrightarrow5625^{10}=45^{10}.125^{10}\)
\(\Leftrightarrow5625^{10}=\left(45.125\right)^{10}\)
\(\Leftrightarrow5625^{10}=5625^{10}\)
\(\Rightarrow75^{20}=45^{10}.5^{30}\left(đpcm\right)\)
Bài 2:
a) \(\frac{x}{-4}=\frac{-3}{5}\)
\(\Rightarrow x.5=-4.\left(-3\right)\)
\(\Rightarrow x.5=12\)
\(\Rightarrow x=\frac{12}{5}=2,4\)
b) c) d) Làm tương tự câu a. Bn tự lm cho nhớ
e) \(30.5x=4.12\)
\(\Rightarrow150x=48\)
\(\Rightarrow x=\frac{48}{150}=0,32\)
f) g) Làm tương tự câu e. Bn tự lm cho nhớ
a) 106 - 57
= 26 . 56 - 57
= 56 . (26 - 5)
= 56 . (64 - 5)
= 56 . 59 chia hết cho 59
=> đpcm
b) 817 - 279 - 913
= (34)7 - (33)9 - (32)13
= 328 - 327 - 326
= 326 .(32 - 3 - 1)
= 326 . (9 - 3 - 1)
= 324 . 32 . 5
= 324 . 9 . 5
= 324 . 45 chia hết cho 45
=> đpcm
c) 87 - 218
= (23)7 - 218
= 221 - 218
= 218 . (23 - 1)
= 218 (8 - 1)
= 217 . 2 . 7
= 217 . 14 chia hết cho 14
=> đpcm
d) 109 + 108 + 107
= 107 . (102 + 10 + 1)
= 57 . 27 . (100 + 10 + 1)
= 57 . 26 . 2 . 111
= 57 . 26 . 222 chia hết cho 222
=> đpcm
Ta có:\(8^7-2^{18}=\left(2^3\right)^7-2^{18}\)\(=2^{21}-2^{18}=2^{17}\cdot2^4-2^{17}\cdot2=2^{17}\cdot\left(2^4-1\right)=2^{17}\cdot14\)\(⋮14\)
\(\Rightarrow8^7-2^{18}⋮14\)
(ĐPCM)
1, Ta có: \(8^7-2^{18}=2^{21}-2^{18}=2^{17}\left(2^4-2\right)=2^{17}.14⋮14\)
2, Đặt: \(\dfrac{a}{2}=\dfrac{b}{5}=\dfrac{c}{7}=k\)
\(\Rightarrow a=2k;b=5k;c=7k\)
Nên: \(A=\dfrac{a-b+c}{a+2b-c}=\dfrac{2k-5k+7k}{2k+10k-7k}=\dfrac{3k}{5k}=\dfrac{3}{5}\)
Vậy...
a) \(2x+5-\left(x-7\right)=18\)
\(2x+5-x+7=18\)
\(x+12=18\)
\(x=18-12\)
\(x=6\)
b) \(2\left(x+1\right)+4^2=2^4\)
\(2\left(x+1\right)+16=16\)
\(2\left(x+1\right)=16-16\)
\(2\left(x+1\right)=0\)
\(\Rightarrow\left(x+1\right)=0\)
\(x=0-1\)
\(x=-1\)
c) \(\frac{x-3}{x+5}=\frac{5}{7}\)
\(\Rightarrow\left(x-3\right)7=\left(x+5\right)5\)
\(7x-21=5x+25\)
\(7x-5x=25+21\)
\(2x=46\)
\(x=\frac{46}{2}\)
\(x=23\)
Bài 1 :
a, \(-1\dfrac{2}{3}\)= \(\dfrac{-5}{3}\)
Dựa vào tính chất của Tỉ lệ thức :
Ta có : \(\dfrac{x}{y}=\dfrac{-5}{3}\rightarrow\dfrac{x}{-5}=\dfrac{y}{3}\)
Dựa vào tính chất của dãy tỉ số = nhau
Ta có : \(\dfrac{x}{-5}=\dfrac{y}{3}=\dfrac{x+y}{\left(-5\right)+3}=\dfrac{18}{-2}=-9\)
\(\rightarrow\dfrac{x}{-5}=-9\rightarrow x=\left(-5\right).\left(-9\right)\Rightarrow x=45\\ \rightarrow\dfrac{y}{3}=-9\rightarrow y=3.\left(-9\right)\Rightarrow y=-27\)b,
Ta có :
( x + 4 ) . 7 = ( y + 7 ) . 4
\(\rightarrow\) 7x + 28 = 4y + 28
\(\rightarrow\) 7x = 4y
Vì 7x = 4y
\(\Rightarrow\) x = 22 / ( 4 + 7 ) . 7 = 14
\(\Rightarrow\) y = 22 - 14 = 8
Đợi mk lm câu 2 nha
\(\Leftrightarrow\dfrac{41}{9}:\dfrac{41}{18}-7< x< \left(\dfrac{16}{5}:\dfrac{16}{5}+\dfrac{9}{2}\cdot\dfrac{76}{45}\right):\dfrac{-43}{2}\)
\(\Leftrightarrow-5< x< \left(1+\dfrac{38}{5}\right)\cdot\dfrac{-2}{43}=\dfrac{43}{5}\cdot\dfrac{-2}{43}=\dfrac{-2}{5}\)
mà x là số nguyên
nên \(x\in\left\{-4;-3;-2;-1\right\}\)