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`(-4,2) . 5,1 + 5,1 . (-5,8)`
`= 5,1 . [-4,2 + (-5,8)]`
`= 5,1 . (-10)`
`= -51`
a) 14,7 + (-8,4) + (-4,7) = (14,7 - 4,7) + (-8,4)
= 10 - 8,4 = 1,6
b) (-4,2).5,1 + 5,1.(-5,8) = 5,1. (- 4,2 - 5,8)
= 5,1. (-10) = -51
c) (-0,4: 0,04 + 10) . (1,2.20 + 12.8)
= (-10 + 10). (1,2.20 + 12.8)
= 0. (1,2.20 + 12.8) = 0.
a) \(x:0,1+x:0,2=5,1\)
\(\Leftrightarrow x:\left(0,1+0,2\right)=5,1\)
\(\Leftrightarrow x:0,3=5,1\)
\(\Leftrightarrow x=5,1.0,3\)
\(\Leftrightarrow x=1,53\)
b) \(5:x-2,6:x=2,5\)
\(\Leftrightarrow\left(5-2,6\right):x=2,5\)
\(\Leftrightarrow2,4:x=2,5\)
\(\Leftrightarrow x=2,4:2,5\)
\(\Leftrightarrow x=0,96\)
a) 95*3,6-2,6*95
=95*(3,6-2,6)
=95*1
=95
b)107/49+51/107
=107/(49+51)
=107/100
=1,07
c)87,45-36,09-34,91
=51,36-34,91
=16,45
d) 15,56-(3,56+4,8)
=15,56-3,56-4,8
=12-4,8
=7,2
a) \(\dfrac{17}{8}:\left(\dfrac{27}{8}+\dfrac{-11}{2}\right)\)
\(=\dfrac{17}{8}.\dfrac{-8}{17}\)
\(=-1\)
b) \(7,63.21,15+7,63.\left(-121,15\right)\)
\(=7,63.\left(21,15-121,15\right)\)
\(=7,63.\left(-100\right)\)
\(=-763\)
c) \(\left(-\dfrac{5}{24}-0,75\right):\left(-2\dfrac{7}{8}\right)\)
\(=\left(-\dfrac{5}{24}-\dfrac{3}{4}\right):\left(-\dfrac{7}{4}\right)\)
\(=\dfrac{-23}{24}.\dfrac{-4}{7}\)
\(=\dfrac{23}{42}\).
\(a.\dfrac{17}{8}:\left(\dfrac{27}{8}+\dfrac{-11}{2}\right)\text{=}\dfrac{17}{8}:\dfrac{-17}{8}\text{=}-1\)
\(b.7,63.21,15+7,63.-121,15\text{=}7,63.\left(21,15-121,15\right)\text{=}7,63.-100\text{=}-763\)
\(c.\left(\dfrac{-5}{24}-0,75\right):\dfrac{-23}{8}\text{=}\dfrac{-23}{24}.\dfrac{-8}{23}\text{=}\dfrac{1}{3}\)