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7 tháng 4 2023

a, \(\dfrac{4}{5}\) + \(\dfrac{9}{15}\) : \(\dfrac{1}{15}\)

\(\dfrac{4}{5}\) + \(\dfrac{9}{15}\) \(\times\) 15

\(\dfrac{4}{5}\)+ 9

\(\dfrac{4}{5}+\dfrac{45}{5}\)

\(\dfrac{49}{5}\) 

b, - \(\dfrac{5}{15}\) \(\times\) ( 1\(\dfrac{1}{2}\) - (-\(\dfrac{2}{7}\)) - (- \(\dfrac{14}{8}\)) - 1\(\dfrac{1}{3}\)

= - \(\dfrac{1}{3}\) \(\times\) ( \(\dfrac{3}{2}\)+\(\dfrac{2}{7}\)\(\dfrac{7}{4}\)) - \(\dfrac{4}{3}\)

= - \(\dfrac{1}{3}\) \(\times\) ( \(\dfrac{42}{28}\)\(\dfrac{8}{28}\)\(\dfrac{49}{28}\)) - \(\dfrac{4}{3}\)

= - \(\dfrac{1}{3}\) \(\times\) \(\dfrac{99}{28}\) - \(\dfrac{4}{3}\)

= - \(\dfrac{99}{84}\) - \(\dfrac{112}{84}\)

= - \(\dfrac{211}{84}\)

23 tháng 6 2018

a) \(\frac{1}{5}+\frac{3}{17}-\frac{4}{3}+\left(\frac{4}{5}-\frac{3}{17}+\frac{1}{3}\right)-\frac{7}{15}+\left(\frac{-14}{30}\right)\)

\(=\left(\frac{1}{5}+\frac{4}{5}\right)+\left(\frac{3}{17}-\frac{3}{17}\right)-\left(\frac{4}{3}-\frac{1}{3}\right)-\left(\frac{7}{15}+\frac{14}{30}\right)\)

\(=1+0-1-\left(\frac{7}{15}+\frac{7}{15}\right)\)

= -14/15

b) \(\left(\frac{5}{8}-\frac{4}{13}+\frac{3}{2}\right)-\left(\frac{5}{8}+\frac{9}{13}\right)-\left(\frac{-3}{2}\right)+\frac{7}{-15}\)

\(=\frac{5}{8}-\frac{4}{13}+\frac{3}{2}-\frac{5}{8}-\frac{9}{13}+\frac{3}{2}-\frac{7}{15}\)

\(=\left(\frac{5}{8}-\frac{5}{8}\right)-\left(\frac{4}{13}+\frac{9}{13}\right)+\left(\frac{3}{2}+\frac{3}{2}\right)-\frac{7}{15}\)

\(=0-1+3-\frac{7}{15}\)

\(=2-\frac{7}{15}\)

\(=\frac{23}{15}\)

23 tháng 6 2018

a) 1/5 +3/17-4/3+4/5-3/17+1/3-7/15-14/30

= (1/5+4/5)-4/3+1/3-(7/15+14/30)

=1-1-28/30=-28/30

a: \(=\dfrac{5}{7}\left(\dfrac{5}{11}+\dfrac{2}{11}-\dfrac{14}{11}\right)=\dfrac{5}{7}\cdot\dfrac{-7}{11}=-\dfrac{5}{11}\)

b: \(=\dfrac{12}{7}\left(19+\dfrac{5}{8}-15-\dfrac{1}{4}\right)=\dfrac{12}{7}\cdot\left(4+\dfrac{3}{8}\right)\)

\(=\dfrac{12}{7}\cdot\dfrac{35}{8}=\dfrac{3}{2}\cdot5=\dfrac{15}{2}\)

c: \(=\dfrac{2}{15}-\dfrac{2}{15}\cdot5+\dfrac{3}{15}=\dfrac{2}{15}\cdot\left(-4\right)+\dfrac{3}{15}=\dfrac{-8+3}{15}=\dfrac{-5}{15}=-\dfrac{1}{3}\)

d: \(=\dfrac{4}{9}\left(19+\dfrac{1}{3}-39-\dfrac{1}{3}\right)=\dfrac{4}{9}\cdot\left(-20\right)=-\dfrac{80}{9}\)

BÀI 1

a,  \(5\times\frac{-7}{10}=\frac{-35}{10}=\frac{-7}{2}\)

b,  \(\frac{4}{5}\times\frac{-7}{10}=\frac{-28}{50}=\frac{-14}{25}\)

c,  \(\frac{4}{9}+\frac{4}{3}\times\frac{16}{4}=\frac{4}{9}+\frac{16}{3}=\frac{52}{9}\)

d,  \(\frac{11}{22}-\frac{3}{9}\times\frac{14}{21}=\frac{11}{22}-\frac{2}{9}=\frac{55}{198}=\frac{5}{18}\)  

BÀI 2

\(A=\frac{6}{13}\times\frac{5}{7}+\frac{6}{13}\times\frac{2}{7}+\frac{17}{13}\)

\(A=\frac{30}{91}+\frac{12}{91}+\frac{17}{13}\)

\(A=\frac{30}{91}+\frac{12}{91}+\frac{119}{91}\)

\(A=\frac{161}{91}=\frac{23}{13}\)

\(B=\frac{11}{15}\times\frac{4}{11}+\frac{11}{15}\times\frac{5}{11}+\frac{11}{15}\times\frac{2}{11}\)

\(B=\frac{4}{15}+\frac{1}{3}+\frac{2}{15}\)

\(B=\frac{11}{15}\)

\(C=\left(\frac{19}{64}-\frac{33}{22}+\frac{24}{51}\right)\times\left(\frac{1}{5}-\frac{1}{15}-\frac{2}{15}\right)\)

\(C=\frac{-797}{1088}\times0\)

\(C=0\)

\(D=\frac{8}{13}\times\frac{7}{12}+\frac{8}{13}\times\frac{5}{12}-\frac{1}{12}\)

\(D=\frac{14}{39}+\frac{10}{39}-\frac{1}{12}\)

\(D=\frac{83}{156}\)

3 tháng 10 2021

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