Question

[Nguyễn Thị Trà]

a)

b)

3)

4)

Answer 1

[Gia Hân Ngô]

1) \(2x - \frac{3}{4}= \left ( + \frac{2}{3} \right )\)

\(2x = \frac{2}{3}+ \frac{3}{4}\)

\(2x = \frac{17}{12}\)

\(x = \frac{17}{12}: 2\)

x = \(\frac{17}{24}\)

Vậy ...........

2) x⁵ : x³ = \(\frac{1}{16}\)

\(x^{2}= \frac{1}{16}\)

=> \(x= \frac{1}{14}\) hoặc \(x= - \frac{1}{14}\)

Vậy ........

3) \(\left | x + \frac{1}{3} \right | - 2 = - 1\)

\(\left | x + \frac{1}{3} \right | = 1\)

* \(x + \frac{1}{3} = 1\)

\(x = 1 - \frac{1}{3}\)

\(x = \frac{2}{3}\)

* \(x + \frac{1}{3} = - 1\)

\(x =- 1 - \frac{1}{3}\)

\(x = - \frac{4}{3}\)

Vậy ...........hoặc..............

4) \(\frac{2}{9}x\left (x - 3\tfrac{7}{8} \right )= 0\)

\(\frac{2}{9}x\left (x - \frac{31}{8} \right )= 0\)

<=> \(\begin{bmatrix} \frac{2}{9}x = 0 & & \\ x - \frac{31}{8}= 0 & & \end{bmatrix}\)

\(\Leftrightarrow \begin{bmatrix} x = 0 & & \\ x = \frac{31}{8} & & \end{bmatrix}\)

pn bỏ dấu ngoặc bên phải nhé

Vậy ...............hoặc............

Chúc pn học tốt

Answer 2

[Gia Hân Ngô]

câu 2 KL 2 giá trị nhé