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a) \(-\left(315.4+275\right)+4.315-\left(10-275\right)\)
\(=-315.4-275+4.315-10+275\)
\(=315.\left(-4+4\right)+\left(-275+275\right)-10\)
\(=315.0+0-10=0-10=-10\)
b) \(\left(-2,5.0,375.0,4\right)-\left[0,125.3,25.\left(-8\right)\right]\)
\(=\left[\left(-2,5.0,4\right).0,375\right]-\left[\left(-8.0,125\right).3,25\right]\)
\(=\left[-1.0,375\right]-\left[-1.3,25\right]\)
\(=\left[-1.\left(0,375-3,25\right)\right]=-1.\left(-2,875\right)=2,875\)
Cậu có thể tham khảo bài làm trên đây ạ, chúc cậu học tốt ^^
1) \(7.4^x=7.4^3\Leftrightarrow4^x=4^3;x=3\)
2) \(\frac{3}{2.5^x}=\frac{3}{2.5^{12}}\Leftrightarrow5^x=5^{12};x=12\)
\(2^x=2.2^8=2^9;x=9\)
4) \(5.3^x=7.3^5-2.3^5\Leftrightarrow5.3^x=3^5.\left(7-2\right)\)
\(\Leftrightarrow3^5.x=3^5.5;x=5\)
\(a,=\dfrac{3}{2}-\dfrac{5}{6}:\dfrac{1}{4}+\sqrt{\dfrac{1}{4}-\dfrac{1}{2}}=\dfrac{3}{2}-\dfrac{10}{3}+\sqrt{\dfrac{1}{2}}=-\dfrac{11}{6}+\dfrac{\sqrt{2}}{2}=\dfrac{-33+3\sqrt{2}}{6}\)
\(b,=-\dfrac{4}{3}\cdot\dfrac{9}{2}+\dfrac{13}{12}\cdot\left(-\dfrac{8}{13}\right)=6-\dfrac{2}{3}=\dfrac{16}{3}\\ c,=\dfrac{1}{4}-\left(-\dfrac{1}{6}:4-8\cdot\dfrac{1}{16}\right)=\dfrac{1}{4}-\left(-\dfrac{1}{24}-\dfrac{1}{2}\right)\\ =\dfrac{1}{4}-\dfrac{13}{24}=-\dfrac{7}{24}\\ d,=\dfrac{3^{11}\cdot5^{11}\cdot5^7\cdot3^4}{5^{18}\cdot3^{18}}=\dfrac{1}{3^3}=\dfrac{1}{27}\)
a) 5x + 1 - 2.5x = 75
<=> 5x.5 - 2.5x = 75
<=> 5x.3 = 75
<=> 5x = 25
<=> 5x = 52
<=> x = 2
Vậy x = 2
b) 9x + 1 - 5.32x = 324
<=> (32)x + 1 - 5.32x = 324
<=> 32x + 2 - 5.32x = 324
<=> 32x.32 - 5.32x = 324
<=> 32x . 4 = 324
<=> 32x = 81
<=> 32x = 34
<=> 2x = 4
<=> x = 2
Vậy x = 2
a: \(\Leftrightarrow2x=\dfrac{19}{5}:\dfrac{3}{32}=\dfrac{608}{15}\)
hay x=304/15
b: \(\Leftrightarrow0.25x=20\)
hay x=80
c: \(\Leftrightarrow x=\dfrac{1}{100}:\dfrac{5}{2}=\dfrac{2}{500}=\dfrac{1}{250}\)
d: \(\Leftrightarrow0.1x=\dfrac{2}{3}:\dfrac{5}{3}=\dfrac{2}{5}\)
hay \(x=\dfrac{2}{5}:\dfrac{1}{10}=\dfrac{20}{5}=4\)
{ x2 - [ 62 - ( 82 - 9.7)3 - 7.5]3 - 5.3 }3 = 1
{ x2 + [ 36 - (64 - 63)3 - 35]3 - 15}3 = 1
[ x2 - ( 36 - 13 - 35 ) - 15 ]3 = 1
[ x2 - ( 36 - 1 - 35 ) - 15]3 = 1
[ x2 - ( 35 - 35 ) - 15]3 = 1
[ x2 - 0 - 15]3 = 1
( x2 - 15 )3 = 1
<=> ( x2 - 15)3 = 13
=> x2 - 15 = 1
<=> x2 = 16
=> x = 4
A (-6.37*0.4)*2.5=-6.37*(0.4*2.5)=-6.37*1=-6.37
B (-0.125*-5.3)*8=(-0.125*8)*(-5.3)=-1*(-5.3)=5.3
C -2.5*(-4)*(-7.9)=10*(-7.9)=-79