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3.2x—3=45
3.2x=45+3
3.2x=48
2x=48:3
2x=16
x=16:2
x=8
4x .3+12=120
4x.3=120–12
4x.3=108
4x=108:3
4x=36
x=36:4
x=9
\(3.2x-3=45\)
\(3.2x=45+3\)
\(3.2x=48\)
\(2x=\frac{48}{3}\)
\(2x=16\)
\(x=8\)
Vậy \(x=8\)
\(1500:\left[\left(36x+40\right):x\right]=30\)
\(\left(36x+40\right):x=1500:30\)
\(36x+40=50x\)
\(50x-36x=40\)
\(14x=40\)
\(x=\frac{40}{14}\)
\(x=\frac{20}{7}\)
Vậy \(x=\frac{20}{7}\)
a, \(4x^3+12=120\)
\(\Leftrightarrow4x^3=120-12\)
\(\Leftrightarrow4x^3=108\)
\(\Leftrightarrow x^3=108:4\)
\(\Leftrightarrow x^3=27\)
\(\Leftrightarrow x=3\)
b, \(3.2^x-3=45\)
\(\Leftrightarrow3.2^x=45+3\)
\(\Leftrightarrow3.2^x=48\)
\(\Leftrightarrow2^x=48:3\)
\(\Leftrightarrow2^x=16\)
\(\Leftrightarrow x=4\)
Câu c, bạn làm tương tự nha !
a, 4x^3 + 12 = 120 b,3.2^x-3=45 c, 1500:[(30x +40):x]=30
4x^3=120-12 3.2^x =45+3 (30x +40):x =1500:30
4x^3=108 3.2^x =48 (30x +40):x = 50
x^3=108:4 2^x =48:3 30x:x+40:x = 50
x^3=27 2^x =16 30+40:x=50
=> x^3= 3^3 2^x =2^4 40:x=50-30
=> x = 3 => x =4 40:x= 20
=>x=40:20
=>x=20 ( câu c tui có làm sai thì đừng trách nhé )
\(4x^3+12=120\)
\(\Rightarrow4x^3=108\)
\(\Rightarrow x^3=108:4=27=3^3\)
\(\Rightarrow x=3\)
\(3.2^x-3=45\)
\(\Rightarrow3.2^x=48\)
\(\Rightarrow2^x=16=2^4\Rightarrow x=4\)
\(1500:\left[\left(30x+40\right):x\right]=30\)
\(\Rightarrow\left(30x+40\right):x=50\)
\(\Rightarrow30x:x+40:x=50\)
\(\Rightarrow30+40:x=50\)
\(\Rightarrow40:x=20\Rightarrow x=2\)
[(6x - 72) : 2 - 84]. 28 = 5628
=> (6x - 72) : 2 - 84 = 5628 : 28 = 201
=> (6x - 72) : 2 = 201 + 84 = 285
=> 6x - 72 = 285 . 2 = 570
=> 6x = 570 + 72 = 642
=> x = 642 : 6
=> x = 107
a) x = 2^8 : 2^4 + 3^2 . 3^3
x = 2^4 + 3^5
x = 16 + 243
x = 259
b) 6x - 39 = 5628 : 28
6x - 39 = 201
6x = 240
x = 40
[(6x-39):3] . 28 = 5628
(6x - 39) : 3 = 201
6x - 39 = 603
6x = 642
x = 107
a) 7.(x - 3) + 4 = 18
7. (x - 3) = 14
x - 3 = 2
x = 5
b) 2x - 13 = 201
2x = 214
x = 107
a: Ta có: \(\left[\left(6x-39\right):3\right]\cdot28=5628\)
\(\Leftrightarrow\left(6x-39\right):3=201\)
\(\Leftrightarrow6x-39=603\)
\(\Leftrightarrow6x=642\)
hay x=107
b: Ta có: \(4x^3+12=120\)
\(\Leftrightarrow4x^3=108\)
\(\Leftrightarrow x^3=27\)
hay x=3
c: Ta có: \(1500:\left[\left(30x+40\right):x\right]=30\)
\(\Leftrightarrow\left(30x+40\right):x=50\)
\(\Leftrightarrow30x+40=50x\)
hay x=-2